当我的脚本正在执行一些可能需要时间的任务时,我如何使用进度条?
例如,一个函数需要一段时间才能完成,完成后返回True。如何在函数执行期间显示进度条?
请注意,我需要这是实时的,所以我不知道该怎么做。我需要一根线吗?我不知道。
现在我没有打印任何东西,而函数正在执行,但一个进度条会很好。此外,我更感兴趣的是从代码的角度如何做到这一点。
当我的脚本正在执行一些可能需要时间的任务时,我如何使用进度条?
例如,一个函数需要一段时间才能完成,完成后返回True。如何在函数执行期间显示进度条?
请注意,我需要这是实时的,所以我不知道该怎么做。我需要一根线吗?我不知道。
现在我没有打印任何东西,而函数正在执行,但一个进度条会很好。此外,我更感兴趣的是从代码的角度如何做到这一点。
当前回答
使用os_sys lib:
我在许多类型的条形图中使用它,例如:
from os_sys.progress import bar as Bar
bar = Bar('progresing: ', max=20)
for i in range(20):
#do somthing
bar.next()
bar.finish()
你的输出将是:
procesing: |###### | 2/10
请在os_sys的描述中阅读更多信息
其他回答
在这里寻找等效的解决方案后,我只是为我的需求做了一个简单的进度类。我想我应该把它贴出来。
from __future__ import print_function
import sys
import re
class ProgressBar(object):
DEFAULT = 'Progress: %(bar)s %(percent)3d%%'
FULL = '%(bar)s %(current)d/%(total)d (%(percent)3d%%) %(remaining)d to go'
def __init__(self, total, width=40, fmt=DEFAULT, symbol='=',
output=sys.stderr):
assert len(symbol) == 1
self.total = total
self.width = width
self.symbol = symbol
self.output = output
self.fmt = re.sub(r'(?P<name>%\(.+?\))d',
r'\g<name>%dd' % len(str(total)), fmt)
self.current = 0
def __call__(self):
percent = self.current / float(self.total)
size = int(self.width * percent)
remaining = self.total - self.current
bar = '[' + self.symbol * size + ' ' * (self.width - size) + ']'
args = {
'total': self.total,
'bar': bar,
'current': self.current,
'percent': percent * 100,
'remaining': remaining
}
print('\r' + self.fmt % args, file=self.output, end='')
def done(self):
self.current = self.total
self()
print('', file=self.output)
例子:
from time import sleep
progress = ProgressBar(80, fmt=ProgressBar.FULL)
for x in xrange(progress.total):
progress.current += 1
progress()
sleep(0.1)
progress.done()
将打印以下内容:
[========] 17/80 (21%) 63
受到许多不依赖包的答案的启发,我在这里分享我的实现。在任何循环中使用的函数都需要当前迭代数、迭代总数和初始时间。
import time
def simple_progress_bar(i: int, n: int, init_time: float):
avg_time = (time.time()-init_time)/(i+1)
percent = ((i+1)/(n))*100
print(
end=f"\r|{'='*(int(percent))+'>'+'.'*int(100-int(percent))}|| " + \
f"||Completion: {percent : 4.3f}% || \t "+ \
f"||Time elapsed: {avg_time*(i+1):4.3f} seconds || \t " + \
f"||Remaining time: {(avg_time*(n-(i+1))): 4.3f} seconds."
)
return
N = 325
t0 = time.time()
for k in range(N):
# stuff goes here #
time.sleep(0.0001)
# stuff goes here #
simple_progress_bar(k, N, t0)
已经有很多令人惊叹的答案,但我想分享我对进度条的解决方案。
from time import sleep
def progress_bar(progress: float, total: float, width: int = 25):
percent = width * ((progress + 1) / total)
bar = chr(9608) * int(percent) + "-" * (width - int(percent))
print(f"\r|{bar}| {(100/width)*percent:.2f}%", end="\r")
numbers = range(0, 1000)
numbersLen = len(numbers)
for i in numbers:
sleep(0.01) # Do something usefull here
progress_bar(i, numbersLen)
编辑:
如果你正在寻找一个条,调整它是基于终端的宽度和可能的消息在结束,然后这也是工作。请注意,如果终端太窄,消息将消失,因为如果它太宽,竖条将断开。
def progressBar(progress: float, total: float, message: str = ""):
terminalWidth = get_terminal_size().columns
width = int(terminalWidth / 4)
percent = width * ((progress + 1) / total)
bar = chr(9608) * int(percent) + "-" * (width - int(percent))
if terminalWidth <= 40:
message = ""
else:
message = message + (" " * (int(terminalWidth / 2) - len(message)))
print(f"\r|{bar}| {(100/width)*percent:.2f}% " + message, end="\r")
这个进度条显示了每完成2%的点和每完成10%的数字。
import sys
def ProgressBar (num, total, nextPercent, nextPoint):
num = float (num)
total = float (total) - 1
if not nextPoint:
nextPoint = 0.0
if not nextPercent:
nextPoint += 2.0
sys.stdout.write ("[0%")
nextPercent = 10
elif num == total:
sys.stdout.write ("100%]\n")
nextPercent += 10
elif not nextPoint:
nextPoint = 0.0
elif num / total * 100 >= nextPercent:
sys.stdout.write (str(int (nextPercent)) + "%")
nextPercent += 10
elif num / total * 100 >= nextPoint:
sys.stdout.write (":")
nextPoint += 2
return (nextPercent, nextPoint)
nextPercent, nextPoint = 0, 0
total = 1000
for num in range (total):
nextPercent, nextPoint = ProgressBar (num, total, nextPercent, nextPoint)
结果:
>>>
[0%::::10%:::::20%:::::30%:::::40%:::::50%:::::60%:::::70%:::::80%:::::90%:::::100%]
>>>
我想我有点晚了,但这应该适用于使用当前版本的python 3的人,因为这使用了“f-strings”,正如python 3.6 PEP 498中介绍的那样:
Code
from numpy import interp
class Progress:
def __init__(self, value, end, title='Downloading',buffer=20):
self.title = title
#when calling in a for loop it doesn't include the last number
self.end = end -1
self.buffer = buffer
self.value = value
self.progress()
def progress(self):
maped = int(interp(self.value, [0, self.end], [0, self.buffer]))
print(f'{self.title}: [{"#"*maped}{"-"*(self.buffer - maped)}]{self.value}/{self.end} {((self.value/self.end)*100):.2f}%', end='\r')
例子
#some loop that does perfroms a task
for x in range(21) #set to 21 to include until 20
Progress(x, 21)
输出
Downloading: [########------------] 8/20 40.00%