是否有一种方法,我们可以实现onBackPressed()在Android片段类似的方式,我们实现在Android活动?

因为Fragment的生命周期没有onBackPressed()。在android3.0片段中是否有其他替代方法来覆盖onBackPressed() ?


当前回答

在片段的onCreate方法中添加以下内容:

@Override
public void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);

    OnBackPressedCallback callback = new OnBackPressedCallback(true) {
        @Override
        public void handleOnBackPressed() {
            //Handle the back pressed
        }
    };
    requireActivity().getOnBackPressedDispatcher().addCallback(this, callback);
}

其他回答

在我看来,最好的解决办法是:

JAVA解决方案

创建简单的界面:

public interface IOnBackPressed {
    /**
     * If you return true the back press will not be taken into account, otherwise the activity will act naturally
     * @return true if your processing has priority if not false
     */
    boolean onBackPressed();
}

在你的活动中

public class MyActivity extends Activity {
    @Override public void onBackPressed() {
    Fragment fragment = getSupportFragmentManager().findFragmentById(R.id.main_container);
       if (!(fragment instanceof IOnBackPressed) || !((IOnBackPressed) fragment).onBackPressed()) {
          super.onBackPressed();
       }
    } ...
}

最后在你的片段中:

public class MyFragment extends Fragment implements IOnBackPressed{
   @Override
   public boolean onBackPressed() {
       if (myCondition) {
            //action not popBackStack
            return true; 
        } else {
            return false;
        }
    }
}

芬兰湾的科特林解决方案

1 -创建接口

interface IOnBackPressed {
    fun onBackPressed(): Boolean
}

2 -准备你的活动

class MyActivity : AppCompatActivity() {
    override fun onBackPressed() {
        val fragment =
            this.supportFragmentManager.findFragmentById(R.id.main_container)
        (fragment as? IOnBackPressed)?.onBackPressed()?.not()?.let {
            super.onBackPressed()
        }
    }
}

3 -实现在你的目标片段

class MyFragment : Fragment(), IOnBackPressed {
    override fun onBackPressed(): Boolean {
        return if (myCondition) {
            //action not popBackStack
            true
        } else {
            false
        }
    }
}

试试这个,如果你真的想在Fragment中启用onBackPressed()。 在浪费了一个小时的时间后,我根据我以前的经验,做出了这个完全符合需求的解决方案。

你只需要关注私有int STATUS_FRAGMENT=0的值;这就满足了片段中addToBackStack()的需求。

import android.view.MenuItem;
import android.view.View;

import androidx.annotation.NonNull;
import androidx.appcompat.app.AppCompatActivity;
import androidx.fragment.app.Fragment;

import com.example.growfast.NavigationItemsFolder.CoreFragments.Cart;
import com.example.growfast.NavigationItemsFolder.CoreFragments.HelpDesk;
import com.example.growfast.NavigationItemsFolder.CoreFragments.Home;
import com.example.growfast.NavigationItemsFolder.CoreFragments.ProfileDetails;
import com.example.growfast.R;
import com.google.android.material.bottomnavigation.BottomNavigationView;

public class BusinessManagement extends AppCompatActivity {

    public BottomNavigationView bottomNavigationView;
    private int STATUS_FRAGMENT=0;

    @Override
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_base_layout);
        setBottomNavigationMenu();

    }

    private void setBottomNavigationMenu() {
        bottomNavigationView = findViewById(R.id.navigation);
        bottomNavigationView.setVisibility(View.VISIBLE);

        bottomNavigationView.setOnNavigationItemSelectedListener(new BottomNavigationView.OnNavigationItemSelectedListener() {

            Fragment fragment = null;

            @Override
            public boolean onNavigationItemSelected(@NonNull MenuItem item) {

                switch (item.getItemId()) {

                    case R.id.action_home:
                        fragment = new Home();
                        break;

                    case R.id.action_profile:
                        fragment = new ProfileDetails();
                        break;
                    case R.id.action_cart:
                        fragment = new Cart();
                        break;
                    case R.id.action_favourites_menu:
                        fragment = new HelpDesk();
                        break;

                }
                return loadFromFragment(fragment);

            }
        });
        bottomNavigationView.setSelectedItemId(R.id.action_home);
    }

    private boolean loadFromFragment(Fragment fragment) {
        if (fragment != null) {
            getSupportFragmentManager().beginTransaction().replace(R.id.my_container, fragment)
                    .commit();
            STATUS_FRAGMENT=1;
            return true;
        }
        return false;
    }

    @Override
    public void onBackPressed() {
        if (STATUS_FRAGMENT==1) {
            bottomNavigationView.setSelectedItemId(R.id.action_home);
            STATUS_FRAGMENT=0;
            bottomNavigationView.setVisibility(View.VISIBLE);
        }
        else{
            super.onBackPressed();
        }
    }


}```

在kotlin的情况下使用这个onAttach回调

        override fun onAttach(context: Context) {
          super.onAttach(context)
           val callback: OnBackPressedCallback = object : 
                 OnBackPressedCallback(true) {
                 override fun handleOnBackPressed() {
                 // your onbackpressed code 


            }
          }
      requireActivity().onBackPressedDispatcher.addCallback(this, callback)
      }

通过处理onBackPressed提供自定义反向导航现在更容易在片段内进行回调。

class MyFragment : Fragment() {
    override fun onCreate(savedInstanceState: Bundle?) {
        super.onCreate(savedInstanceState)
        val onBackPressedCallback = object : OnBackPressedCallback(true) {
            override fun handleOnBackPressed() {
                if (true == conditionForCustomAction) {
                    myCustomActionHere()
                } else  NavHostFragment.findNavController(this@MyFragment).navigateUp();    
        }
    }
    requireActivity().onBackPressedDispatcher.addCallback(
        this, onBackPressedCallback
    )
    ...
}

如果你想要基于某些条件的默认后退动作,你可以使用:

 NavHostFragment.findNavController(this@MyFragment).navigateUp();

如果你使用EventBus,它可能是一个更简单的解决方案:

在你的片段中:

@Override
public void onAttach(Activity activity) {
    super.onAttach(activity);
    EventBus.getDefault().register(this);
}

@Override
public void onDetach() {
    super.onDetach();
    EventBus.getDefault().unregister(this);
}


// This method will be called when a MessageEvent is posted
public void onEvent(BackPressedMessage type){
    getSupportFragmentManager().popBackStack();
}

在你的Activity类中你可以定义:

@Override
public void onStart() {
    super.onStart();
    EventBus.getDefault().register(this);
}

@Override
public void onStop() {
    EventBus.getDefault().unregister(this);
    super.onStop();
}

// This method will be called when a MessageEvent is posted
public void onEvent(BackPressedMessage type){
    super.onBackPressed();
}

@Override
public void onBackPressed() {
    EventBus.getDefault().post(new BackPressedMessage(true));
}

java只是一个POJO对象

这是超级干净的,没有接口/实现的麻烦。