我写了自定义挂钩与typescript，如果有人还需要它。

import React, { useEffect, useRef, useState } from "react";

export const useStateWithCallback = <T>(initialState: T): [state: T, setState: (updatedState: React.SetStateAction<T>, callback?: (updatedState: T) => void) => void] => {
    const [state, setState] = useState<T>(initialState);
    const callbackRef = useRef<(updated: T) => void>();

    const handleSetState = (updatedState: React.SetStateAction<T>, callback?: (updatedState: T) => void) => {
        callbackRef.current = callback;
        setState(updatedState);
    };

    useEffect(() => {
        if (typeof callbackRef.current === "function") {
            callbackRef.current(state);
            callbackRef.current = undefined;
        }
    }, [state]);

    return [state, handleSetState];
}

我不认为用useRef区分挂载与否是一个好方法，不是一个更好的方法来确定useState()在useEffect()中生成的值是否为初始值?

const [val, setVal] = useState(null)

useEffect(() => {
  if (val === null) return
  console.log('not mounted, val updated', val)
}, [val])

您需要使用useEffect钩子来实现这一点。

const [counter, setCounter] = useState(0);

const doSomething = () => {
  setCounter(123);
}

useEffect(() => {
   console.log('Do something after counter has changed', counter);
}, [counter]);

如果你想在第一次初始渲染时忽略useEffect回调，那么相应地修改代码:

import React, { useEffect, useRef } from 'react';

const [counter, setCounter] = useState(0);
const didMount = useRef(false);

const doSomething = () => {
  setCounter(123);
}

useEffect(() => {
  // Return early, if this is the first render:
  if ( !didMount.current ) {
    return didMount.current = true;
  }
  // Paste code to be executed on subsequent renders:
  console.log('Do something after counter has changed', counter);
}, [counter]);

你的问题很有道理。让我告诉您，useEffect在默认情况下运行一次，并在每次依赖数组更改之后运行一次。

请看下面的例子:

import React,{ useEffect, useState } from "react";

const App = () => {
  const [age, setAge] = useState(0);
  const [ageFlag, setAgeFlag] = useState(false);

  const updateAge = ()=>{
    setAgeFlag(false);
    setAge(age+1);
    setAgeFlag(true);
  };

  useEffect(() => {
    if(!ageFlag){
      console.log('effect called without change - by default');
    }
    else{
      console.log('effect called with change ');
    }
  }, [ageFlag,age]);

  return (
    <form>
      <h2>hooks demo effect.....</h2>
      {age}
      <button onClick={updateAge}>Text</button>
    </form>
  );
}

export default App;

如果你想要setState回调与钩子一起执行，那么使用标志变量并在useEffect中给出If ELSE OR If块，以便当条件满足时，只执行该代码块。无论如何，当依赖项数组改变时，效果会运行，但效果中的IF代码只会在特定的条件下执行。

我认为，使用useEffect不是一种直观的方式。

我为此创建了一个包装器。在这个自定义钩子中，你可以将你的回调传递给setState参数，而不是useState参数。

我刚刚创建了Typescript版本。所以如果你需要在Javascript中使用它，只需从代码中删除一些类型符号。

使用

const [state, setState] = useStateCallback(1);
setState(2, (n) => {
  console.log(n) // 2
});

宣言

import { SetStateAction, useCallback, useEffect, useRef, useState } from 'react';

type Callback<T> = (value?: T) => void;
type DispatchWithCallback<T> = (value: T, callback?: Callback<T>) => void;

function useStateCallback<T>(initialState: T | (() => T)): [T, DispatchWithCallback<SetStateAction<T>>] {
  const [state, _setState] = useState(initialState);

  const callbackRef = useRef<Callback<T>>();
  const isFirstCallbackCall = useRef<boolean>(true);

  const setState = useCallback((setStateAction: SetStateAction<T>, callback?: Callback<T>): void => {
    callbackRef.current = callback;
    _setState(setStateAction);
  }, []);

  useEffect(() => {
    if (isFirstCallbackCall.current) {
      isFirstCallbackCall.current = false;
      return;
    }
    callbackRef.current?.(state);
  }, [state]);

  return [state, setState];
}

export default useStateCallback;

缺点

如果传递的箭头函数引用了一个变量外部函数，那么它将捕获当前值，而不是状态更新后的值。 在上面的使用示例中，console.log(state)将打印1而不是2。

我探索了use-state with-callback npm库和其他类似的自定义钩子，但最后我意识到我可以做这样的事情:

const [user, setUser] = React.useState(
  {firstName: 'joe', lastName: 'schmo'}
)

const handleFirstNameChange=(val)=> {
  const updatedUser = {
     ...user,
     firstName: val
  }
  setUser(updatedUser)
  updateDatabase(updatedUser)
}