Bool (generator)将返回正确的结果

建议:

def peek(iterable):
    try:
        first = next(iterable)
    except StopIteration:
        return None
    return first, itertools.chain([first], iterable)

用法:

res = peek(mysequence)
if res is None:
    # sequence is empty.  Do stuff.
else:
    first, mysequence = res
    # Do something with first, maybe?
    # Then iterate over the sequence:
    for element in mysequence:
        # etc.

下面是一个包装生成器的简单装饰器，因此如果为空，它将返回None。如果您的代码需要知道生成器在循环遍历之前是否会生成任何东西，那么这可能很有用。

def generator_or_none(func):
    """Wrap a generator function, returning None if it's empty. """

    def inner(*args, **kwargs):
        # peek at the first item; return None if it doesn't exist
        try:
            next(func(*args, **kwargs))
        except StopIteration:
            return None

        # return original generator otherwise first item will be missing
        return func(*args, **kwargs)

    return inner

用法:

import random

@generator_or_none
def random_length_generator():
    for i in range(random.randint(0, 10)):
        yield i

gen = random_length_generator()
if gen is None:
    print('Generator is empty')

一个有用的例子是在模板代码中—即jinj2

{% if content_generator %}
  <section>
    <h4>Section title</h4>
    {% for item in content_generator %}
      {{ item }}
    {% endfor %
  </section>
{% endif %}

在我的例子中，我需要知道在我将一组生成器传递给一个函数之前，它是否已经填充，该函数合并了这些项，即zip(…)。解决方案与公认的答案相似，但又有足够的不同:

定义:

def has_items(iterable):
    try:
        return True, itertools.chain([next(iterable)], iterable)
    except StopIteration:
        return False, []

用法:

def filter_empty(iterables):
    for iterable in iterables:
        itr_has_items, iterable = has_items(iterable)
        if itr_has_items:
            yield iterable


def merge_iterables(iterables):
    populated_iterables = filter_empty(iterables)
    for items in zip(*populated_iterables):
        # Use items for each "slice"

我的特定问题具有这样的属性，即可迭代对象要么为空，要么具有完全相同数量的条目。

我发现只有这个解决方案也适用于空迭代。

def is_generator_empty(generator):
    a, b = itertools.tee(generator)
    try:
        next(a)
    except StopIteration:
        return True, b
    return False, b

is_empty, generator = is_generator_empty(generator)

或者如果你不想使用异常来尝试使用

def is_generator_empty(generator):
    a, b = itertools.tee(generator)
    for item in a:
        return False, b
    return True, b

is_empty, generator = is_generator_empty(generator)

在标记的解决方案中，您不能将其用于空生成器，如

def get_empty_generator():
    while False:
        yield None 

generator = get_empty_generator()

Bool (generator)将返回正确的结果