简单地在onKeyUp()中做:

@Override
public boolean onKeyUp(int keyCode, KeyEvent event) {

    if (keyCode == KeyEvent.KEYCODE_BACK) {
        // do something
        return true;  // return true if back handled, false otherwise
    }

    return super.onKeyUp(keyCode, event);
}

通过处理onBackPressed提供自定义反向导航现在更容易在片段内进行回调。

class MyFragment : Fragment() {
    override fun onCreate(savedInstanceState: Bundle?) {
        super.onCreate(savedInstanceState)
        val onBackPressedCallback = object : OnBackPressedCallback(true) {
            override fun handleOnBackPressed() {
                if (true == conditionForCustomAction) {
                    myCustomActionHere()
                } else  NavHostFragment.findNavController(this@MyFragment).navigateUp();    
        }
    }
    requireActivity().onBackPressedDispatcher.addCallback(
        this, onBackPressedCallback
    )
    ...
}

如果你想要基于某些条件的默认后退动作，你可以使用:

 NavHostFragment.findNavController(this@MyFragment).navigateUp();

更新:OnBackPressedDispatcher应该被使用。

指南如何使用可在developer.android.com/guide/navigation/navigation-custom-back

你可以在activity中注册fragment来处理背按:

interface BackPressRegistrar {
    fun registerHandler(handler: BackPressHandler)
    fun unregisterHandler(handler: BackPressHandler)
}

interface BackPressHandler {
    fun onBackPressed(): Boolean
}

用法:

在片段:

private val backPressHandler = object : BackPressHandler {
    override fun onBackPressed(): Boolean {
        showClosingWarning()
        return false
    }
}

override fun onResume() {
    super.onResume()
    (activity as? BackPressRegistrar)?.registerHandler(backPressHandler)
}

override fun onStop() {
    (activity as? BackPressRegistrar)?.unregisterHandler(backPressHandler)
    super.onStop()
}

在活动:

class MainActivity : AppCompatActivity(), BackPressRegistrar {


    private var registeredHandler: BackPressHandler? = null
    override fun registerHandler(handler: BackPressHandler) { registeredHandler = handler }
    override fun unregisterHandler(handler: BackPressHandler) { registeredHandler = null }

    override fun onBackPressed() {
        if (registeredHandler?.onBackPressed() != false) super.onBackPressed()
    }
}

你可以像这样使用父活动的onBackPressedDispatcher:

val backpress = requireActivity().onBackPressedDispatcher.addCallback(viewLifecycleOwner, true) {
            // here dispatcher works for any action when back pressed
}

你也可以从fragment中启用/禁用backpress按钮，如下所示:

backpress.isEnabled = true/false

新的和更好的方法:以下片段中的代码段将帮助您捕获反按事件。

JAVA

@Override
public void onAttach(@NonNull Context context) {
    super.onAttach(context);

    OnBackPressedCallback callback = new OnBackPressedCallback(true) {
        @Override
        public void handleOnBackPressed() {
            Toast.makeText(mContext, "back pressed", Toast.LENGTH_SHORT).show();
            
            // And when you want to go back based on your condition
            if (yourCondition) {
                this.setEnabled(false);
                requireActivity().onBackPressed();
            }
        }
    };

    requireActivity().getOnBackPressedDispatcher().addCallback(this, callback);
}

科特林

activity?.onBackPressedDispatcher?.addCallback(viewLifecycleOwner, object : OnBackPressedCallback(true) {
    override fun handleOnBackPressed() {

    }
})

这是我的答案，处理碎片按下后退按钮。 我有底部导航与五个项目(A, B, C, D,E)附加到活动时，点击一个项目，我附加的片段到活动。 让我们假设点击项目(A)，我附加片段(A)，然后如果点击项目(B)，我附加片段(B)，以此类推。

点击项目的流程。A - C > B - > - > D - > E

返回按钮按下的流程。D E - > - > - > C > B

 @Override
        public void onBackPressed() {
            int count = getSupportFragmentManager().getBackStackEntryCount();
            if (count == 0) {
                super.onBackPressed();
            } else {
                int index = ((getSupportFragmentManager().getBackStackEntryCount()) -1);
                getSupportFragmentManager().popBackStack();
                FragmentManager.BackStackEntry backEntry = getSupportFragmentManager().getBackStackEntryAt(index);
                int stackId = backEntry.getId();
                bottomNavigationView.getMenu().getItem(stackId).setChecked(true);
            }
        }