是否可以在ES6类中创建私有属性?

举个例子。 如何阻止访问instance.property?

class Something {
  constructor(){
    this.property = "test";
  }
}

var instance = new Something();
console.log(instance.property); //=> "test"

当前回答

我找到了一个非常简单的解决方案,只需使用Object.freeze()。当然,问题是以后你不能向对象添加任何东西。

class Cat {
    constructor(name ,age) {
        this.name = name
        this.age = age
        Object.freeze(this)
    }
}

let cat = new Cat('Garfield', 5)
cat.age = 6 // doesn't work, even throws an error in strict mode

其他回答

这取决于你问谁:-)

最大最小类提案中没有包含私有属性修饰符,这似乎已经进入了当前的草案。

但是,可能会支持私有名称,它允许私有属性—而且它们可能也可以用于类定义中。

更新:一个语法更好的提案正在酝酿中。欢迎投稿。


是的,对于对象的作用域访问,ES6引入了符号。

符号是唯一的,你不能从外部访问一个,除非通过反射(就像Java/ c#中的私有),但任何有权访问内部符号的人都可以使用它进行键访问:

var property = Symbol();
class Something {
    constructor(){
        this[property] = "test";
    }
}

var instance = new Something();

console.log(instance.property); //=> undefined, can only access with access to the Symbol

我们可以使用getter和setter来模拟类的私有属性。

eg 1

class FootballClub {
    constructor (cname, cstadium, ccurrentmanager) {
        this.name = cname;
        this._stadium  = cstadium;  //  we will treat this prop as private and give getter and setter for this.
        this.currmanager = ccurrentmanager;
    }

    get stadium( ) {
        return this._stadium.toUpperCase();
    }

}

let club = new FootballClub("Arsenal", "Emirates" , "Arteta")
console.log(club);
//FootballClub {
//    name: 'Arsenal',
//    _stadium: 'Emirates',
//    currmanager: 'Arteta'
//  }
console.log( club.stadium ); // EMIRATES
club.stadium = "Highbury"; // TypeError: Cannot set property stadium of #<FootballClub> which has only a getter

在上面的例子中,我们没有给出stadium的setter方法,因此我们不能为它设置一个新值。在接下来的例子中,为体育场添加了一个setter

eg 2

class FootballClub {
    constructor (cname, cstadium, ccurrentmanager) {
        this.name = cname;
        this._stadium  = cstadium;  //  we will treat this prop as private and give getter and setter for this.
        this.currmanager = ccurrentmanager;
    }

    get stadium( ) {
        return this._stadium.toUpperCase();
    }

    set stadium(val) {
       this._stadium = val;
    }
}

let club = new FootballClub("Arsenal", "Emirates" , "Arteta")
console.log(club.stadium); // EMIRATES
club.stadium = "Emirates Stadium";
console.log(club.stadium); // EMIRATES STADIUM

哦,这么多奇异的解决方案!我通常不关心隐私,所以我使用“伪隐私”,正如这里所说的。但如果确实关心(如果有一些特殊的要求),我会在这个例子中使用:

class jobImpl{
  // public
  constructor(name){
    this.name = name;
  }
  // public
  do(time){
    console.log(`${this.name} started at ${time}`);
    this.prepare();
    this.execute();
  }
  //public
  stop(time){
    this.finish();
    console.log(`${this.name} finished at ${time}`);
  }
  // private
  prepare(){ console.log('prepare..'); }
  // private
  execute(){ console.log('execute..'); }
  // private
  finish(){ console.log('finish..'); }
}

function Job(name){
  var impl = new jobImpl(name);
  return {
    do: time => impl.do(time),
    stop: time => impl.stop(time)
  };
}

// Test:
// create class "Job"
var j = new Job("Digging a ditch");
// call public members..
j.do("08:00am");
j.stop("06:00pm");

// try to call private members or fields..
console.log(j.name); // undefined
j.execute(); // error

函数(构造函数)的另一种可能实现:

function Job(name){
  var impl = new jobImpl(name);
  this.do = time => impl.do(time),
  this.stop = time => impl.stop(time)
}

更新:看别人的回答,这个已经过时了。

简单的回答,不,ES6类不支持私有属性。

但是你可以模仿这种行为,不将新属性附加到对象,而是将它们保存在类构造函数中,并使用getter和setter来获取隐藏的属性。注意,在类的每个新实例上重新定义getter和setter。

ES6

class Person {
    constructor(name) {
        var _name = name
        this.setName = function(name) { _name = name; }
        this.getName = function() { return _name; }
    }
}

ES5

function Person(name) {
    var _name = name
    this.setName = function(name) { _name = name; }
    this.getName = function() { return _name; }
}