上面的建议非常好，但我认为大多数人只是想要一个现成的解决方案，不依赖于外部包，但也是可重用的。

我得到了上面所有的优点，并把它做成了一个函数，以及一个测试用例。

要使用它，只需复制“def update_progress(progress)”下面的行，而不是测试脚本。不要忘记导入sys。在需要显示或更新进度条时调用此函数。

这是通过直接向控制台发送“\r”符号来将光标移回起始位置。python中的"print"不能识别上述符号，因此我们需要'sys'

import time, sys

# update_progress() : Displays or updates a console progress bar
## Accepts a float between 0 and 1. Any int will be converted to a float.
## A value under 0 represents a 'halt'.
## A value at 1 or bigger represents 100%
def update_progress(progress):
    barLength = 10 # Modify this to change the length of the progress bar
    status = ""
    if isinstance(progress, int):
        progress = float(progress)
    if not isinstance(progress, float):
        progress = 0
        status = "error: progress var must be float\r\n"
    if progress < 0:
        progress = 0
        status = "Halt...\r\n"
    if progress >= 1:
        progress = 1
        status = "Done...\r\n"
    block = int(round(barLength*progress))
    text = "\rPercent: [{0}] {1}% {2}".format( "#"*block + "-"*(barLength-block), progress*100, status)
    sys.stdout.write(text)
    sys.stdout.flush()


# update_progress test script
print "progress : 'hello'"
update_progress("hello")
time.sleep(1)

print "progress : 3"
update_progress(3)
time.sleep(1)

print "progress : [23]"
update_progress([23])
time.sleep(1)

print ""
print "progress : -10"
update_progress(-10)
time.sleep(2)

print ""
print "progress : 10"
update_progress(10)
time.sleep(2)

print ""
print "progress : 0->1"
for i in range(101):
    time.sleep(0.1)
    update_progress(i/100.0)

print ""
print "Test completed"
time.sleep(10)

这是测试脚本显示的结果(最后一个进度条是动画):

progress : 'hello'
Percent: [----------] 0% error: progress var must be float
progress : 3
Percent: [##########] 100% Done...
progress : [23]
Percent: [----------] 0% error: progress var must be float

progress : -10
Percent: [----------] 0% Halt...

progress : 10
Percent: [##########] 100% Done...

progress : 0->1
Percent: [##########] 100% Done...
Test completed

如果它是一个大循环，迭代次数固定，需要花费很多时间，你可以使用我做的这个函数。循环的每一次迭代都增加了进展。其中count是循环的当前迭代，total是循环的值，size(int)是你想要的条的大小，以10为增量，即(size 1 =10个字符，size 2 =20个字符)

import sys
def loadingBar(count,total,size):
    percent = float(count)/float(total)*100
    sys.stdout.write("\r" + str(int(count)).rjust(3,'0')+"/"+str(int(total)).rjust(3,'0') + ' [' + '='*int(percent/10)*size + ' '*(10-int(percent/10))*size + ']')

例子:

for i in range(0,100):
     loadingBar(i,100,2)
     #do some code 

输出:

i = 50
>> 050/100 [==========          ]

你也可以用启迪。主要的优点是你可以在不覆盖进度条的同时记录日志。

import time
import enlighten

manager = enlighten.Manager()
pbar = manager.counter(total=100)

for num in range(1, 101):
    time.sleep(0.05)
    print('Step %d complete' % num)
    pbar.update()

它还可以处理多个进度条。

import time
import enlighten

manager = enlighten.Manager()
odds = manager.counter(total=50)
evens = manager.counter(total=50)

for num in range(1, 101):
    time.sleep(0.05)
    if num % 2:
        odds.update()
    else:
        evens.update()

对于类似的应用程序(在循环中跟踪进度)，我简单地使用python-progressbar:

他们的例子是这样的，

from progressbar import *               # just a simple progress bar


widgets = ['Test: ', Percentage(), ' ', Bar(marker='0',left='[',right=']'),
           ' ', ETA(), ' ', FileTransferSpeed()] #see docs for other options

pbar = ProgressBar(widgets=widgets, maxval=500)
pbar.start()

for i in range(100,500+1,50):
    # here do something long at each iteration
    pbar.update(i) #this adds a little symbol at each iteration
pbar.finish()
print

这里有一个简单的解决方案!

void = '-'
fill = '#'
count = 100/length
increaseCount = 0
for i in range(length):
    print('['+(fill*i)+(void*(length-i))+'] '+str(int(increaseCount))+'%',end='\r')
    increaseCount += count
    time.sleep(0.1)
print('['+(fill*(i+1))+(void*(length-(i+1)))+'] '+str(int(increaseCount))+'%',end='\n')

注意:如果需要，可以修改fill和“void”字符。

加载条(图片)

已经有很多令人惊叹的答案，但我想分享我对进度条的解决方案。

from time import sleep

def progress_bar(progress: float, total: float, width: int = 25):
    percent = width * ((progress + 1) / total)
    bar = chr(9608) * int(percent) + "-" * (width - int(percent))
    print(f"\r|{bar}| {(100/width)*percent:.2f}%", end="\r")

numbers = range(0, 1000)
numbersLen = len(numbers)
for i in numbers:
    sleep(0.01) # Do something usefull here
    progress_bar(i, numbersLen)

编辑:

如果你正在寻找一个条，调整它是基于终端的宽度和可能的消息在结束，然后这也是工作。请注意，如果终端太窄，消息将消失，因为如果它太宽，竖条将断开。

def progressBar(progress: float, total: float, message: str = ""):
    terminalWidth = get_terminal_size().columns
    width = int(terminalWidth / 4)
    percent = width * ((progress + 1) / total)
    bar = chr(9608) * int(percent) + "-" * (width - int(percent))
    if terminalWidth <= 40:
        message = ""
    else:
        message = message + (" " * (int(terminalWidth / 2) - len(message)))
    print(f"\r|{bar}| {(100/width)*percent:.2f}% " + message, end="\r")