受到许多不依赖包的答案的启发，我在这里分享我的实现。在任何循环中使用的函数都需要当前迭代数、迭代总数和初始时间。

import time    
def simple_progress_bar(i: int, n: int, init_time: float):
    avg_time = (time.time()-init_time)/(i+1)
    percent = ((i+1)/(n))*100
    print(
        end=f"\r|{'='*(int(percent))+'>'+'.'*int(100-int(percent))}|| " + \
        f"||Completion: {percent : 4.3f}% || \t "+ \
        f"||Time elapsed: {avg_time*(i+1):4.3f} seconds || \t " + \
        f"||Remaining time: {(avg_time*(n-(i+1))): 4.3f} seconds."
    )
    return



N = 325
t0 = time.time()
for k in range(N):
    # stuff goes here #
    time.sleep(0.0001)
    # stuff goes here #
    
    simple_progress_bar(k, N, t0)

PIP安装progressbar2

import os
import time
import progressbar 

os.environ['PYCHARM_HOSTED'] = '1' # https://github.com/WoLpH/python-progressbar/issues/237

class COLOR: # https://stackoverflow.com/a/287944/11465149
    YELLOW    = '\033[93m'
    GREEN     = '\033[92m'
    RED       = '\033[91m'
    BOLD      = '\033[1m'
    ENDC      = '\033[0m'

widgets=[
    'FILE.JSON ',
    COLOR.YELLOW          , progressbar.Percentage()                        , COLOR.ENDC,
    COLOR.RED + COLOR.BOLD, progressbar.Bar(left=' ', marker='━', right=' '), COLOR.ENDC,
    COLOR.YELLOW          , progressbar.Timer()                             , COLOR.ENDC
]

for i in progressbar.progressbar(range(100), widgets=widgets):
    time.sleep(0.01)
    if i == 99:
        widgets[4] = COLOR.GREEN

使用enumerate(…progressbar(max_value=…)+ this，以防你想使用它作为下载进度条

如果它是一个大循环，迭代次数固定，需要花费很多时间，你可以使用我做的这个函数。循环的每一次迭代都增加了进展。其中count是循环的当前迭代，total是循环的值，size(int)是你想要的条的大小，以10为增量，即(size 1 =10个字符，size 2 =20个字符)

import sys
def loadingBar(count,total,size):
    percent = float(count)/float(total)*100
    sys.stdout.write("\r" + str(int(count)).rjust(3,'0')+"/"+str(int(total)).rjust(3,'0') + ' [' + '='*int(percent/10)*size + ' '*(10-int(percent/10))*size + ']')

例子:

for i in range(0,100):
     loadingBar(i,100,2)
     #do some code 

输出:

i = 50
>> 050/100 [==========          ]

一个非常简单的方法:

def progbar(count: int) -> None:
    for i in range(count):
        print(f"[{i*'#'}{(count-1-i)*' '}] - {i+1}/{count}", end="\r")
        yield i
    print('\n')

以及用法:

from time import sleep

for i in progbar(10):
    sleep(0.2) #whatever task you need to do

下面的代码是一个相当通用的解决方案，也有一个时间消耗和剩余时间估计。你可以使用任何可迭代对象。进度条的大小固定为25个字符，但可以使用完整、半块和四分之一块字符以1%的速度显示更新。输出如下所示:

 18% |████▌                    | \ [0:00:01, 0:00:06]

代码示例:

import sys, time
from numpy import linspace

def ProgressBar(iterObj):
  def SecToStr(sec):
    m, s = divmod(sec, 60)
    h, m = divmod(m, 60)
    return u'%d:%02d:%02d'%(h, m, s)
  L = len(iterObj)
  steps = {int(x):y for x,y in zip(linspace(0, L, min(100,L), endpoint=False),
                                   linspace(0, 100, min(100,L), endpoint=False))}
  qSteps = ['', u'\u258E', u'\u258C', u'\u258A'] # quarter and half block chars
  startT = time.time()
  timeStr = '   [0:00:00, -:--:--]'
  activity = [' -',' \\',' |',' /']
  for nn,item in enumerate(iterObj):
    if nn in steps:
      done = u'\u2588'*int(steps[nn]/4.0)+qSteps[int(steps[nn]%4)]
      todo = ' '*(25-len(done))
      barStr = u'%4d%% |%s%s|'%(steps[nn], done, todo)
    if nn>0:
      endT = time.time()
      timeStr = ' [%s, %s]'%(SecToStr(endT-startT),
                             SecToStr((endT-startT)*(L/float(nn)-1)))
    sys.stdout.write('\r'+barStr+activity[nn%4]+timeStr); sys.stdout.flush()
    yield item
  barStr = u'%4d%% |%s|'%(100, u'\u2588'*25)
  timeStr = '   [%s, 0:00:00]\n'%(SecToStr(time.time()-startT))
  sys.stdout.write('\r'+barStr+timeStr); sys.stdout.flush()

# Example
s = ''
for c in ProgressBar(list('Disassemble and reassemble this string')):
  time.sleep(0.2)
  s += c
print(s)

欢迎提出改进建议或其他意见。干杯!

我使用format()方法来制作一个加载条。以下是我的解决方案:

import time

loadbarwidth = 23

for i in range(1, loadbarwidth + 1):
    time.sleep(0.1) 

    strbarwidth = '[{}{}] - {}\r'.format(
        (i * '#'),
        ((loadbarwidth - i) * '-'),
        (('{:0.2f}'.format(((i) * (100/loadbarwidth))) + '%'))
    )

    print(strbarwidth ,end = '')

print()

输出:

[#######################] - 100.00%