在。net下使用c#和WPF(而不是Windows窗体或控制台),创建一个只能作为单个实例运行的应用程序的正确方法是什么?
我知道它与某种叫做互斥的神秘事物有关,我很少能找到有人费心停下来解释其中一个是什么。
代码还需要通知已经运行的实例,用户试图启动第二个实例,如果存在命令行参数,还可能传递任何命令行参数。
在。net下使用c#和WPF(而不是Windows窗体或控制台),创建一个只能作为单个实例运行的应用程序的正确方法是什么?
我知道它与某种叫做互斥的神秘事物有关,我很少能找到有人费心停下来解释其中一个是什么。
代码还需要通知已经运行的实例,用户试图启动第二个实例,如果存在命令行参数,还可能传递任何命令行参数。
当前回答
基于命名互斥的方法不是跨平台的,因为命名互斥在Mono中不是全局的。基于进程枚举的方法没有任何同步,可能会导致不正确的行为(例如,同时启动的多个进程可能都根据时间自行终止)。在控制台应用程序中不需要基于windows系统的方法。这个解决方案建立在Divin的答案之上,解决了所有这些问题:
using System;
using System.IO;
namespace TestCs
{
public class Program
{
// The app id must be unique. Generate a new guid for your application.
public static string AppId = "01234567-89ab-cdef-0123-456789abcdef";
// The stream is stored globally to ensure that it won't be disposed before the application terminates.
public static FileStream UniqueInstanceStream;
public static int Main(string[] args)
{
EnsureUniqueInstance();
// Your code here.
return 0;
}
private static void EnsureUniqueInstance()
{
// Note: If you want the check to be per-user, use Environment.SpecialFolder.ApplicationData instead.
string lockDir = Path.Combine(
Environment.GetFolderPath(Environment.SpecialFolder.CommonApplicationData),
"UniqueInstanceApps");
string lockPath = Path.Combine(lockDir, $"{AppId}.unique");
Directory.CreateDirectory(lockDir);
try
{
// Create the file with exclusive write access. If this fails, then another process is executing.
UniqueInstanceStream = File.Open(lockPath, FileMode.Create, FileAccess.Write, FileShare.None);
// Although only the line above should be sufficient, when debugging with a vshost on Visual Studio
// (that acts as a proxy), the IO exception isn't passed to the application before a Write is executed.
UniqueInstanceStream.Write(new byte[] { 0 }, 0, 1);
UniqueInstanceStream.Flush();
}
catch
{
throw new Exception("Another instance of the application is already running.");
}
}
}
}
其他回答
这么简单的问题有这么多答案。稍微改变一下这里是我对这个问题的解决方案。
Creating a Mutex can be troublesome because the JIT-er only sees you using it for a small portion of your code and wants to mark it as ready for garbage collection. It pretty much wants to out-smart you thinking you are not going to be using that Mutex for that long. In reality you want to hang onto this Mutex for as long as your application is running. The best way to tell the garbage collector to leave you Mutex alone is to tell it to keep it alive though out the different generations of garage collection. Example:
var m = new Mutex(...);
...
GC.KeepAlive(m);
我从这个网页上获得了灵感:http://www.ai.uga.edu/~mc/SingleInstance.html
请检查这里提出的解决方案,它使用信号量来确定现有实例是否已经在运行,适用于WPF应用程序,并且可以通过使用TcpListener和TcpClient将参数从第二个实例传递给第一个已经运行的实例:
它不仅适用于。net Framework,也适用于。net Core。
更新2017-01-25。在尝试了一些东西之后,我决定使用VisualBasic.dll,它更容易,工作效果更好(至少对我来说)。我让我之前的答案只是作为参考…
只是作为参考,这是我如何不传递参数(我找不到任何理由这样做…我指的是带有参数的单个应用程序,这些参数可以从一个实例传递到另一个实例)。 如果需要文件关联,那么应用程序应该(根据用户的标准期望)为每个文档实例化。如果你必须传递args到现有的应用程序,我想我会使用vb dll。
不传递参数(只是单实例应用程序),我更喜欢不注册一个新的窗口消息,不覆盖Matt Davis解决方案中定义的消息循环。虽然添加一个VisualBasic dll不是一个大问题,但我不喜欢添加一个新的引用只是做单个实例应用程序。此外,我更喜欢用Main实例化一个新类,而不是调用Shutdown from app. startup重写以确保尽快退出。
希望大家都喜欢……或者会启发一点:-)
项目启动类应该设置为“SingleInstanceApp”。
public class SingleInstanceApp
{
[STAThread]
public static void Main(string[] args)
{
Mutex _mutexSingleInstance = new Mutex(true, "MonitorMeSingleInstance");
if (_mutexSingleInstance.WaitOne(TimeSpan.Zero, true))
{
try
{
var app = new App();
app.InitializeComponent();
app.Run();
}
finally
{
_mutexSingleInstance.ReleaseMutex();
_mutexSingleInstance.Close();
}
}
else
{
MessageBox.Show("One instance is already running.");
var processes = Process.GetProcessesByName(Assembly.GetEntryAssembly().GetName().Name);
{
if (processes.Length > 1)
{
foreach (var process in processes)
{
if (process.Id != Process.GetCurrentProcess().Id)
{
WindowHelper.SetForegroundWindow(process.MainWindowHandle);
}
}
}
}
}
}
}
WindowHelper:
using System;
using System.Runtime.InteropServices;
using System.Windows;
using System.Windows.Interop;
using System.Windows.Threading;
namespace HQ.Util.Unmanaged
{
public class WindowHelper
{
[DllImport("user32.dll")]
[return: MarshalAs(UnmanagedType.Bool)]
public static extern bool SetForegroundWindow(IntPtr hWnd);
这里有一个解决方案:
Protected Overrides Sub OnStartup(e As StartupEventArgs)
Const appName As String = "TestApp"
Dim createdNew As Boolean
_mutex = New Mutex(True, appName, createdNew)
If Not createdNew Then
'app is already running! Exiting the application
MessageBox.Show("Application is already running.")
Application.Current.Shutdown()
End If
MyBase.OnStartup(e)
End Sub
这是我的两分钱
static class Program
{
[STAThread]
static void Main()
{
bool createdNew;
using (new Mutex(true, "MyApp", out createdNew))
{
if (createdNew) {
Application.EnableVisualStyles();
Application.SetCompatibleTextRenderingDefault(false);
var mainClass = new SynGesturesLogic();
Application.ApplicationExit += mainClass.tray_exit;
Application.Run();
}
else
{
var current = Process.GetCurrentProcess();
foreach (var process in Process.GetProcessesByName(current.ProcessName).Where(process => process.Id != current.Id))
{
NativeMethods.SetForegroundWindow(process.MainWindowHandle);
break;
}
}
}
}
}