整数和浮点数都需要被接受，包括负数。

private void textBox1_KeyPress(object sender, KeyPressEventArgs e)
{
    // Text
    string text = ((Control) sender).Text;

    // Is Negative Number?
    if (e.KeyChar == '-' && text.Length == 0)
    {
        e.Handled = false;
        return;
    }

    // Is Float Number?
    if (e.KeyChar == '.' && text.Length > 0 && !text.Contains("."))
    {
        e.Handled = false;
        return;
    }

    // Is Digit?
    e.Handled = (!char.IsDigit(e.KeyChar) && !char.IsControl(e.KeyChar));
}

在我们的网页与文本框的定义，我们可以添加一个onkeypress事件只接受数字。它不会显示任何消息，但它将防止您输入错误。它为我工作，用户不能输入任何除了数字。

<asp:TextBox runat="server" ID="txtFrom"
     onkeypress="if(isNaN(String.fromCharCode(event.keyCode))) return false;">

两个选择:

Use a NumericUpDown instead. NumericUpDown does the filtering for you, which is nice. Of course it also gives your users the ability to hit the up and down arrows on the keyboard to increment and decrement the current value. Handle the appropriate keyboard events to prevent anything but numeric input. I've had success with this two event handlers on a standard TextBox: private void textBox1_KeyPress(object sender, KeyPressEventArgs e) { if (!char.IsControl(e.KeyChar) && !char.IsDigit(e.KeyChar) && (e.KeyChar != '.')) { e.Handled = true; } // only allow one decimal point if ((e.KeyChar == '.') && ((sender as TextBox).Text.IndexOf('.') > -1)) { e.Handled = true; } }

您可以删除'的支票。如果你的文本框不允许小数点，'(和后续检查不止一个'.')。你也可以添加一个检查'-'如果你的文本框应该允许负值。

如果您想限制用户的位数，请使用:textBox1。MaxLength = 2;//这将允许用户只输入2位数字

这是一个简单的独立的Winforms自定义控件，从标准的TextBox派生而来，只允许System。Int32输入(它可以很容易地适用于其他类型，如System。Int64,等等)。它支持复制/粘贴操作和负数:

public class Int32TextBox : TextBox
{
    protected override void OnKeyPress(KeyPressEventArgs e)
    {
        base.OnKeyPress(e);

        NumberFormatInfo fi = CultureInfo.CurrentCulture.NumberFormat;

        string c = e.KeyChar.ToString();
        if (char.IsDigit(c, 0))
            return;

        if ((SelectionStart == 0) && (c.Equals(fi.NegativeSign)))
            return;

        // copy/paste
        if ((((int)e.KeyChar == 22) || ((int)e.KeyChar == 3))
            && ((ModifierKeys & Keys.Control) == Keys.Control))
            return;

        if (e.KeyChar == '\b')
            return;

        e.Handled = true;
    }

    protected override void WndProc(ref System.Windows.Forms.Message m)
    {
        const int WM_PASTE = 0x0302;
        if (m.Msg == WM_PASTE)
        {
            string text = Clipboard.GetText();
            if (string.IsNullOrEmpty(text))
                return;

            if ((text.IndexOf('+') >= 0) && (SelectionStart != 0))
                return;

            int i;
            if (!int.TryParse(text, out i)) // change this for other integer types
                return;

            if ((i < 0) && (SelectionStart != 0))
                return;
        }
        base.WndProc(ref m);
    }

2017年更新:我的第一个答案有一些问题:

你可以输入一个比给定类型的整数更长的值(例如2147483648大于Int32.MaxValue); 更一般地说，对于输入的结果没有真正的验证; 它只处理int32，你必须写特定的TextBox衍生控件为每种类型(Int64等)

所以我提出了另一个更通用的版本，它仍然支持复制/粘贴，+和-号等。

public class ValidatingTextBox : TextBox
{
    private string _validText;
    private int _selectionStart;
    private int _selectionEnd;
    private bool _dontProcessMessages;

    public event EventHandler<TextValidatingEventArgs> TextValidating;

    protected virtual void OnTextValidating(object sender, TextValidatingEventArgs e) => TextValidating?.Invoke(sender, e);

    protected override void WndProc(ref Message m)
    {
        base.WndProc(ref m);
        if (_dontProcessMessages)
            return;

        const int WM_KEYDOWN = 0x100;
        const int WM_ENTERIDLE = 0x121;
        const int VK_DELETE = 0x2e;

