enum Rank: Int {
    case Ace = 1
    case Two, Three, Four, Five, Six, Seven, Eight, Nine, Ten
    case Jack, Queen, King

    func simpleDescription() -> String {
        switch self {
        case .Ace: return "ace"
        case .Jack: return "jack"
        case .Queen: return "queen"
        case .King: return "king"
        default: return String(self.toRaw())
        }
    }
}

enum Suit: Int {
    case Spades = 1
    case Hearts, Diamonds, Clubs

    func simpleDescription() -> String {
        switch self {
        case .Spades: return "spades"
        case .Hearts: return "hearts"
        case .Diamonds: return "diamonds"
        case .Clubs: return "clubs"
        }
    }

    func color() -> String {
        switch self {
        case .Spades, .Clubs: return "black"
        case .Hearts, .Diamonds: return "red"
        }
    }
}

struct Card {
    var rank: Rank
    var suit: Suit
    func simpleDescription() -> String {
        return "The \(rank.simpleDescription()) of \(suit.simpleDescription())"
    }

    static func createPokers() -> Card[] {
        let ranks = Array(Rank.Ace.toRaw()...Rank.King.toRaw())
        let suits = Array(Suit.Spades.toRaw()...Suit.Clubs.toRaw())
        let cards = suits.reduce(Card[]()) { (tempCards, suit) in
            tempCards + ranks.map { rank in
                Card(rank: Rank.fromRaw(rank)!, suit: Suit.fromRaw(suit)!)
            }
        }
        return cards
    }
}

这看起来像一个黑客，但如果你使用原始值，你可以这样做

enum Suit: Int {  
    case Spades = 0, Hearts, Diamonds, Clubs  
 ...  
}  

var suitIndex = 0  
while var suit = Suit.fromRaw(suitIndex++) {  
   ...  
}  

enum Rank: Int {
    case Ace = 1
    case Two, Three, Four, Five, Six, Seven, Eight, Nine, Ten
    case Jack, Queen, King

    func simpleDescription() -> String {
        switch self {
        case .Ace: return "ace"
        case .Jack: return "jack"
        case .Queen: return "queen"
        case .King: return "king"
        default: return String(self.toRaw())
        }
    }
}

enum Suit: Int {
    case Spades = 1
    case Hearts, Diamonds, Clubs

    func simpleDescription() -> String {
        switch self {
        case .Spades: return "spades"
        case .Hearts: return "hearts"
        case .Diamonds: return "diamonds"
        case .Clubs: return "clubs"
        }
    }

    func color() -> String {
        switch self {
        case .Spades, .Clubs: return "black"
        case .Hearts, .Diamonds: return "red"
        }
    }
}

struct Card {
    var rank: Rank
    var suit: Suit
    func simpleDescription() -> String {
        return "The \(rank.simpleDescription()) of \(suit.simpleDescription())"
    }

    static func createPokers() -> Card[] {
        let ranks = Array(Rank.Ace.toRaw()...Rank.King.toRaw())
        let suits = Array(Suit.Spades.toRaw()...Suit.Clubs.toRaw())
        let cards = suits.reduce(Card[]()) { (tempCards, suit) in
            tempCards + ranks.map { rank in
                Card(rank: Rank.fromRaw(rank)!, suit: Suit.fromRaw(suit)!)
            }
        }
        return cards
    }
}

enum Rank: Int
{
    case Ace = 0
    case Two, Three, Four, Five, Six, Seve, Eight, Nine, Ten
    case Jack, Queen, King
    case Count
}

enum Suit : Int
{
    case Spades = 0
    case Hearts, Diamonds, Clubs
    case Count
}

struct Card
{
    var rank:Rank
    var suit:Suit
}

class Test
{
    func makeDeck() -> Card[]
    {
        let suitsCount:Int = Suit.Count.toRaw()
        let rankCount:Int = Rank.Count.toRaw()
        let repeatedCard:Card = Card(rank:Rank.Ace, suit:Suit.Spades)
        let deck:Card[] = Card[](count:suitsCount*rankCount, repeatedValue:repeatedCard)

        for i:Int in 0..rankCount
        {
            for j:Int in 0..suitsCount
            {
                deck[i*suitsCount+j] = Card(rank: Rank.fromRaw(i)!, suit: Suit.fromRaw(j)!)
            }
        }
        return deck
    }
}

根据Rick的回答:这要快5倍

我添加了函数count()，并迭代值:

public enum MetricType: Int {
    case mvps = 0
    case allNBA = 1
    case championshipRings = 2
    case finalAppearances = 3
    case gamesPlayed = 4
    case ppg = 5

    static func count() -> Int {
        return (ppg.rawValue) + 1
    }

    static var allValues: [MetricType] {
        var array: [MetricType] = Array()
        var item : MetricType = MetricType.mvps
        while item.rawValue < MetricType.count() {
            array.append(item)
            item = MetricType(rawValue: (item.rawValue + 1))!
        }
    return array
    }
}

(改进Karthik Kumar的回答)

这个解决方案是使用编译器来保证你不会错过一个case。

enum Suit: String {
    case spades = "♠"
    case hearts = "♥"
    case diamonds = "♦"
    case clubs = "♣"

    static var enumerate: [Suit] {
        switch Suit.spades {
        // make sure the two lines are identical ^_^
        case        .spades, .hearts, .diamonds, .clubs:
            return [.spades, .hearts, .diamonds, .clubs]
        }
    }
}