假设我有3个输入:rate、sendAmount和receiveAmount。我把这3个输入放到useEffect上。规则如下:
如果sendAmount改变了,我计算receiveAmount = sendAmount * rate
如果receiveAmount改变了,我计算sendAmount = receiveAmount / rate
如果速率发生变化,当sendAmount > 0时,我计算receiveAmount = sendAmount * rate;当receiveAmount > 0时,我计算sendAmount = receiveAmount / rate
下面是代码和框https://codesandbox.io/s/pkl6vn7x6j来演示这个问题。
是否有一种方法来比较oldValues和newValues,如componentDidUpdate,而不是为这种情况下做3处理程序?
谢谢
下面是我使用usePrevious的最终解决方案
https://codesandbox.io/s/30n01w2r06
在本例中,我不能使用多个useEffect,因为每次更改都会导致相同的网络调用。这就是为什么我还使用changeCount来跟踪更改。这个changeCount还有助于仅从本地跟踪更改,因此可以防止由于服务器更改而引起的不必要的网络调用。
离开公认的答案,一个不需要自定义钩子的替代解决方案:
const Component = ({ receiveAmount, sendAmount }) => {
const prevAmount = useRef({ receiveAmount, sendAmount }).current;
useEffect(() => {
if (prevAmount.receiveAmount !== receiveAmount) {
// process here
}
if (prevAmount.sendAmount !== sendAmount) {
// process here
}
return () => {
prevAmount.receiveAmount = receiveAmount;
prevAmount.sendAmount = sendAmount;
};
}, [receiveAmount, sendAmount]);
};
这假设您实际上需要引用前面“process here”位中的任何值。否则,除非你的条件超出了一个直接的!==比较,这里最简单的解决方案是:
const Component = ({ receiveAmount, sendAmount }) => {
useEffect(() => {
// process here
}, [receiveAmount]);
useEffect(() => {
// process here
}, [sendAmount]);
};
由于状态与功能组件中的组件实例不是紧密耦合的,因此如果不先保存之前的状态,例如使用useRef,则无法在useEffect中到达之前的状态。这也意味着状态更新可能在错误的位置被错误地实现,因为之前的状态在setState更新函数中可用。
这是useReducer的一个很好的用例,它提供了类似redux的存储,并允许实现各自的模式。状态更新是显式执行的,因此不需要确定更新的是哪个状态属性;这在已调度的行动中已经很清楚了。
下面是一个例子:
function reducer({ sendAmount, receiveAmount, rate }, action) {
switch (action.type) {
case "sendAmount":
sendAmount = action.payload;
return {
sendAmount,
receiveAmount: sendAmount * rate,
rate
};
case "receiveAmount":
receiveAmount = action.payload;
return {
sendAmount: receiveAmount / rate,
receiveAmount,
rate
};
case "rate":
rate = action.payload;
return {
sendAmount: receiveAmount ? receiveAmount / rate : sendAmount,
receiveAmount: sendAmount ? sendAmount * rate : receiveAmount,
rate
};
default:
throw new Error();
}
}
function handleChange(e) {
const { name, value } = e.target;
dispatch({
type: name,
payload: value
});
}
...
const [state, dispatch] = useReducer(reducer, {
rate: 2,
sendAmount: 0,
receiveAmount: 0
});
...
下面是我使用的一个自定义钩子,我认为它比使用usePrevious更直观。
import { useRef, useEffect } from 'react'
// useTransition :: Array a => (a -> Void, a) -> Void
// |_______| |
// | |
// callback deps
//
// The useTransition hook is similar to the useEffect hook. It requires
// a callback function and an array of dependencies. Unlike the useEffect
// hook, the callback function is only called when the dependencies change.
// Hence, it's not called when the component mounts because there is no change
// in the dependencies. The callback function is supplied the previous array of
// dependencies which it can use to perform transition-based effects.
const useTransition = (callback, deps) => {
const func = useRef(null)
useEffect(() => {
func.current = callback
}, [callback])
const args = useRef(null)
useEffect(() => {
if (args.current !== null) func.current(...args.current)
args.current = deps
}, deps)
}
您可以像下面那样使用useTransition。
useTransition((prevRate, prevSendAmount, prevReceiveAmount) => {
if (sendAmount !== prevSendAmount || rate !== prevRate && sendAmount > 0) {
const newReceiveAmount = sendAmount * rate
// do something
} else {
const newSendAmount = receiveAmount / rate
// do something
}
}, [rate, sendAmount, receiveAmount])
希望这能有所帮助。
我刚刚发布了react-delta,它解决了这种情况。在我看来,useEffect有太多的责任。
责任
它使用Object.is比较其依赖数组中的所有值
它基于#1的结果运行effect/cleanup回调
分解责任
react-delta将useEffect的职责分解为几个更小的钩子。
责任# 1
usePrevious(值)
useLatest(值)
useDelta(价值,选项)
useDeltaArray (valueArray选项)
useDeltaObject (valueObject选项)
一些(deltaArray)
每一个(deltaArray)
责任# 2
布尔useConditionalEffect(回调)
根据我的经验,这种方法比useEffect/useRef解决方案更灵活、干净和简洁。