        bool delete = m.Msg == WM_KEYDOWN && (int)m.WParam == VK_DELETE;
        if ((m.Msg == WM_KEYDOWN && !delete) || m.Msg == WM_ENTERIDLE)
        {
            DontProcessMessage(() =>
            {
                _validText = Text;
                _selectionStart = SelectionStart;
                _selectionEnd = SelectionLength;
            });
        }

        const int WM_CHAR = 0x102;
        const int WM_PASTE = 0x302;
        if (m.Msg == WM_CHAR || m.Msg == WM_PASTE || delete)
        {
            string newText = null;
            DontProcessMessage(() =>
            {
                newText = Text;
            });

            var e = new TextValidatingEventArgs(newText);
            OnTextValidating(this, e);
            if (e.Cancel)
            {
                DontProcessMessage(() =>
                {
                    Text = _validText;
                    SelectionStart = _selectionStart;
                    SelectionLength = _selectionEnd;
                });
            }
        }
    }

    private void DontProcessMessage(Action action)
    {
        _dontProcessMessages = true;
        try
        {
            action();
        }
        finally
        {
            _dontProcessMessages = false;
        }
    }
}

public class TextValidatingEventArgs : CancelEventArgs
{
    public TextValidatingEventArgs(string newText) => NewText = newText;
    public string NewText { get; }
}

对于Int32，你可以从它导出，像这样:

public class Int32TextBox : ValidatingTextBox
{
    protected override void OnTextValidating(object sender, TextValidatingEventArgs e)
    {
        e.Cancel = !int.TryParse(e.NewText, out int i);
    }
}

或w/o派生，使用新的textvalididating事件，像这样:

var vtb = new ValidatingTextBox();
...
vtb.TextValidating += (sender, e) => e.Cancel = !int.TryParse(e.NewText, out int i);

但它的优点是它适用于任何字符串和任何验证例程。

我已经为各种验证创建了一个可重用的文本框扩展类，并考虑共享它。

您所需要做的就是引发一个TextChange事件，然后调用Validate方法。它是这样的:

private void tbxAmount_TextChanged(object sender, EventArgs e)
{ 
    tbxAmount.Validate(TextValidator.ValidationType.Amount);
}

下面是扩展类:

public static class TextValidator
{
    public enum ValidationType
    {
        Amount,
        Integer
    }

    /// <summary>
    /// Validate a textbox on text change.
    /// </summary>
    /// <param name="tbx"></param>
    /// <param name="validationType"></param>
    public static void Validate(this TextBox tbx, ValidationType validationType)
    {
        PerformValidation(tbx, validationType);
        tbx.Select(tbx.Text.Length, 0);
    }


    private static void PerformValidation(this TextBox tbx, ValidationType validationType)
    {
        char[] enteredString = tbx.Text.ToCharArray();
        switch (validationType)
        {
            case ValidationType.Amount:
                tbx.Text = AmountValidation(enteredString);
                break;

            case ValidationType.Integer:
                tbx.Text = IntegerValidation(enteredString);
                break;

            default:
                break;
        }

        tbx.SelectionStart = tbx.Text.Length;
    }



    private static string AmountValidation(char[] enteredString)
    {
        string actualString = string.Empty;
        int count = 0;
        foreach (char c in enteredString.AsEnumerable())
        {
            if (count >= 1 && c == '.')
            { actualString.Replace(c, ' '); actualString.Trim(); }
            else
            {
                if (Char.IsDigit(c))
                {
                    actualString = actualString + c;
                }

                if (c == '.')
                {
                    actualString = actualString + c; count++;
                }

                else
                {
                    actualString.Replace(c, ' ');
                    actualString.Trim();
                }
            }
        }
        return actualString;
    }


    private static string IntegerValidation(char[] enteredString)
    {
        string actualString = string.Empty;
        foreach (char c in enteredString.AsEnumerable())
        {
            if (Char.IsDigit(c))
            {
                actualString = actualString + c;
            }
            else
            {
                actualString.Replace(c, ' ');
                actualString.Trim();
            }
        }
        return actualString;
    }
}

你可以在这里找到完整的代码

我也在寻找最好的方法来检查文本框中只有数字和键盘的问题是，它不支持通过右键单击或剪贴板复制粘贴，所以提出了这个代码，验证光标离开文本字段时，它也检查空字段。(newguy改编版)

private void txtFirstValue_MouseLeave(object sender, EventArgs e)
{
    int num;
    bool isNum = int.TryParse(txtFirstValue.Text.Trim(), out num);

    if (!isNum && txtFirstValue.Text != String.Empty)
    {
        MessageBox.Show("The First Value You Entered Is Not a Number, Please Try Again", "Invalid Value Detected", MessageBoxButtons.OK, MessageBoxIcon.Error);
        txtFirstValue.Clear();
    }
}