我有一个windows窗体应用程序与一个文本框控件，我想只接受整数值。在过去，我通过重载KeyPress事件并删除不符合规范的字符来进行这种验证。我已经看了MaskedTextBox控件，但我想一个更通用的解决方案，可以与也许正则表达式，或依赖于其他控件的值。
理想情况下，按下非数字字符要么不产生结果，要么立即向用户提供关于无效字符的反馈。
当前回答
这可能有用。它允许“真实”数值，包括正确的小数点和前面的加号或减号。从相关的KeyPress事件中调用它。
private bool IsOKForDecimalTextBox(char theCharacter, TextBox theTextBox)
{
// Only allow control characters, digits, plus and minus signs.
// Only allow ONE plus sign.
// Only allow ONE minus sign.
// Only allow the plus or minus sign as the FIRST character.
// Only allow ONE decimal point.
// Do NOT allow decimal point or digits BEFORE any plus or minus sign.
if (
!char.IsControl(theCharacter)
&& !char.IsDigit(theCharacter)
&& (theCharacter != '.')
&& (theCharacter != '-')
&& (theCharacter != '+')
)
{
// Then it is NOT a character we want allowed in the text box.
return false;
}
// Only allow one decimal point.
if (theCharacter == '.'
&& theTextBox.Text.IndexOf('.') > -1)
{
// Then there is already a decimal point in the text box.
return false;
}
// Only allow one minus sign.
if (theCharacter == '-'
&& theTextBox.Text.IndexOf('-') > -1)
{
// Then there is already a minus sign in the text box.
return false;
}
// Only allow one plus sign.
if (theCharacter == '+'
&& theTextBox.Text.IndexOf('+') > -1)
{
// Then there is already a plus sign in the text box.
return false;
}
// Only allow one plus sign OR minus sign, but not both.
if (
(
(theCharacter == '-')
|| (theCharacter == '+')
)
&&
(
(theTextBox.Text.IndexOf('-') > -1)
||
(theTextBox.Text.IndexOf('+') > -1)
)
)
{
// Then the user is trying to enter a plus or minus sign and
// there is ALREADY a plus or minus sign in the text box.
return false;
}
// Only allow a minus or plus sign at the first character position.
if (
(
(theCharacter == '-')
|| (theCharacter == '+')
)
&& theTextBox.SelectionStart != 0
)
{
// Then the user is trying to enter a minus or plus sign at some position
// OTHER than the first character position in the text box.
return false;
}
// Only allow digits and decimal point AFTER any existing plus or minus sign
if (
(
// Is digit or decimal point
char.IsDigit(theCharacter)
||
(theCharacter == '.')
)
&&
(
// A plus or minus sign EXISTS
(theTextBox.Text.IndexOf('-') > -1)
||
(theTextBox.Text.IndexOf('+') > -1)
)
&&
// Attempting to put the character at the beginning of the field.
theTextBox.SelectionStart == 0
)
{
// Then the user is trying to enter a digit or decimal point in front of a minus or plus sign.
return false;
}
// Otherwise the character is perfectly fine for a decimal value and the character
// may indeed be placed at the current insertion position.
return true;
}
其他回答
你可以在文本框的textchanged事件中这样做。
这是一个演示
private void textBox1_TextChanged(object sender, EventArgs e)
{
string actualdata = string.Empty;
char[] entereddata = textBox1.Text.ToCharArray();
foreach (char aChar in entereddata.AsEnumerable())
{
if (Char.IsDigit(aChar))
{
actualdata = actualdata + aChar;
// MessageBox.Show(aChar.ToString());
}
else
{
MessageBox.Show(aChar + " is not numeric");
actualdata.Replace(aChar, ' ');
actualdata.Trim();
}
}
textBox1.Text = actualdata;
}
你可以使用TextChanged/ Keypress事件，使用正则表达式过滤数字，并采取一些行动。
似乎目前对这个问题的许多答案都是手动解析输入文本。如果你正在寻找一个特定的内置数字类型(例如int或double)，为什么不只是将工作委托给该类型的TryParse方法?例如:
public class IntTextBox : TextBox
{
string PreviousText = "";
int BackingResult;
public IntTextBox()
{
TextChanged += IntTextBox_TextChanged;
}
public bool HasResult { get; private set; }
public int Result
{
get
{
return HasResult ? BackingResult : default(int);
}
}
void IntTextBox_TextChanged(object sender, EventArgs e)
{
HasResult = int.TryParse(Text, out BackingResult);
if (HasResult || string.IsNullOrEmpty(Text))
{
// Commit
PreviousText = Text;
}
else
{
// Revert
var changeOffset = Text.Length - PreviousText.Length;
var previousSelectionStart =
Math.Max(0, SelectionStart - changeOffset);
Text = PreviousText;
SelectionStart = previousSelectionStart;
}
}
}
如果你想要更通用但仍然兼容Visual Studio的设计器:
