简单的解决方案，只需安装

我使用-state-with-callback

import React from 'react';
import { useStateWithCallbackLazy } from "use-state-with-callback";

const initialFilters = {
  smart_filter: "",
};

const MyCallBackComp = () => {
  const [filters, setFilters] = useStateWithCallbackLazy(initialFilters);

  const filterSearchHandle = (e) => {
    setFilters(
      {
        ...filters,
        smart_filter: e,
      },
      (value) => console.log("smartFilters:>", value)
    );
  };

  return (
    <Input
      type="text"
      onChange={(e) => filterSearchHandle(e.target.value)}
      name="filter"
      placeholder="Search any thing..."
    />
  );
};

认为: 反应usestate回调

传递一个函数怎么样?

const [name, setName] = useState(initialName); 
...
setName(() => {
    const nextName = "Michael";
    console.log(nextName);
    return nextName;
  });

我不认为用useRef区分挂载与否是一个好方法，不是一个更好的方法来确定useState()在useEffect()中生成的值是否为初始值?

const [val, setVal] = useState(null)

useEffect(() => {
  if (val === null) return
  console.log('not mounted, val updated', val)
}, [val])

在我们有内置的setState回调支持之前，我们可以用简单的javascript方式…调用该函数并直接将新变量传递给它。

  const [counter, setCounter] = useState(0);

  const doSomething = () => {
    const newCounter = 123
    setCounter(newCounter);
    doSomethingWCounter(newCounter);
  };

  function doSomethingWCounter(newCounter) {
    console.log(newCounter); // 123
  }

您需要使用useEffect钩子来实现这一点。

const [counter, setCounter] = useState(0);

const doSomething = () => {
  setCounter(123);
}

useEffect(() => {
   console.log('Do something after counter has changed', counter);
}, [counter]);

如果你想在第一次初始渲染时忽略useEffect回调，那么相应地修改代码:

import React, { useEffect, useRef } from 'react';

const [counter, setCounter] = useState(0);
const didMount = useRef(false);

const doSomething = () => {
  setCounter(123);
}

useEffect(() => {
  // Return early, if this is the first render:
  if ( !didMount.current ) {
    return didMount.current = true;
  }
  // Paste code to be executed on subsequent renders:
  console.log('Do something after counter has changed', counter);
}, [counter]);

编辑

在这里使用promise似乎仍然推迟了重新渲染后的执行，两次触发setState可能是获得最新状态的最佳解决方案。因为setState将被列出，我们只需要在重新渲染之前获得prevState。

最初的发布

我刚刚弄清楚了我们是否可以在这里使用一个Promise让setState变成可等待的。

这是我的实验结果，感觉比使用回调更好

主要是在useEffect中触发解析函数

function useAsyncState(initialState) {
  const [state, setState] = useState(initialState)
  const resolveCb = useRef()

  const handleSetState = (updatedState) => new Promise((resolve, reject) => {
    // force previous promise resolved
    if (typeof resolveCb.current === 'function') {
      resolveCb.current(updatedState)
    }
    resolveCb.current = resolve
    try {
      setState(updatedState)
    } catch(err) {
      resolveCb.current = undefined
      reject(err)
    }
  })

  useEffect(() => {
    if (typeof resolveCb.current === 'function') {
      resolveCb.current(state)
      resolveCb.current = undefined
    }
  }, [state])

  return [state, handleSetState]
}

组件中使用

function App() {
  const [count, setCount] = useAsyncState(0)

  const increment = useMemoizedFn(async () => {
    const newCount = await setCount(count + 1)
    console.log(newCount)
  })

  console.log('rerender')

  return (
    <div>
      <h3 onClick={increment}>Hi, {count}</h3>
    </div>
  )
}