如何在Python中将彩色文本输出到终端?


当前回答

如果你正在编程一个游戏,也许你想改变背景颜色,只使用空格?例如:

print " "+ "\033[01;41m" + " " +"\033[01;46m"  + "  " + "\033[01;42m"

其他回答

我编写了一个简单的模块,可在以下网址获得:http://pypi.python.org/pypi/colorconsole

它适用于Windows、Mac OS X和Linux。它在Linux和Mac上使用ANSI,但在Windows上使用对控制台函数的本地调用。你有颜色、光标定位和键盘输入。它不是诅咒的替代品,但如果您需要在简单脚本或ASCII游戏中使用,它可能非常有用。

我是Python新手,每次我发现像这样的主题时都很兴奋。但这次(突然)我觉得我有话要说。尤其是因为几分钟前,我在Python中发现了一件令人惊叹的事情(至少对我来说是这样):

上下文管理器

from contextlib import contextmanager
# FORECOLOR
BLACKFC,REDFC,GREENFC,YELLOWFC,BLUEFC = '38;30m','38;31m','38;32m','38;33m','38;34m'
# BACKGOUND
BLACKBG,REDBG,GREENBG,YELLOWBG,BLUEBG = '48;40m','48;41m','48;42m','48;43m','48;44m'

@contextmanager
def printESC(prefix, color, text):
  print("{prefix}{color}{text}".format(prefix=prefix, color=color, text=text), end='')
  yield
  print("{prefix}0m".format(prefix=prefix))

with printESC('\x1B[', REDFC, 'Colored Text'):
  pass

实例

或者就像这样:

# FORECOLOR
BLACKFC,REDFC,GREENFC,YELLOWFC,BLUEFC = '38;30m','38;31m','38;32m','38;33m','38;34m'
# BACKGOUND
BLACKBG,REDBG,GREENBG,YELLOWBG,BLUEBG = '48;40m','48;41m','48;42m','48;43m','48;44m'

def printESC(prefix, color, text):
  print("{prefix}{color}{text}".format(prefix=prefix, color=color, text=text), end='')
  print("{prefix}0m".format(prefix=prefix))

printESC('\x1B[', REDFC, 'Colored Text')

https://raw.github.com/fabric/fabric/master/fabric/colors.py

"""
.. versionadded:: 0.9.2

Functions for wrapping strings in ANSI color codes.

Each function within this module returns the input string ``text``, wrapped
with ANSI color codes for the appropriate color.

For example, to print some text as green on supporting terminals::

    from fabric.colors import green

    print(green("This text is green!"))

Because these functions simply return modified strings, you can nest them::

    from fabric.colors import red, green

    print(red("This sentence is red, except for " + \
          green("these words, which are green") + "."))

If ``bold`` is set to ``True``, the ANSI flag for bolding will be flipped on
for that particular invocation, which usually shows up as a bold or brighter
version of the original color on most terminals.
"""


def _wrap_with(code):

    def inner(text, bold=False):
        c = code
        if bold:
            c = "1;%s" % c
        return "\033[%sm%s\033[0m" % (c, text)
    return inner

red = _wrap_with('31')
green = _wrap_with('32')
yellow = _wrap_with('33')
blue = _wrap_with('34')
magenta = _wrap_with('35')
cyan = _wrap_with('36')
white = _wrap_with('37')

我编写了一个在PyPI上可用的库,它有一个遵循标准打印函数的简单API。

你可以用pip安装着色来安装它。

import coloring

# Directly use print-like functions
coloring.print_red('Hello', 12)
coloring.print_green('Hey', end="", sep=";")
print()

# Get str as return
print(coloring.red('hello'))

# Use the generic colorize function
print(coloring.colorize("I'm red", "red")) # Using color names
print(coloring.colorize("I'm green", (0, 255, 0)))  # Using RGB colors
print(coloring.colorize("I'm blue", "#0000ff"))  # Using hex colors

# Or using styles (underline, bold, italic, ...)
print(coloring.colorize('Hello', 'red', s='ub'))  # underline and bold

执行代码:

您可以在此处查看所有功能:https://github.com/Nazime/coloring.

我最终做了这个,我觉得这是最干净的:

formatters = {
    'RED': '\033[91m',
    'GREEN': '\033[92m',
    'END': '\033[0m',
}

print 'Master is currently {RED}red{END}!'.format(**formatters)
print 'Help make master {GREEN}green{END} again!'.format(**formatters)