在。net下使用c#和WPF(而不是Windows窗体或控制台),创建一个只能作为单个实例运行的应用程序的正确方法是什么?

我知道它与某种叫做互斥的神秘事物有关,我很少能找到有人费心停下来解释其中一个是什么。

代码还需要通知已经运行的实例,用户试图启动第二个实例,如果存在命令行参数,还可能传递任何命令行参数。


当前回答

看起来有一个很好的方法来处理这个问题:

WPF单实例应用程序

这提供了一个类,您可以添加它来管理所有互斥量和消息传递的cruff,从而将实现简化到非常简单的程度。

其他回答

[我在下面提供了控制台和wpf应用程序的示例代码。]

在创建命名的Mutex实例后,只需检查createdNew变量的值(示例如下!)。

布尔值createdNew将返回false:

如果命名为“YourApplicationNameHere”的互斥锁实例已经存在 在系统某处创建

布尔值createdNew将返回true:

如果这是第一个名为“YourApplicationNameHere”的互斥锁 系统。

控制台应用程序-示例:

static Mutex m = null;

static void Main(string[] args)
{
    const string mutexName = "YourApplicationNameHere";
    bool createdNew = false;

    try
    {
        // Initializes a new instance of the Mutex class with a Boolean value that indicates 
        // whether the calling thread should have initial ownership of the mutex, a string that is the name of the mutex, 
        // and a Boolean value that, when the method returns, indicates whether the calling thread was granted initial ownership of the mutex.

        using (m = new Mutex(true, mutexName, out createdNew))
        {
            if (!createdNew)
            {
                Console.WriteLine("instance is alreday running... shutting down !!!");
                Console.Read();
                return; // Exit the application
            }

            // Run your windows forms app here
            Console.WriteLine("Single instance app is running!");
            Console.ReadLine();
        }


    }
    catch (Exception ex)
    {

        Console.WriteLine(ex.Message);
        Console.ReadLine();
    }
}

WPF-Example:

public partial class App : Application
{
static Mutex m = null;

protected override void OnStartup(StartupEventArgs e)
{

    const string mutexName = "YourApplicationNameHere";
    bool createdNew = false;

    try
    {
        // Initializes a new instance of the Mutex class with a Boolean value that indicates 
        // whether the calling thread should have initial ownership of the mutex, a string that is the name of the mutex, 
        // and a Boolean value that, when the method returns, indicates whether the calling thread was granted initial ownership of the mutex.

        m = new Mutex(true, mutexName, out createdNew);

        if (!createdNew)
        {
            Current.Shutdown(); // Exit the application
        }

    }
    catch (Exception)
    {
        throw;
    }

    base.OnStartup(e);
}


protected override void OnExit(ExitEventArgs e)
{
    if (m != null)
    {
        m.Dispose();
    }
    base.OnExit(e);
}
}

我找到了一个更简单的解决方案,与戴尔·拉根的方法类似,但稍加修改。它基于标准的Microsoft WindowsFormsApplicationBase类,几乎可以做你需要的所有事情。

首先,你创建SingleInstanceController类,你可以在所有其他使用Windows窗体的单实例应用程序中使用它:

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Windows.Forms;
using Microsoft.VisualBasic.ApplicationServices;


namespace SingleInstanceController_NET
{
    public class SingleInstanceController
    : WindowsFormsApplicationBase
    {
        public delegate Form CreateMainForm();
        public delegate void StartNextInstanceDelegate(Form mainWindow);
        CreateMainForm formCreation;
        StartNextInstanceDelegate onStartNextInstance;
        public SingleInstanceController(CreateMainForm formCreation, StartNextInstanceDelegate onStartNextInstance)
        {
            // Set whether the application is single instance
            this.formCreation = formCreation;
            this.onStartNextInstance = onStartNextInstance;
            this.IsSingleInstance = true;

            this.StartupNextInstance += new StartupNextInstanceEventHandler(this_StartupNextInstance);                      
        }

        void this_StartupNextInstance(object sender, StartupNextInstanceEventArgs e)
        {
            if (onStartNextInstance != null)
            {
                onStartNextInstance(this.MainForm); // This code will be executed when the user tries to start the running program again,
                                                    // for example, by clicking on the exe file.
            }                                       // This code can determine how to re-activate the existing main window of the running application.
        }

        protected override void OnCreateMainForm()
        {
            // Instantiate your main application form
            this.MainForm = formCreation();
        }

        public void Run()
        {
            string[] commandLine = new string[0];
            base.Run(commandLine);
        }
    }
}

