我有一个windows窗体应用程序与一个文本框控件,我想只接受整数值。在过去,我通过重载KeyPress事件并删除不符合规范的字符来进行这种验证。我已经看了MaskedTextBox控件,但我想一个更通用的解决方案,可以与也许正则表达式,或依赖于其他控件的值。
理想情况下,按下非数字字符要么不产生结果,要么立即向用户提供关于无效字符的反馈。
我有一个windows窗体应用程序与一个文本框控件,我想只接受整数值。在过去,我通过重载KeyPress事件并删除不符合规范的字符来进行这种验证。我已经看了MaskedTextBox控件,但我想一个更通用的解决方案,可以与也许正则表达式,或依赖于其他控件的值。
理想情况下,按下非数字字符要么不产生结果,要么立即向用户提供关于无效字符的反馈。
当前回答
这可能有用。它允许“真实”数值,包括正确的小数点和前面的加号或减号。从相关的KeyPress事件中调用它。
private bool IsOKForDecimalTextBox(char theCharacter, TextBox theTextBox)
{
// Only allow control characters, digits, plus and minus signs.
// Only allow ONE plus sign.
// Only allow ONE minus sign.
// Only allow the plus or minus sign as the FIRST character.
// Only allow ONE decimal point.
// Do NOT allow decimal point or digits BEFORE any plus or minus sign.
if (
!char.IsControl(theCharacter)
&& !char.IsDigit(theCharacter)
&& (theCharacter != '.')
&& (theCharacter != '-')
&& (theCharacter != '+')
)
{
// Then it is NOT a character we want allowed in the text box.
return false;
}
// Only allow one decimal point.
if (theCharacter == '.'
&& theTextBox.Text.IndexOf('.') > -1)
{
// Then there is already a decimal point in the text box.
return false;
}
// Only allow one minus sign.
if (theCharacter == '-'
&& theTextBox.Text.IndexOf('-') > -1)
{
// Then there is already a minus sign in the text box.
return false;
}
// Only allow one plus sign.
if (theCharacter == '+'
&& theTextBox.Text.IndexOf('+') > -1)
{
// Then there is already a plus sign in the text box.
return false;
}
// Only allow one plus sign OR minus sign, but not both.
if (
(
(theCharacter == '-')
|| (theCharacter == '+')
)
&&
(
(theTextBox.Text.IndexOf('-') > -1)
||
(theTextBox.Text.IndexOf('+') > -1)
)
)
{
// Then the user is trying to enter a plus or minus sign and
// there is ALREADY a plus or minus sign in the text box.
return false;
}
// Only allow a minus or plus sign at the first character position.
if (
(
(theCharacter == '-')
|| (theCharacter == '+')
)
&& theTextBox.SelectionStart != 0
)
{
// Then the user is trying to enter a minus or plus sign at some position
// OTHER than the first character position in the text box.
return false;
}
// Only allow digits and decimal point AFTER any existing plus or minus sign
if (
(
// Is digit or decimal point
char.IsDigit(theCharacter)
||
(theCharacter == '.')
)
&&
(
// A plus or minus sign EXISTS
(theTextBox.Text.IndexOf('-') > -1)
||
(theTextBox.Text.IndexOf('+') > -1)
)
&&
// Attempting to put the character at the beginning of the field.
theTextBox.SelectionStart == 0
)
{
// Then the user is trying to enter a digit or decimal point in front of a minus or plus sign.
return false;
}
// Otherwise the character is perfectly fine for a decimal value and the character
// may indeed be placed at the current insertion position.
return true;
}
其他回答
只需使用NumericUpDown控件,并设置那些丑陋的上下按钮可见性为假。
numericUpDown1.Controls[0].Visible = false;
NumericUpDown实际上是一个包含“旋转框”(上下按钮)的控件集合,一个文本框和一些代码来验证和wange-jangle。
标记:
YourNumericUpDown.Controls[0].visible = false
将隐藏按钮,同时保持底层代码活动。
虽然不是一个明显的解决方案,但它简单而有效。. controls[1]将隐藏文本框部分,如果你想这样做的话。
两个选择:
Use a NumericUpDown instead. NumericUpDown does the filtering for you, which is nice. Of course it also gives your users the ability to hit the up and down arrows on the keyboard to increment and decrement the current value. Handle the appropriate keyboard events to prevent anything but numeric input. I've had success with this two event handlers on a standard TextBox: private void textBox1_KeyPress(object sender, KeyPressEventArgs e) { if (!char.IsControl(e.KeyChar) && !char.IsDigit(e.KeyChar) && (e.KeyChar != '.')) { e.Handled = true; } // only allow one decimal point if ((e.KeyChar == '.') && ((sender as TextBox).Text.IndexOf('.') > -1)) { e.Handled = true; } }
您可以删除'的支票。如果你的文本框不允许小数点,'(和后续检查不止一个'.')。你也可以添加一个检查'-'如果你的文本框应该允许负值。
如果您想限制用户的位数,请使用:textBox1。MaxLength = 2;//这将允许用户只输入2位数字
你可以使用TextChanged/ Keypress事件,使用正则表达式过滤数字,并采取一些行动。
我已经为各种验证创建了一个可重用的文本框扩展类,并考虑共享它。
您所需要做的就是引发一个TextChange事件,然后调用Validate方法。它是这样的:
private void tbxAmount_TextChanged(object sender, EventArgs e)
{
tbxAmount.Validate(TextValidator.ValidationType.Amount);
}
下面是扩展类:
public static class TextValidator
{
public enum ValidationType
{
Amount,
Integer
}
/// <summary>
/// Validate a textbox on text change.
/// </summary>
/// <param name="tbx"></param>
/// <param name="validationType"></param>
public static void Validate(this TextBox tbx, ValidationType validationType)
{
PerformValidation(tbx, validationType);
tbx.Select(tbx.Text.Length, 0);
}
private static void PerformValidation(this TextBox tbx, ValidationType validationType)
{
char[] enteredString = tbx.Text.ToCharArray();
switch (validationType)
{
case ValidationType.Amount:
tbx.Text = AmountValidation(enteredString);
break;
case ValidationType.Integer:
tbx.Text = IntegerValidation(enteredString);
break;
default:
break;
}
tbx.SelectionStart = tbx.Text.Length;
}
private static string AmountValidation(char[] enteredString)
{
string actualString = string.Empty;
int count = 0;
foreach (char c in enteredString.AsEnumerable())
{
if (count >= 1 && c == '.')
{ actualString.Replace(c, ' '); actualString.Trim(); }
else
{
if (Char.IsDigit(c))
{
actualString = actualString + c;
}
if (c == '.')
{
actualString = actualString + c; count++;
}
else
{
actualString.Replace(c, ' ');
actualString.Trim();
}
}
}
return actualString;
}
private static string IntegerValidation(char[] enteredString)
{
string actualString = string.Empty;
foreach (char c in enteredString.AsEnumerable())
{
if (Char.IsDigit(c))
{
actualString = actualString + c;
}
else
{
actualString.Replace(c, ' ');
actualString.Trim();
}
}
return actualString;
}
}
你可以在这里找到完整的代码
这是用.NET 5/Core来实现的一种很好很短的方法
private void textBox1_KeyDown(object sender, KeyEventArgs e) {
if (e.KeyData != Keys.Back)
e.SuppressKeyPress = !int.TryParse(Convert.ToString((char) e.KeyData), out int _);
}
编辑:增加了退格键的支持