React钩子引入了useState来设置组件状态。但是我如何使用钩子来替换下面的回调代码:

setState(
  { name: "Michael" },
  () => console.log(this.state)
);

我想在状态更新后做一些事情。

我知道我可以使用useEffect来做额外的事情,但我必须检查之前的状态值,这需要位代码。我正在寻找一个简单的解决方案,可以使用useState挂钩。


当前回答

你的问题很有道理。让我告诉您,useEffect在默认情况下运行一次,并在每次依赖数组更改之后运行一次。

请看下面的例子:

import React,{ useEffect, useState } from "react";

const App = () => {
  const [age, setAge] = useState(0);
  const [ageFlag, setAgeFlag] = useState(false);

  const updateAge = ()=>{
    setAgeFlag(false);
    setAge(age+1);
    setAgeFlag(true);
  };

  useEffect(() => {
    if(!ageFlag){
      console.log('effect called without change - by default');
    }
    else{
      console.log('effect called with change ');
    }
  }, [ageFlag,age]);

  return (
    <form>
      <h2>hooks demo effect.....</h2>
      {age}
      <button onClick={updateAge}>Text</button>
    </form>
  );
}

export default App;

如果你想要setState回调与钩子一起执行,那么使用标志变量并在useEffect中给出If ELSE OR If块,以便当条件满足时,只执行该代码块。无论如何,当依赖项数组改变时,效果会运行,但效果中的IF代码只会在特定的条件下执行。

其他回答

你可以使用以下方法,我知道获得更新后的最新状态:

useEffect https://reactjs.org/docs/hooks-reference.html#useeffect

    const [state, setState] = useState({name: "Michael"});
    
    const handleChangeName = () => {
      setState({name: "Jack"});
    }
    
    useEffect(() => {
      console.log(state.name); //"Jack"

      //do something here
    }, [state]);

功能更新 https://reactjs.org/docs/hooks-reference.html#functional-updates 如果新的状态是用之前的状态计算出来的,你可以传递一个函数给setState。该函数将接收之前的值,并返回更新后的值。”

    const [state, setState] = useState({name: "Michael"});

    const handleChangeName = () => {
      setState({name: "Jack"})
      setState(prevState => {
        console.log(prevState.name);//"Jack"

        //do something here

        // return updated state
        return prevState;
      });
    }

useRef https://reactjs.org/docs/hooks-reference.html#useref 返回的ref对象将在组件的整个生命周期内持续存在。

    const [state, setState] = useState({name: "Michael"});

    const stateRef = useRef(state);
    stateRef.current  = state;
    const handleClick = () => {
      setState({name: "Jack"});

      setTimeout(() => {
        //it refers to old state object
        console.log(state.name);// "Michael";

        //out of syntheticEvent and after batch update
        console.log(stateRef.current.name);//"Jack"

        //do something here
      }, 0);
    }

在react synticevent处理程序中,setState是一个批量更新过程,因此每次状态更改都会等待并返回一个新状态。 setState()并不总是立即更新组件。它可以批处理或延迟更新。", https://reactjs.org/docs/react-component.html#setstate

这里有一个有用的链接 React是否保持状态更新的顺序?

我们可以写一个叫做useScheduleNextRenderCallback的钩子,它返回一个“schedule”函数。在我们调用setState之后,我们可以调用“schedule”函数,传递一个我们希望在下次呈现时运行的回调。

import { useCallback, useEffect, useRef } from "react";

type ScheduledCallback = () => void;
export const useScheduleNextRenderCallback = () => {
  const ref = useRef<ScheduledCallback>();

  useEffect(() => {
    if (ref.current !== undefined) {
      ref.current();
      ref.current = undefined;
    }
  });

  const schedule = useCallback((fn: ScheduledCallback) => {
    ref.current = fn;
  }, []);

  return schedule;
};

使用示例:

const App = () => {
  const scheduleNextRenderCallback = useScheduleNextRenderCallback();

  const [state, setState] = useState(0);

  const onClick = useCallback(() => {
    setState(state => state + 1);
    scheduleNextRenderCallback(() => {
      console.log("next render");
    });
  }, []);

  return <button onClick={onClick}>click me to update state</button>;
};

简化的测试用例:https://stackblitz.com/edit/react-ts-rjd9jk

您需要使用useEffect钩子来实现这一点。

const [counter, setCounter] = useState(0);

const doSomething = () => {
  setCounter(123);
}

useEffect(() => {
   console.log('Do something after counter has changed', counter);
}, [counter]);

如果你想在第一次初始渲染时忽略useEffect回调,那么相应地修改代码:

import React, { useEffect, useRef } from 'react';

const [counter, setCounter] = useState(0);
const didMount = useRef(false);

const doSomething = () => {
  setCounter(123);
}

useEffect(() => {
  // Return early, if this is the first render:
  if ( !didMount.current ) {
    return didMount.current = true;
  }
  // Paste code to be executed on subsequent renders:
  console.log('Do something after counter has changed', counter);
}, [counter]);

你的问题很有道理。让我告诉您,useEffect在默认情况下运行一次,并在每次依赖数组更改之后运行一次。

请看下面的例子:

import React,{ useEffect, useState } from "react";

const App = () => {
  const [age, setAge] = useState(0);
  const [ageFlag, setAgeFlag] = useState(false);

  const updateAge = ()=>{
    setAgeFlag(false);
    setAge(age+1);
    setAgeFlag(true);
  };

  useEffect(() => {
    if(!ageFlag){
      console.log('effect called without change - by default');
    }
    else{
      console.log('effect called with change ');
    }
  }, [ageFlag,age]);

  return (
    <form>
      <h2>hooks demo effect.....</h2>
      {age}
      <button onClick={updateAge}>Text</button>
    </form>
  );
}

export default App;

如果你想要setState回调与钩子一起执行,那么使用标志变量并在useEffect中给出If ELSE OR If块,以便当条件满足时,只执行该代码块。无论如何,当依赖项数组改变时,效果会运行,但效果中的IF代码只会在特定的条件下执行。

在我们有内置的setState回调支持之前,我们可以用简单的javascript方式…调用该函数并直接将新变量传递给它。

  const [counter, setCounter] = useState(0);

  const doSomething = () => {
    const newCounter = 123
    setCounter(newCounter);
    doSomethingWCounter(newCounter);
  };

  function doSomethingWCounter(newCounter) {
    console.log(newCounter); // 123
  }