private boolean isMainFragment = true;

@Override
public void onBackPressed() {

    if (isMainFragment){
        finish();
    }else {
        getSupportFragmentManager().popBackStack();
        isMainFragment = true;
    }
}

当打开花药片段时，只需添加

isMainFragment = false;

这是我的工作

非常简短而甜蜜的回答:

getActivity().onBackPressed();

我案例的整个场景说明:

我在MainActivity中有FragmentA， 我从FragmentA打开FragmentB (FragmentB是FragmentA的子或嵌套片段)

 Fragment duedateFrag = new FragmentB();
 FragmentTransaction ft  = getFragmentManager().beginTransaction();
 ft.replace(R.id.container_body, duedateFrag);
 ft.addToBackStack(null);
 ft.commit();

现在如果你想从FragmentB访问FragmentA你可以简单地输入getActivity().onBackPressed();在FragmentB。

在kotlin的情况下使用这个onAttach回调

        override fun onAttach(context: Context) {
          super.onAttach(context)
           val callback: OnBackPressedCallback = object : 
                 OnBackPressedCallback(true) {
                 override fun handleOnBackPressed() {
                 // your onbackpressed code 


            }
          }
      requireActivity().onBackPressedDispatcher.addCallback(this, callback)
      }

在我看来，最好的解决办法是:

JAVA解决方案

创建简单的界面:

public interface IOnBackPressed {
    /**
     * If you return true the back press will not be taken into account, otherwise the activity will act naturally
     * @return true if your processing has priority if not false
     */
    boolean onBackPressed();
}

在你的活动中

public class MyActivity extends Activity {
    @Override public void onBackPressed() {
    Fragment fragment = getSupportFragmentManager().findFragmentById(R.id.main_container);
       if (!(fragment instanceof IOnBackPressed) || !((IOnBackPressed) fragment).onBackPressed()) {
          super.onBackPressed();
       }
    } ...
}

最后在你的片段中:

public class MyFragment extends Fragment implements IOnBackPressed{
   @Override
   public boolean onBackPressed() {
       if (myCondition) {
            //action not popBackStack
            return true; 
        } else {
            return false;
        }
    }
}

芬兰湾的科特林解决方案

1 -创建接口

interface IOnBackPressed {
    fun onBackPressed(): Boolean
}

2 -准备你的活动

class MyActivity : AppCompatActivity() {
    override fun onBackPressed() {
        val fragment =
            this.supportFragmentManager.findFragmentById(R.id.main_container)
        (fragment as? IOnBackPressed)?.onBackPressed()?.not()?.let {
            super.onBackPressed()
        }
    }
}

3 -实现在你的目标片段

class MyFragment : Fragment(), IOnBackPressed {
    override fun onBackPressed(): Boolean {
        return if (myCondition) {
            //action not popBackStack
            true
        } else {
            false
        }
    }
}

在我的解决方案(Kotlin);

我使用onBackAlternative函数作为BaseActivity的参数。

BaseActivity

abstract class BaseActivity {

    var onBackPressAlternative: (() -> Unit)? = null

    override fun onBackPressed() {
        if (onBackPressAlternative != null) {
            onBackPressAlternative!!()
        } else {
            super.onBackPressed()
        }
    }
}

我有一个函数在BaseFragment上设置onBackPressAlternative。

碱基片段

abstract class BaseFragment {

     override fun onStart() {
        super.onStart()
        ...
        setOnBackPressed(null) // Add this
     }

      //Method must be declared as open, for overriding in child class
     open fun setOnBackPressed(onBackAlternative: (() -> Unit)?) {
         (activity as BaseActivity<*, *>).onBackPressAlternative = onBackAlternative
     }
}

然后我的onBackPressAlternative就可以用于片段了。

子片段

override fun setOnBackPressed(onBackAlternative: (() -> Unit)?) {
    (activity as BaseActivity<*, *>).onBackPressAlternative = {
        // TODO Your own custom onback function 
    }
}

简单地在onKeyUp()中做:

@Override
public boolean onKeyUp(int keyCode, KeyEvent event) {

    if (keyCode == KeyEvent.KEYCODE_BACK) {
        // do something
        return true;  // return true if back handled, false otherwise
    }

    return super.onKeyUp(keyCode, event);
}