public class ParsableTextBox : TextBox
{
TryParser BackingTryParse;
string PreviousText = "";
object BackingResult;
public ParsableTextBox()
: this(null)
{
}
public ParsableTextBox(TryParser tryParse)
{
TryParse = tryParse;
TextChanged += ParsableTextBox_TextChanged;
}
public delegate bool TryParser(string text, out object result);
public TryParser TryParse
{
set
{
Enabled = !(ReadOnly = value == null);
BackingTryParse = value;
}
}
public bool HasResult { get; private set; }
public object Result
{
get
{
return GetResult<object>();
}
}
public T GetResult<T>()
{
return HasResult ? (T)BackingResult : default(T);
}
void ParsableTextBox_TextChanged(object sender, EventArgs e)
{
if (BackingTryParse != null)
{
HasResult = BackingTryParse(Text, out BackingResult);
}
if (HasResult || string.IsNullOrEmpty(Text))
{
// Commit
PreviousText = Text;
}
else
{
// Revert
var changeOffset = Text.Length - PreviousText.Length;
var previousSelectionStart =
Math.Max(0, SelectionStart - changeOffset);
Text = PreviousText;
SelectionStart = previousSelectionStart;
}
}
}
最后，如果你想要完全通用的东西，不关心Designer支持:
public class ParsableTextBox<T> : TextBox
{
TryParser BackingTryParse;
string PreviousText;
T BackingResult;
public ParsableTextBox()
: this(null)
{
}
public ParsableTextBox(TryParser tryParse)
{
TryParse = tryParse;
TextChanged += ParsableTextBox_TextChanged;
}
public delegate bool TryParser(string text, out T result);
public TryParser TryParse
{
set
{
Enabled = !(ReadOnly = value == null);
BackingTryParse = value;
}
}
public bool HasResult { get; private set; }
public T Result
{
get
{
return HasResult ? BackingResult : default(T);
}
}
void ParsableTextBox_TextChanged(object sender, EventArgs e)
{
if (BackingTryParse != null)
{
HasResult = BackingTryParse(Text, out BackingResult);
}
if (HasResult || string.IsNullOrEmpty(Text))
{
// Commit
PreviousText = Text;
}
else
{
// Revert
var changeOffset = Text.Length - PreviousText.Length;
var previousSelectionStart =
Math.Max(0, SelectionStart - changeOffset);
Text = PreviousText;
SelectionStart = previousSelectionStart;
}
}
}
我会在KeyDown事件中处理它。
void TextBox_KeyDown(object sender, KeyEventArgs e)
{
char c = Convert.ToChar(e.PlatformKeyCode);
if (!char.IsDigit(c))
{
e.Handled = true;
}
}
很抱歉吵醒死人，但我想有人可能会觉得这对将来的参考有用。
以下是我的处理方法。它处理浮点数，但可以很容易地修改为整数。
基本上你只能按0 - 9和。
前面只能有一个0。
所有其他字符将被忽略，光标位置保持不变。
private bool _myTextBoxChanging = false;
private void myTextBox_TextChanged(object sender, EventArgs e)
{
validateText(myTextBox);
}
private void validateText(TextBox box)
{
// stop multiple changes;
if (_myTextBoxChanging)
return;
_myTextBoxChanging = true;
string text = box.Text;
if (text == "")
return;
string validText = "";
bool hasPeriod = false;
int pos = box.SelectionStart;
for (int i = 0; i < text.Length; i++ )
{
bool badChar = false;
char s = text[i];
if (s == '.')
{
if (hasPeriod)
badChar = true;
else
hasPeriod = true;
}
else if (s < '0' || s > '9')
badChar = true;
if (!badChar)
validText += s;
else
{
if (i <= pos)
pos--;
}
}
// trim starting 00s
while (validText.Length >= 2 && validText[0] == '0')
{
if (validText[1] != '.')
{
validText = validText.Substring(1);
if (pos < 2)
pos--;
}
else
break;
}
if (pos > validText.Length)
pos = validText.Length;
box.Text = validText;
box.SelectionStart = pos;
_myTextBoxChanging = false;
}
下面是一个快速修改的int版本:
private void validateText(TextBox box)
{
// stop multiple changes;
if (_myTextBoxChanging)
return;
_myTextBoxChanging = true;
string text = box.Text;
if (text == "")
return;
string validText = "";
int pos = box.SelectionStart;
for (int i = 0; i < text.Length; i++ )
{
char s = text[i];
if (s < '0' || s > '9')
{
if (i <= pos)
pos--;
}
else
validText += s;
}
// trim starting 00s
while (validText.Length >= 2 && validText.StartsWith("00"))
{
validText = validText.Substring(1);
if (pos < 2)
pos--;
}
if (pos > validText.Length)
pos = validText.Length;
box.Text = validText;
box.SelectionStart = pos;
_myTextBoxChanging = false;
}
