假设我有3个输入:rate、sendAmount和receiveAmount。我把这3个输入放到useEffect上。规则如下:
如果sendAmount改变了，我计算receiveAmount = sendAmount * rate
如果receiveAmount改变了，我计算sendAmount = receiveAmount / rate
如果速率发生变化，当sendAmount > 0时，我计算receiveAmount = sendAmount * rate;当receiveAmount > 0时，我计算sendAmount = receiveAmount / rate
下面是代码和框https://codesandbox.io/s/pkl6vn7x6j来演示这个问题。
是否有一种方法来比较oldValues和newValues，如componentDidUpdate，而不是为这种情况下做3处理程序?
谢谢
下面是我使用usePrevious的最终解决方案
https://codesandbox.io/s/30n01w2r06
在本例中，我不能使用多个useEffect，因为每次更改都会导致相同的网络调用。这就是为什么我还使用changeCount来跟踪更改。这个changeCount还有助于仅从本地跟踪更改，因此可以防止由于服务器更改而引起的不必要的网络调用。
选项1 -当值改变时运行useEffect
const Component = (props) => {
useEffect(() => {
console.log("val1 has changed");
}, [val1]);
return <div>...</div>;
};
Demo
选项2 - useHasChanged钩子
比较当前值和以前值是一种常见的模式，它证明了它自己的自定义钩子隐藏了实现细节。
const Component = (props) => {
const hasVal1Changed = useHasChanged(val1)
useEffect(() => {
if (hasVal1Changed ) {
console.log("val1 has changed");
}
});
return <div>...</div>;
};
const useHasChanged= (val: any) => {
const prevVal = usePrevious(val)
return prevVal !== val
}
const usePrevious = (value) => {
const ref = useRef();
useEffect(() => {
ref.current = value;
});
return ref.current;
}
Demo
您可以编写一个自定义钩子，使用useRef为您提供先前的道具
function usePrevious(value) {
const ref = useRef();
useEffect(() => {
ref.current = value;
});
return ref.current;
}
然后在useEffect中使用它
const Component = (props) => {
const {receiveAmount, sendAmount } = props
const prevAmount = usePrevious({receiveAmount, sendAmount});
useEffect(() => {
if(prevAmount.receiveAmount !== receiveAmount) {
// process here
}
if(prevAmount.sendAmount !== sendAmount) {
// process here
}
}, [receiveAmount, sendAmount])
}
但是，如果您为每个想要单独处理的变更id分别使用两个useEffect，那么阅读和理解起来会更清晰，可能会更好
由于状态与功能组件中的组件实例不是紧密耦合的，因此如果不先保存之前的状态，例如使用useRef，则无法在useEffect中到达之前的状态。这也意味着状态更新可能在错误的位置被错误地实现，因为之前的状态在setState更新函数中可用。
这是useReducer的一个很好的用例，它提供了类似redux的存储，并允许实现各自的模式。状态更新是显式执行的，因此不需要确定更新的是哪个状态属性;这在已调度的行动中已经很清楚了。
下面是一个例子:
function reducer({ sendAmount, receiveAmount, rate }, action) {
switch (action.type) {
case "sendAmount":
sendAmount = action.payload;
return {
sendAmount,
receiveAmount: sendAmount * rate,
rate
};
case "receiveAmount":
receiveAmount = action.payload;
return {
sendAmount: receiveAmount / rate,
receiveAmount,
rate
};
case "rate":
rate = action.payload;
return {
sendAmount: receiveAmount ? receiveAmount / rate : sendAmount,
receiveAmount: sendAmount ? sendAmount * rate : receiveAmount,
rate
};
default:
throw new Error();
}
}
function handleChange(e) {
const { name, value } = e.target;
dispatch({
type: name,
payload: value
});
}
...
const [state, dispatch] = useReducer(reducer, {
rate: 2,
sendAmount: 0,
receiveAmount: 0
});
...
离开公认的答案，一个不需要自定义钩子的替代解决方案:
const Component = ({ receiveAmount, sendAmount }) => {
const prevAmount = useRef({ receiveAmount, sendAmount }).current;
useEffect(() => {
if (prevAmount.receiveAmount !== receiveAmount) {
// process here
}
if (prevAmount.sendAmount !== sendAmount) {
// process here
}
return () => {
prevAmount.receiveAmount = receiveAmount;
prevAmount.sendAmount = sendAmount;
};
}, [receiveAmount, sendAmount]);
};
这假设您实际上需要引用前面“process here”位中的任何值。否则，除非你的条件超出了一个直接的!==比较，这里最简单的解决方案是:
const Component = ({ receiveAmount, sendAmount }) => {
useEffect(() => {
// process here
}, [receiveAmount]);
useEffect(() => {
// process here
}, [sendAmount]);
};
选项1 -当值改变时运行useEffect
const Component = (props) => {
useEffect(() => {
console.log("val1 has changed");
}, [val1]);
return <div>...</div>;
};
Demo
选项2 - useHasChanged钩子
比较当前值和以前值是一种常见的模式，它证明了它自己的自定义钩子隐藏了实现细节。
const Component = (props) => {
const hasVal1Changed = useHasChanged(val1)
useEffect(() => {
if (hasVal1Changed ) {
console.log("val1 has changed");
}
});
return <div>...</div>;
};
const useHasChanged= (val: any) => {
const prevVal = usePrevious(val)
return prevVal !== val
}
const usePrevious = (value) => {
const ref = useRef();
useEffect(() => {
ref.current = value;
});
return ref.current;
}
Demo
