当我的脚本正在执行一些可能需要时间的任务时,我如何使用进度条?

例如,一个函数需要一段时间才能完成,完成后返回True。如何在函数执行期间显示进度条?

请注意,我需要这是实时的,所以我不知道该怎么做。我需要一根线吗?我不知道。

现在我没有打印任何东西,而函数正在执行,但一个进度条会很好。此外,我更感兴趣的是从代码的角度如何做到这一点。


当前回答

#doesnt affect actual execution
#based on events and consumption in background
#may be that actual process completes a bit earlier than progress shows 99%
#make an instance with number of elements in a loop
#in each iteration call the method current_progress

import time
from math import ceil
import os
import sys
from threading import Thread
class progress_bar(object):
 def __init__(self,total_elements,length_bar=25):
  self.length_bar=length_bar
  self.total_elements=total_elements
  self.singleweight=(float(1)/float(total_elements))*100
  self.done=0
  self.qt=[0]
  self.call_count=0
  t=Thread(target=self.display_progress)
  t.start()
 def current_progress(self):
  self.done+=1
  self.qt=[self.done]+self.qt
 def display_progress(self):
  while True:
   try:
    done=self.qt.pop()
   except:
    continue
   else:
    self.call_count+=1
    self.progress=self.singleweight*done
    fill=ceil(self.progress)
    bar=int((fill*self.length_bar)/100)*"|"
    bar="["+bar+str(fill)+"%"
    barp=bar
    for i in range(0,self.length_bar+3-(len(bar))):
     barp=barp+"_"
    barp=barp+"]"
    if self.progress <= 100:
     os.system("clear")
     print("Progress:",barp, sep=' ', end='\n', file=sys.stdout, flush=True)
    if self.call_count == self.total_elements:
     break
  else:
   pass

其他回答

有一些特定的库(比如这里的这个),但也许一些非常简单的库就可以做到:

import time
import sys

toolbar_width = 40

# setup toolbar
sys.stdout.write("[%s]" % (" " * toolbar_width))
sys.stdout.flush()
sys.stdout.write("\b" * (toolbar_width+1)) # return to start of line, after '['

for i in range(toolbar_width):
    time.sleep(0.1) # do real work here
    # update the bar
    sys.stdout.write("-")
    sys.stdout.flush()

sys.stdout.write("]\n") # this ends the progress bar

注意:progressbar2是progressbar的一个分支,已经很多年没有维护过了。

受到许多不依赖包的答案的启发,我在这里分享我的实现。在任何循环中使用的函数都需要当前迭代数、迭代总数和初始时间。

import time    
def simple_progress_bar(i: int, n: int, init_time: float):
    avg_time = (time.time()-init_time)/(i+1)
    percent = ((i+1)/(n))*100
    print(
        end=f"\r|{'='*(int(percent))+'>'+'.'*int(100-int(percent))}|| " + \
        f"||Completion: {percent : 4.3f}% || \t "+ \
        f"||Time elapsed: {avg_time*(i+1):4.3f} seconds || \t " + \
        f"||Remaining time: {(avg_time*(n-(i+1))): 4.3f} seconds."
    )
    return



N = 325
t0 = time.time()
for k in range(N):
    # stuff goes here #
    time.sleep(0.0001)
    # stuff goes here #
    
    simple_progress_bar(k, N, t0)

上面的建议非常好,但我认为大多数人只是想要一个现成的解决方案,不依赖于外部包,但也是可重用的。

我得到了上面所有的优点,并把它做成了一个函数,以及一个测试用例。

要使用它,只需复制“def update_progress(progress)”下面的行,而不是测试脚本。不要忘记导入sys。在需要显示或更新进度条时调用此函数。

这是通过直接向控制台发送“\r”符号来将光标移回起始位置。python中的"print"不能识别上述符号,因此我们需要'sys'

import time, sys

# update_progress() : Displays or updates a console progress bar
## Accepts a float between 0 and 1. Any int will be converted to a float.
## A value under 0 represents a 'halt'.
## A value at 1 or bigger represents 100%
def update_progress(progress):
    barLength = 10 # Modify this to change the length of the progress bar
    status = ""
    if isinstance(progress, int):
        progress = float(progress)
    if not isinstance(progress, float):
        progress = 0
        status = "error: progress var must be float\r\n"
    if progress < 0:
        progress = 0
        status = "Halt...\r\n"
    if progress >= 1:
        progress = 1
        status = "Done...\r\n"
    block = int(round(barLength*progress))
    text = "\rPercent: [{0}] {1}% {2}".format( "#"*block + "-"*(barLength-block), progress*100, status)
    sys.stdout.write(text)
    sys.stdout.flush()


# update_progress test script
print "progress : 'hello'"
update_progress("hello")
time.sleep(1)

print "progress : 3"
update_progress(3)
time.sleep(1)

print "progress : [23]"
update_progress([23])
time.sleep(1)

print ""
print "progress : -10"
update_progress(-10)
time.sleep(2)

print ""
print "progress : 10"
update_progress(10)
time.sleep(2)

print ""
print "progress : 0->1"
for i in range(101):
    time.sleep(0.1)
    update_progress(i/100.0)

print ""
print "Test completed"
time.sleep(10)

这是测试脚本显示的结果(最后一个进度条是动画):

progress : 'hello'
Percent: [----------] 0% error: progress var must be float
progress : 3
Percent: [##########] 100% Done...
progress : [23]
Percent: [----------] 0% error: progress var must be float

progress : -10
Percent: [----------] 0% Halt...

progress : 10
Percent: [##########] 100% Done...

progress : 0->1
Percent: [##########] 100% Done...
Test completed
from IPython.display import clear_output
progress_bar=u"\u001b[7m Loading: "
for i in range(100):
    clear_output(wait=True)
    progress_bar+=u"\u001b[7m "
    print(progress_bar+str(i+1)+"%")
    time.sleep(0.03) #you can change the speed

输出

#doesnt affect actual execution
#based on events and consumption in background
#may be that actual process completes a bit earlier than progress shows 99%
#make an instance with number of elements in a loop
#in each iteration call the method current_progress

import time
from math import ceil
import os
import sys
from threading import Thread
class progress_bar(object):
 def __init__(self,total_elements,length_bar=25):
  self.length_bar=length_bar
  self.total_elements=total_elements
  self.singleweight=(float(1)/float(total_elements))*100
  self.done=0
  self.qt=[0]
  self.call_count=0
  t=Thread(target=self.display_progress)
  t.start()
 def current_progress(self):
  self.done+=1
  self.qt=[self.done]+self.qt
 def display_progress(self):
  while True:
   try:
    done=self.qt.pop()
   except:
    continue
   else:
    self.call_count+=1
    self.progress=self.singleweight*done
    fill=ceil(self.progress)
    bar=int((fill*self.length_bar)/100)*"|"
    bar="["+bar+str(fill)+"%"
    barp=bar
    for i in range(0,self.length_bar+3-(len(bar))):
     barp=barp+"_"
    barp=barp+"]"
    if self.progress <= 100:
     os.system("clear")
     print("Progress:",barp, sep=' ', end='\n', file=sys.stdout, flush=True)
    if self.call_count == self.total_elements:
     break
  else:
   pass