有人知道如何在Python中从多维数组中提取列吗?
当前回答
array = [[1,2,3,4],[5,6,7,8],[9,10,11,12],[13,14,15,16]]
col1 = [val[1] for val in array]
col2 = [val[2] for val in array]
col3 = [val[3] for val in array]
col4 = [val[4] for val in array]
print(col1)
print(col2)
print(col3)
print(col4)
Output:
[1, 5, 9, 13]
[2, 6, 10, 14]
[3, 7, 11, 15]
[4, 8, 12, 16]
其他回答
如果你有一个数组
a = [[1, 2], [2, 3], [3, 4]]
然后像这样提取第一列:
[row[0] for row in a]
结果是这样的:
[1, 2, 3]
您是否使用了NumPy数组?Python有array模块,但不支持多维数组。普通的Python列表也是一维的。
然而,如果你有一个简单的二维列表,像这样:
A = [[1,2,3,4],
[5,6,7,8]]
然后你可以像这样提取一个列:
def column(matrix, i):
return [row[i] for row in matrix]
提取第二列(索引1):
>>> column(A, 1)
[2, 6]
或者简单地说:
>>> [row[1] for row in A]
[2, 6]
如果你在Python中有一个二维数组(不是numpy),你可以像这样提取所有的列,
data = [
['a', 1, 2],
['b', 3, 4],
['c', 5, 6]
]
columns = list(zip(*data))
print("column[0] = {}".format(columns[0]))
print("column[1] = {}".format(columns[1]))
print("column[2] = {}".format(columns[2]))
执行这段代码会得到,
>>> print("column[0] = {}".format(columns[0]))
column[0] = ('a', 'b', 'c')
>>> print("column[1] = {}".format(columns[1]))
column[1] = (1, 3, 5)
>>> print("column[2] = {}".format(columns[2]))
column[2] = (2, 4, 6)
我更喜欢下一个提示: 将矩阵命名为matrix_a并使用column_number,例如:
import numpy as np
matrix_a = np.array([[1,2,3,4],[5,6,7,8],[9,10,11,12]])
column_number=2
# you can get the row from transposed matrix - it will be a column:
col=matrix_a.transpose()[column_number]
array = [[1,2,3,4],[5,6,7,8],[9,10,11,12],[13,14,15,16]]
col1 = [val[1] for val in array]
col2 = [val[2] for val in array]
col3 = [val[3] for val in array]
col4 = [val[4] for val in array]
print(col1)
print(col2)
print(col3)
print(col4)
Output:
[1, 5, 9, 13]
[2, 6, 10, 14]
[3, 7, 11, 15]
[4, 8, 12, 16]