为什么编译器不让我向前声明类型定义?
假设这是不可能的,那么保持我的包含树小的最佳实践是什么?
为什么编译器不让我向前声明类型定义?
假设这是不可能的,那么保持我的包含树小的最佳实践是什么?
当前回答
像@BillKotsias一样,我使用了继承,而且它对我很有效。
我改变了这个混乱(这需要所有的boost头在我的声明*.h)
#include <boost/accumulators/accumulators.hpp>
#include <boost/accumulators/statistics.hpp>
#include <boost/accumulators/statistics/stats.hpp>
#include <boost/accumulators/statistics/mean.hpp>
#include <boost/accumulators/statistics/moment.hpp>
#include <boost/accumulators/statistics/min.hpp>
#include <boost/accumulators/statistics/max.hpp>
typedef boost::accumulators::accumulator_set<float,
boost::accumulators::features<
boost::accumulators::tag::median,
boost::accumulators::tag::mean,
boost::accumulators::tag::min,
boost::accumulators::tag::max
>> VanillaAccumulator_t ;
std::unique_ptr<VanillaAccumulator_t> acc;
在这个声明中(*.h)
class VanillaAccumulator;
std::unique_ptr<VanillaAccumulator> acc;
实现(*.cpp)是
#include <boost/accumulators/accumulators.hpp>
#include <boost/accumulators/statistics.hpp>
#include <boost/accumulators/statistics/stats.hpp>
#include <boost/accumulators/statistics/mean.hpp>
#include <boost/accumulators/statistics/moment.hpp>
#include <boost/accumulators/statistics/min.hpp>
#include <boost/accumulators/statistics/max.hpp>
class VanillaAccumulator : public
boost::accumulators::accumulator_set<float,
boost::accumulators::features<
boost::accumulators::tag::median,
boost::accumulators::tag::mean,
boost::accumulators::tag::min,
boost::accumulators::tag::max
>>
{
};
其他回答
在c++(而不是普通C)中,对一个类型定义两次是完全合法的,只要两个定义完全相同:
// foo.h
struct A{};
typedef A *PA;
// bar.h
struct A; // forward declare A
typedef A *PA;
void func(PA x);
// baz.cc
#include "bar.h"
#include "foo.h"
// We've now included the definition for PA twice, but it's ok since they're the same
...
A x;
func(&x);
你可以使用正向类型定义。但是要做
typedef A B;
你必须先向前申报A:
class A;
typedef A B;
我也有同样的问题,不想在不同的文件中混淆多个typedef,所以我用继承解决了它:
was:
class BurstBoss {
public:
typedef std::pair<Ogre::ParticleSystem*, bool> ParticleSystem; // removed this with...
did:
class ParticleSystem : public std::pair<Ogre::ParticleSystem*, bool>
{
public:
ParticleSystem(Ogre::ParticleSystem* system, bool enabled) : std::pair<Ogre::ParticleSystem*, bool>(system, enabled) {
};
};
效果很好。当然,我必须改变所有的参考资料
BurstBoss::ParticleSystem
简单地
ParticleSystem
要“fwd声明一个类型定义”,你需要fwd声明一个类或结构,然后你可以typedef声明类型。编译器可以接受多个相同的类型。
长形式:
class MyClass;
typedef MyClass myclass_t;
简式:
typedef class MyClass myclass_t;
我用继承和构造函数继承(?)替换了typedef(用来指定)。
原始
using CallStack = std::array<StackFrame, MAX_CALLSTACK_DEPTH>;
取代
struct CallStack // Not a typedef to allow forward declaration.
: public std::array<StackFrame, MAX_CALLSTACK_DEPTH>
{
typedef std::array<StackFrame, MAX_CALLSTACK_DEPTH> Base;
using Base::Base;
};
通过这种方式,我可以向前声明CallStack:
class CallStack;