当我的脚本正在执行一些可能需要时间的任务时,我如何使用进度条?
例如,一个函数需要一段时间才能完成,完成后返回True。如何在函数执行期间显示进度条?
请注意,我需要这是实时的,所以我不知道该怎么做。我需要一根线吗?我不知道。
现在我没有打印任何东西,而函数正在执行,但一个进度条会很好。此外,我更感兴趣的是从代码的角度如何做到这一点。
当我的脚本正在执行一些可能需要时间的任务时,我如何使用进度条?
例如,一个函数需要一段时间才能完成,完成后返回True。如何在函数执行期间显示进度条?
请注意,我需要这是实时的,所以我不知道该怎么做。我需要一根线吗?我不知道。
现在我没有打印任何东西,而函数正在执行,但一个进度条会很好。此外,我更感兴趣的是从代码的角度如何做到这一点。
当前回答
#doesnt affect actual execution
#based on events and consumption in background
#may be that actual process completes a bit earlier than progress shows 99%
#make an instance with number of elements in a loop
#in each iteration call the method current_progress
import time
from math import ceil
import os
import sys
from threading import Thread
class progress_bar(object):
def __init__(self,total_elements,length_bar=25):
self.length_bar=length_bar
self.total_elements=total_elements
self.singleweight=(float(1)/float(total_elements))*100
self.done=0
self.qt=[0]
self.call_count=0
t=Thread(target=self.display_progress)
t.start()
def current_progress(self):
self.done+=1
self.qt=[self.done]+self.qt
def display_progress(self):
while True:
try:
done=self.qt.pop()
except:
continue
else:
self.call_count+=1
self.progress=self.singleweight*done
fill=ceil(self.progress)
bar=int((fill*self.length_bar)/100)*"|"
bar="["+bar+str(fill)+"%"
barp=bar
for i in range(0,self.length_bar+3-(len(bar))):
barp=barp+"_"
barp=barp+"]"
if self.progress <= 100:
os.system("clear")
print("Progress:",barp, sep=' ', end='\n', file=sys.stdout, flush=True)
if self.call_count == self.total_elements:
break
else:
pass
其他回答
#doesnt affect actual execution
#based on events and consumption in background
#may be that actual process completes a bit earlier than progress shows 99%
#make an instance with number of elements in a loop
#in each iteration call the method current_progress
import time
from math import ceil
import os
import sys
from threading import Thread
class progress_bar(object):
def __init__(self,total_elements,length_bar=25):
self.length_bar=length_bar
self.total_elements=total_elements
self.singleweight=(float(1)/float(total_elements))*100
self.done=0
self.qt=[0]
self.call_count=0
t=Thread(target=self.display_progress)
t.start()
def current_progress(self):
self.done+=1
self.qt=[self.done]+self.qt
def display_progress(self):
while True:
try:
done=self.qt.pop()
except:
continue
else:
self.call_count+=1
self.progress=self.singleweight*done
fill=ceil(self.progress)
bar=int((fill*self.length_bar)/100)*"|"
bar="["+bar+str(fill)+"%"
barp=bar
for i in range(0,self.length_bar+3-(len(bar))):
barp=barp+"_"
barp=barp+"]"
if self.progress <= 100:
os.system("clear")
print("Progress:",barp, sep=' ', end='\n', file=sys.stdout, flush=True)
if self.call_count == self.total_elements:
break
else:
pass
我使用format()方法来制作一个加载条。以下是我的解决方案:
import time
loadbarwidth = 23
for i in range(1, loadbarwidth + 1):
time.sleep(0.1)
strbarwidth = '[{}{}] - {}\r'.format(
(i * '#'),
((loadbarwidth - i) * '-'),
(('{:0.2f}'.format(((i) * (100/loadbarwidth))) + '%'))
)
print(strbarwidth ,end = '')
print()
输出:
[#######################] - 100.00%
这是创建进度条的简单方法
import time,sys
toolbar_width = 50
# setting up toolbar [-------------------------------------]
sys.stdout.write("[%s]"%(("-")*toolbar_width))
sys.stdout.flush()
# each hash represents 2 % of the progress
for i in range(toolbar_width):
sys.stdout.write("\r") # return to start of line
sys.stdout.flush()
sys.stdout.write("[")#Overwrite over the existing text from the start
sys.stdout.write("#"*(i+1))# number of # denotes the progress completed
sys.stdout.flush()
time.sleep(0.1)
一个非常简单的方法:
def progbar(count: int) -> None:
for i in range(count):
print(f"[{i*'#'}{(count-1-i)*' '}] - {i+1}/{count}", end="\r")
yield i
print('\n')
以及用法:
from time import sleep
for i in progbar(10):
sleep(0.2) #whatever task you need to do
下面的代码是一个相当通用的解决方案,也有一个时间消耗和剩余时间估计。你可以使用任何可迭代对象。进度条的大小固定为25个字符,但可以使用完整、半块和四分之一块字符以1%的速度显示更新。输出如下所示:
18% |████▌ | \ [0:00:01, 0:00:06]
代码示例:
import sys, time
from numpy import linspace
def ProgressBar(iterObj):
def SecToStr(sec):
m, s = divmod(sec, 60)
h, m = divmod(m, 60)
return u'%d:%02d:%02d'%(h, m, s)
L = len(iterObj)
steps = {int(x):y for x,y in zip(linspace(0, L, min(100,L), endpoint=False),
linspace(0, 100, min(100,L), endpoint=False))}
qSteps = ['', u'\u258E', u'\u258C', u'\u258A'] # quarter and half block chars
startT = time.time()
timeStr = ' [0:00:00, -:--:--]'
activity = [' -',' \\',' |',' /']
for nn,item in enumerate(iterObj):
if nn in steps:
done = u'\u2588'*int(steps[nn]/4.0)+qSteps[int(steps[nn]%4)]
todo = ' '*(25-len(done))
barStr = u'%4d%% |%s%s|'%(steps[nn], done, todo)
if nn>0:
endT = time.time()
timeStr = ' [%s, %s]'%(SecToStr(endT-startT),
SecToStr((endT-startT)*(L/float(nn)-1)))
sys.stdout.write('\r'+barStr+activity[nn%4]+timeStr); sys.stdout.flush()
yield item
barStr = u'%4d%% |%s|'%(100, u'\u2588'*25)
timeStr = ' [%s, 0:00:00]\n'%(SecToStr(time.time()-startT))
sys.stdout.write('\r'+barStr+timeStr); sys.stdout.flush()
# Example
s = ''
for c in ProgressBar(list('Disassemble and reassemble this string')):
time.sleep(0.2)
s += c
print(s)
欢迎提出改进建议或其他意见。干杯!