我用这种方式解决了在活动中覆盖onBackPressed。所有的FragmentTransaction在提交前都是addToBackStack:

@Override
public void onBackPressed() {

    int count = getSupportFragmentManager().getBackStackEntryCount();

    if (count == 0) {
        super.onBackPressed();
        //additional code
    } else {
        getSupportFragmentManager().popBackStack();
    }

}

好了，伙计们，我终于找到一个好办法了。

在你的onCreate()在你的活动中容纳你的片段添加一个backstack更改监听器，如下所示:

    fragmentManager.addOnBackStackChangedListener(new FragmentManager.OnBackStackChangedListener() {
        @Override
        public void onBackStackChanged() {
            List<Fragment> f = fragmentManager.getFragments();
            //List<Fragment> f only returns one value
            Fragment frag = f.get(0);
            currentFragment = frag.getClass().getSimpleName();
        }
    });

(同时添加我的fragmenManager是在活动O 现在每次你改变fragment，当前的fragment String就会变成当前fragment的名字。然后在onBackPressed()活动中，你可以这样控制后退按钮的动作:

    @Override
    public void onBackPressed() {

    switch (currentFragment) {
        case "FragmentOne":
            // your code here
            return;
        case "FragmentTwo":
            // your code here
            return;
        default:
            fragmentManager.popBackStack();
            // default action for any other fragment (return to previous)
    }

}

我可以确认这个方法对我有用。

在我的解决方案(Kotlin);

我使用onBackAlternative函数作为BaseActivity的参数。

BaseActivity

abstract class BaseActivity {

    var onBackPressAlternative: (() -> Unit)? = null

    override fun onBackPressed() {
        if (onBackPressAlternative != null) {
            onBackPressAlternative!!()
        } else {
            super.onBackPressed()
        }
    }
}

我有一个函数在BaseFragment上设置onBackPressAlternative。

碱基片段

abstract class BaseFragment {

     override fun onStart() {
        super.onStart()
        ...
        setOnBackPressed(null) // Add this
     }

      //Method must be declared as open, for overriding in child class
     open fun setOnBackPressed(onBackAlternative: (() -> Unit)?) {
         (activity as BaseActivity<*, *>).onBackPressAlternative = onBackAlternative
     }
}

然后我的onBackPressAlternative就可以用于片段了。

子片段

override fun setOnBackPressed(onBackAlternative: (() -> Unit)?) {
    (activity as BaseActivity<*, *>).onBackPressAlternative = {
        // TODO Your own custom onback function 
    }
}

非常简短而甜蜜的回答:

getActivity().onBackPressed();

我案例的整个场景说明:

我在MainActivity中有FragmentA， 我从FragmentA打开FragmentB (FragmentB是FragmentA的子或嵌套片段)

 Fragment duedateFrag = new FragmentB();
 FragmentTransaction ft  = getFragmentManager().beginTransaction();
 ft.replace(R.id.container_body, duedateFrag);
 ft.addToBackStack(null);
 ft.commit();

现在如果你想从FragmentB访问FragmentA你可以简单地输入getActivity().onBackPressed();在FragmentB。

更新:OnBackPressedDispatcher应该被使用。

指南如何使用可在developer.android.com/guide/navigation/navigation-custom-back

你可以在activity中注册fragment来处理背按:

interface BackPressRegistrar {
    fun registerHandler(handler: BackPressHandler)
    fun unregisterHandler(handler: BackPressHandler)
}

interface BackPressHandler {
    fun onBackPressed(): Boolean
}

用法:

在片段:

private val backPressHandler = object : BackPressHandler {
    override fun onBackPressed(): Boolean {
        showClosingWarning()
        return false
    }
}

override fun onResume() {
    super.onResume()
    (activity as? BackPressRegistrar)?.registerHandler(backPressHandler)
}

override fun onStop() {
    (activity as? BackPressRegistrar)?.unregisterHandler(backPressHandler)
    super.onStop()
}

在活动:

class MainActivity : AppCompatActivity(), BackPressRegistrar {


    private var registeredHandler: BackPressHandler? = null
    override fun registerHandler(handler: BackPressHandler) { registeredHandler = handler }
    override fun unregisterHandler(handler: BackPressHandler) { registeredHandler = null }

    override fun onBackPressed() {
        if (registeredHandler?.onBackPressed() != false) super.onBackPressed()
    }
}

简单地在onKeyUp()中做:

@Override
public boolean onKeyUp(int keyCode, KeyEvent event) {

    if (keyCode == KeyEvent.KEYCODE_BACK) {
        // do something
        return true;  // return true if back handled, false otherwise
    }

    return super.onKeyUp(keyCode, event);
}