让我们说我有一个Javascript数组看起来如下:
["Element 1","Element 2","Element 3",...]; // with close to a hundred elements.
什么样的方法适合将数组分成许多更小的数组,假设最多有10个元素?
让我们说我有一个Javascript数组看起来如下:
["Element 1","Element 2","Element 3",...]; // with close to a hundred elements.
什么样的方法适合将数组分成许多更小的数组,假设最多有10个元素?
当前回答
使用发电机
函数*块(arr, n) { 对于(设I = 0;I < arrr .length;I += n) { 加勒比海盗。Slice (i, i + n); } } let someArray = [0,1,2,3,4,5,6,7,8,9] console.log([…块(someArray, 2)]) / /[[0, 1],[2、3],[4,5],[6、7],[8 9]]
可以像这样用Typescript输入:
function* chunks<T>(arr: T[], n: number): Generator<T[], void> {
for (let i = 0; i < arr.length; i += n) {
yield arr.slice(i, i + n);
}
}
其他回答
使用发电机
函数*块(arr, n) { 对于(设I = 0;I < arrr .length;I += n) { 加勒比海盗。Slice (i, i + n); } } let someArray = [0,1,2,3,4,5,6,7,8,9] console.log([…块(someArray, 2)]) / /[[0, 1],[2、3],[4,5],[6、7],[8 9]]
可以像这样用Typescript输入:
function* chunks<T>(arr: T[], n: number): Generator<T[], void> {
for (let i = 0; i < arr.length; i += n) {
yield arr.slice(i, i + n);
}
}
我只是在groupBy函数的帮助下写了这个。
// utils const group = (source) => ({ by: (grouping) => { const groups = source.reduce((accumulator, item) => { const name = JSON.stringify(grouping(item)); accumulator[name] = accumulator[name] || []; accumulator[name].push(item); return accumulator; }, {}); return Object.keys(groups).map(key => groups[key]); } }); const chunk = (source, size) => group(source.map((item, index) => ({ item, index }))) .by(x => Math.floor(x.index / size)) .map(x => x.map(v => v.item)); // 103 items const arr = [6,2,6,6,0,7,4,9,3,1,9,6,1,2,7,8,3,3,4,6,8,7,6,9,3,6,3,5,0,9,3,7,0,4,1,9,7,5,7,4,3,4,8,9,0,5,1,0,0,8,0,5,8,3,2,5,6,9,0,0,1,5,1,7,0,6,1,6,8,4,9,8,9,1,6,5,4,9,1,6,6,1,8,3,5,5,7,0,8,3,1,7,1,1,7,6,4,9,7,0,5,1,0]; const chunks = chunk(arr, 10); console.log(JSON.stringify(chunks));
我稍微改变了BlazeMonger的使用jQuery对象..
var $list = $('li'),
$listRows = [];
for (var i = 0, len = $list.length, chunk = 4, n = 0; i < len; i += chunk, n++) {
$listRows[n] = $list.slice(i, i + chunk);
}
她是一个简单的解决方案使用@Blazemonger解决方案
function array_chunk(arr, size){
// initialize vars
var i,
j = arr.length,
tempArray = [];
// loop through and jump based on size
for (i=0; i<j; i+=size) {
// slice chunk of arr and push to tempArray
tempArray.push(arr.slice(i,i+size));
}
// return temp array (chunck)
return tempArray
}
这让我的管道流动起来,希望这能帮助到其他人。:)
我在jsperf.com上测试了不同的答案。结果可以在https://web.archive.org/web/20150909134228/https://jsperf.com/chunk-mtds上找到
最快的函数(从IE8开始运行)是这个:
function chunk(arr, chunkSize) {
if (chunkSize <= 0) throw "Invalid chunk size";
var R = [];
for (var i=0,len=arr.length; i<len; i+=chunkSize)
R.push(arr.slice(i,i+chunkSize));
return R;
}