然后你可以在你的程序中使用它,如下所示:

using System;
using System.Collections.Generic;
using System.Linq;
using System.Windows.Forms;
using SingleInstanceController_NET;

namespace SingleInstance
{
    static class Program
    {
        /// <summary>
        /// The main entry point for the application.
        /// </summary>
        static Form CreateForm()
        {
            return new Form1(); // Form1 is used for the main window.
        }

        static void OnStartNextInstance(Form mainWindow) // When the user tries to restart the application again,
                                                         // the main window is activated again.
        {
            mainWindow.WindowState = FormWindowState.Maximized;
        }
        [STAThread]
        static void Main()
        {
            Application.EnableVisualStyles();
            Application.SetCompatibleTextRenderingDefault(false);            
            SingleInstanceController controller = new SingleInstanceController(CreateForm, OnStartNextInstance);
            controller.Run();         
        }
    }
}

程序和SingleInstanceController_NET解决方案都应该引用Microsoft。VisualBasic。如果您只是想在用户试图重新启动正在运行的程序时重新激活正在运行的应用程序作为一个正常窗口,那么SingleInstanceController中的第二个参数可以为空。在给定的示例中,窗口是最大化的。

我在这里找不到一个简单的解决方案,所以我希望有人会喜欢这个:

更新2018-09-20

把这段代码放在Program.cs中:

using System.Diagnostics;

static void Main()
{
    Process thisProcess = Process.GetCurrentProcess();
    Process[] allProcesses = Process.GetProcessesByName(thisProcess.ProcessName);
    if (allProcesses.Length > 1)
    {
        // Don't put a MessageBox in here because the user could spam this MessageBox.
        return;
    }

    // Optional code. If you don't want that someone runs your ".exe" with a different name:

    string exeName = AppDomain.CurrentDomain.FriendlyName;
    // in debug mode, don't forget that you don't use your normal .exe name.
    // Debug uses the .vshost.exe.
    if (exeName != "the name of your executable.exe") 
    {
        // You can add a MessageBox here if you want.
        // To point out to users that the name got changed and maybe what the name should be or something like that^^ 
        MessageBox.Show("The executable name should be \"the name of your executable.exe\"", 
            "Wrong executable name", MessageBoxButtons.OK, MessageBoxIcon.Error);
        return;
    }

    // Following code is default code:
    Application.EnableVisualStyles();
    Application.SetCompatibleTextRenderingDefault(false);
    Application.Run(new MainForm());
}

请看下面的代码。它是防止一个WPF应用程序有多个实例的一个很好的简单解决方案。

private void Application_Startup(object sender, StartupEventArgs e)
{
    Process thisProc = Process.GetCurrentProcess();
    if (Process.GetProcessesByName(thisProc.ProcessName).Length > 1)
    {
        MessageBox.Show("Application running");
        Application.Current.Shutdown();
        return;
    }

    var wLogin = new LoginWindow();

    if (wLogin.ShowDialog() == true)
    {
        var wMain = new Main();
        wMain.WindowState = WindowState.Maximized;
        wMain.Show();
    }
    else
    {
        Application.Current.Shutdown();
    }
}

这是我的两分钱

 static class Program
    {
        [STAThread]
        static void Main()
        {
            bool createdNew;
            using (new Mutex(true, "MyApp", out createdNew))
            {
                if (createdNew) {
                    Application.EnableVisualStyles();
                    Application.SetCompatibleTextRenderingDefault(false);
                    var mainClass = new SynGesturesLogic();
                    Application.ApplicationExit += mainClass.tray_exit;
                    Application.Run();
                }
                else
                {
                    var current = Process.GetCurrentProcess();
                    foreach (var process in Process.GetProcessesByName(current.ProcessName).Where(process => process.Id != current.Id))
                    {
                        NativeMethods.SetForegroundWindow(process.MainWindowHandle);
                        break;
                    }
                }
            }
        }
    }