当我的脚本正在执行一些可能需要时间的任务时,我如何使用进度条?

例如,一个函数需要一段时间才能完成,完成后返回True。如何在函数执行期间显示进度条?

请注意,我需要这是实时的,所以我不知道该怎么做。我需要一根线吗?我不知道。

现在我没有打印任何东西,而函数正在执行,但一个进度条会很好。此外,我更感兴趣的是从代码的角度如何做到这一点。


当前回答

已经有很多令人惊叹的答案,但我想分享我对进度条的解决方案。

from time import sleep

def progress_bar(progress: float, total: float, width: int = 25):
    percent = width * ((progress + 1) / total)
    bar = chr(9608) * int(percent) + "-" * (width - int(percent))
    print(f"\r|{bar}| {(100/width)*percent:.2f}%", end="\r")

numbers = range(0, 1000)
numbersLen = len(numbers)
for i in numbers:
    sleep(0.01) # Do something usefull here
    progress_bar(i, numbersLen)

编辑:

如果你正在寻找一个条,调整它是基于终端的宽度和可能的消息在结束,然后这也是工作。请注意,如果终端太窄,消息将消失,因为如果它太宽,竖条将断开。

def progressBar(progress: float, total: float, message: str = ""):
    terminalWidth = get_terminal_size().columns
    width = int(terminalWidth / 4)
    percent = width * ((progress + 1) / total)
    bar = chr(9608) * int(percent) + "-" * (width - int(percent))
    if terminalWidth <= 40:
        message = ""
    else:
        message = message + (" " * (int(terminalWidth / 2) - len(message)))
    print(f"\r|{bar}| {(100/width)*percent:.2f}% " + message, end="\r")

其他回答

我喜欢Brian Khuu的答案,因为它简单,不需要外部包。我做了一点改动,所以我在这里添加了我的版本:

import sys
import time


def updt(total, progress):
    """
    Displays or updates a console progress bar.

    Original source: https://stackoverflow.com/a/15860757/1391441
    """
    barLength, status = 20, ""
    progress = float(progress) / float(total)
    if progress >= 1.:
        progress, status = 1, "\r\n"
    block = int(round(barLength * progress))
    text = "\r[{}] {:.0f}% {}".format(
        "#" * block + "-" * (barLength - block), round(progress * 100, 0),
        status)
    sys.stdout.write(text)
    sys.stdout.flush()


runs = 300
for run_num in range(runs):
    time.sleep(.1)
    updt(runs, run_num + 1)

它取总运行次数(total)和目前处理的运行次数(progress),假设total >= progress。结果如下所示:

[#####---------------] 27%

如果你的工作不能被分解成可测量的块,你可以在一个新的线程中调用你的函数,并记录它所花费的时间:

import thread
import time
import sys

def work():
    time.sleep( 5 )

def locked_call( func, lock ):
    lock.acquire()
    func()
    lock.release()

lock = thread.allocate_lock()
thread.start_new_thread( locked_call, ( work, lock, ) )

# This part is icky...
while( not lock.locked() ):
    time.sleep( 0.1 )

while( lock.locked() ):
    sys.stdout.write( "*" )
    sys.stdout.flush()
    time.sleep( 1 )
print "\nWork Done"

显然,您可以根据需要提高计时精度。

这个进度条显示了每完成2%的点和每完成10%的数字。

import sys

def ProgressBar (num, total, nextPercent, nextPoint):
    num = float (num)
    total = float (total) - 1
    if not nextPoint:
        nextPoint = 0.0
    if not nextPercent:
        nextPoint += 2.0
        sys.stdout.write ("[0%")
        nextPercent = 10
    elif num == total:
        sys.stdout.write ("100%]\n")
        nextPercent += 10
    elif not nextPoint:
        nextPoint = 0.0
    elif num / total * 100 >= nextPercent:
        sys.stdout.write (str(int (nextPercent)) + "%")
        nextPercent += 10
    elif num / total * 100 >= nextPoint:
        sys.stdout.write (":")
        nextPoint += 2
    return (nextPercent, nextPoint)

nextPercent, nextPoint = 0, 0
total = 1000

for num in range (total):
    nextPercent, nextPoint = ProgressBar (num, total, nextPercent, nextPoint)

结果:

>>> 
[0%::::10%:::::20%:::::30%:::::40%:::::50%:::::60%:::::70%:::::80%:::::90%:::::100%]
>>> 

这在Python3中非常简单:

   import time
   import math

    def show_progress_bar(bar_length, completed, total):
        bar_length_unit_value = (total / bar_length)
        completed_bar_part = math.ceil(completed / bar_length_unit_value)
        progress = "*" * completed_bar_part
        remaining = " " * (bar_length - completed_bar_part)
        percent_done = "%.2f" % ((completed / total) * 100)
        print(f'[{progress}{remaining}] {percent_done}%', end='\r')

    bar_length = 30
    total = 100
    for i in range(0, total + 1):
        show_progress_bar(bar_length, i, total)
        time.sleep(0.1)

    print('\n')

我使用format()方法来制作一个加载条。以下是我的解决方案:

import time

loadbarwidth = 23

for i in range(1, loadbarwidth + 1):
    time.sleep(0.1) 

    strbarwidth = '[{}{}] - {}\r'.format(
        (i * '#'),
        ((loadbarwidth - i) * '-'),
        (('{:0.2f}'.format(((i) * (100/loadbarwidth))) + '%'))
    )

    print(strbarwidth ,end = '')

print()

输出:

[#######################] - 100.00%