在伊万·诺索夫的回答上加上我的2点意见:

在我的情况下，我需要许多键被“切片”出对象，所以它变得非常丑非常快，不是一个非常动态的解决方案:

const object = { a: 5, b: 6, c: 7, d: 8, aa: 5, bb: 6, cc: 7, dd: 8, aaa: 5, bbb: 6, ccc: 7, ddd: 8, ab: 5, bc: 6, cd: 7, de: 8  };
const picked = (({ a, aa, aaa, ab, c, cc, ccc, cd }) => ({ a, aa, aaa, ab, c, cc, ccc, cd }))(object);

console.log(picked);

这里有一个使用eval的动态解决方案:

const slice = (k, o) => eval(`(${k} => ${k})(o)`);


const object    = { a: 5, b: 6, c: 7, d: 8, aa: 5, bb: 6, cc: 7, dd: 8, aaa: 5, bbb: 6, ccc: 7, ddd: 8, ab: 5, bc: 6, cd: 7, de: 8  };
const sliceKeys = '({ a, aa, aaa, ab, c, cc, ccc, cd })';

console.log( slice(sliceKeys, object) );

使用对象解构和属性简写

Const对象= {a: 5, b: 6, c: 7}; const = (({a、c }) => ({ a、c}))(对象); console.log(选择);// {a: 5, c: 7}

来自Philipp Kewisch:

这实际上只是一个被即时调用的匿名函数。所有这些都可以在MDN上的解构分配页面上找到。这是一个展开的形式

Let unwrap = ({a, c}) => ({a, c}); 让unwrap2 = function({a, c}){返回{a, c};}; Let selected = unwrap({a: 5, b: 6, c: 7}); 让picke2 = unwrap2({a: 5, b: 6, c: 7}) console.log(选) console.log (picked2)

两种Array.prototype.reduce:

const selectable = {a: null, b: null};
const v = {a: true, b: 'yes', c: 4};

const r = Object.keys(selectable).reduce((a, b) => {
  return (a[b] = v[b]), a;
}, {});

console.log(r);

这个答案使用了神奇的逗号运算符: https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Operators/Comma_Operator

如果你想要更花哨，这个更紧凑:

const r = Object.keys(selectable).reduce((a, b) => (a[b] = v[b], a), {});

把所有这些放到一个可重用的函数中:

const getSelectable = function (selectable, original) {
  return Object.keys(selectable).reduce((a, b) => (a[b] = original[b], a), {})
};

const r = getSelectable(selectable, v);
console.log(r);

值得注意的是，Zod模式在默认情况下会删除未知属性。如果您已经在使用Zod，那么它很可能适合您的开发过程。

https://github.com/colinhacks/zod

import { z } from "zod";

// muppet schema
const muppet = z.object({
  color: z.string(),
  annoying: z.boolean(),
  height: z.string(),
  meta: z.object({ one: z.string(), two: z.string() }),
});

// TypeScript type if you want it
type TMuppet = z.infer<typeof muppet>;

// elmo example
const elmo: TMuppet = {
  color: "red",
  annoying: true,
  height: "unknown",
  meta: { one: "1", two: "2" },
};

// get a subset of the schema (another schema) if you want
const subset = muppet.pick({ color: true, height: true });

// parsing removes unknown properties by default
subset.parse(elmo); // { color: 'red', height: 'unknown' }

我知道它不是最干净的，但它简单易懂。

function obj_multi_select(obj, keys){
    let return_obj = {};
    for (let k = 0; k < keys.length; k++){
        return_obj[keys[k]] = obj[keys[k]];
    };
    return return_obj;
};

如何:

function sliceObj(obj) {
  var o = {}
    , keys = [].slice.call(arguments, 1);
  for (var i=0; i<keys.length; i++) {
    if (keys[i] in obj) o[keys[i]] = obj[keys[i]];
  }
  return o;
}

var subset = sliceObj(elmo, 'color', 'height');