现在,我在'res/layout'文件夹内存储每个XML布局文件,因此管理小型项目是可行和简单的,但当有大型和繁重的项目的情况下,那么应该有一个层次结构和子文件夹内需要的布局文件夹。

如。

layout
-- layout_personal
   -- personal_detail.xml
   -- personal_other.xml
--layout_address
  -- address1.xml
  -- address2.xml

同样,我们希望大型应用程序有子文件夹,那么在Android项目中有办法做到这一点吗?

我能够在布局文件夹内创建layout-personal和layout_address子文件夹,但当需要使用R.layout访问XML布局文件时。_______,当时在菜单中没有任何XML布局弹出。


当前回答

我使用Android文件分组插件的Android工作室。它不允许你创建子文件夹,但是它可以显示你的文件和资源,因为它们在不同的文件夹中。这正是我想要的。

你可以安装“Android文件分组”插件通过

窗口:

Android Studio ->文件->设置->插件。

Mac:

Android Studio标签(左上)->首选项->插件->安装JetBrains插件..

对于Mac,我能够测试它,不能搜索插件。所以我从这里下载了插件,并从上面的设置中使用了从磁盘安装插件选项。

其他回答

你可以用gradle做到这一点。我做了一个演示项目来展示如何做到这一点。

诀窍是使用gradle的能力来合并多个资源文件夹,并设置res文件夹以及sourceSets块中的嵌套子文件夹。

奇怪的是,在声明容器资源文件夹的子资源文件夹之前,您不能声明该文件夹。

下面是构建中的sourceSets块。演示中的Gradle文件。注意,先声明子文件夹。

sourceSets {
    main {
        res.srcDirs = [
            'src/main/res/layouts/layouts_category2',
            'src/main/res/layouts',
            'src/main/res'
        ]
    }
}

另外,实际资源文件(png、xml布局等)的直接父文件仍然需要与规范相对应。

I think the most elegant solution to this problem (given that subfolders are not allowed) is to prepend the file names with the name of the folder you would have placed it inside of. For example, if you have a bunch of layouts for an Activity, Fragment, or just general view called "places" then you should just prepend it with places_my_layout_name. At least this solves the problem of organizing them in a way that they are easier to find within the IDE. It's not the most awesome solution, but it's better than nothing.

答案是否定的。

我想提请您注意这本书Pro Android 2,它指出:

It is also worth noting a few constraints regarding resources. First, Android supports only a linear list of files within the predefined folders under res. For example, it does not support nested folders under the layout folder (or the other folders under res). Second, there are some similarities between the assets folder and the raw folder under res. Both folders can contain raw files, but the files within raw are considered resources and the files within assets are not. Note that because the contents of the assets folder are not considered resources, you can put an arbitrary hierarchy of folders and files within it.

简而言之,答案是否定的。但你肯定可以有多个分辨率文件夹。我认为这是最接近布局文件夹的子文件夹了。你可以这样做。

小问题

我能够通过遵循这个问题的顶部答案来实现子文件夹。

然而,随着项目越来越大,你会有很多子文件夹:

sourceSets {
    main {
        res.srcDirs = [
            'src/main/res/layouts/somethingA',
            'src/main/res/layouts/somethingB',
            'src/main/res/layouts/somethingC',
            'src/main/res/layouts/somethingD',
            'src/main/res/layouts/somethingE',
            'src/main/res/layouts/somethingF',
            'src/main/res/layouts/somethingG',
            'src/main/res/layouts/somethingH',
            'src/main/res/layouts/...many more',
            'src/main/res'
        ]
    }
}

不是什么大问题,但是:

当清单变得很长时,它就不好看了。 你必须改变你的应用/构建。每次添加新文件夹时Gradle。


改进

所以我写了一个简单的Groovy方法来抓取所有嵌套文件夹:

def getLayoutList(path) {
    File file = new File(path)
    def throwAway = file.path.split("/")[0]
    def newPath = file.path.substring(throwAway.length() + 1)
    def array = file.list().collect {
        "${newPath}/${it}"
    }
    array.push("src/main/res");
    return array
}

将此方法粘贴到android{…}块在你的app/build.gradle。


如何使用

对于这样的结构:

<project root>
├── app <---------- TAKE NOTE
├── build
├── build.gradle
├── gradle
├── gradle.properties
├── gradlew
├── gradlew.bat
├── local.properties
└── settings.gradle

像这样使用它:

android {
    sourceSets {
        main {
            res.srcDirs = getLayoutList("app/src/main/res/layouts/")
        }
    }
}

如果你有一个这样的结构:

<project root>
├── my_special_app_name <---------- TAKE NOTE
├── build
├── build.gradle
├── gradle
├── gradle.properties
├── gradlew
├── gradlew.bat
├── local.properties
└── settings.gradle

你可以这样使用它:

android {
    sourceSets {
        main {
            res.srcDirs = getLayoutList("my_special_app_name/src/main/res/layouts/")
        }
    }
}

解释

getLayoutList()接受一个相对路径作为参数。相对路径相对于项目的根路径。所以当我们输入"app/src/main/res/layouts/"时,它会以数组的形式返回所有子文件夹的名称,这将与:

[
    'src/main/res/layouts/somethingA',
    'src/main/res/layouts/somethingB',
    'src/main/res/layouts/somethingC',
    'src/main/res/layouts/somethingD',
    'src/main/res/layouts/somethingE',
    'src/main/res/layouts/somethingF',
    'src/main/res/layouts/somethingG',
    'src/main/res/layouts/somethingH',
    'src/main/res/layouts/...many more',
    'src/main/res'
]

下面是带有注释的脚本,便于理解:

def getLayoutList(path) {
    // let's say path = "app/src/main/res/layouts/
    File file = new File(path)

    def throwAway = file.path.split("/")[0]
    // throwAway = 'app'

    def newPath = file.path.substring(throwAway.length() + 1) // +1 is for '/'
    // newPath = src/main/res/layouts/

    def array = file.list().collect {
        // println "filename: ${it}" // uncomment for debugging
        "${newPath}/${it}"
    }

    array.push("src/main/res");
    // println "result: ${array}" // uncomment for debugging

    return array
}

希望能有所帮助!