使用JSON.stringify()并不总是可靠的。所以在我看来，这种方法是你问题的最佳解决方案

首先，不，没有通用的方法来确定一个对象是否相等!

但是有一个概念叫做浅平等比较。 有一个npm库可以帮助你使用这个概念

例子

const shallowequal = require('shallowequal');
 
const object = { 'user': 'fred' };
const other = { 'user': 'fred' };

// Referential Equality Comparison (`strict ===`)
object === other; // → false

// Shallow Equality Comparison
shallowequal(object, other); // → true

如果你想知道如何创建shallowEqual比较方法，那么请参考这里。它来自开源的fbjs Facebook库。

浅平等比较

shallowequal(其中obj1 methoda)

shallowEqual在两个值(即obj1和obj2)之间进行浅相等比较，以确定它们是否相等。

相等性是通过迭代给定obj1上的键来执行的，并且当任何键的值在obj1和obj2之间不严格相等时返回false。否则，只要所有键的值严格相等，就返回true。

下面的一些解决方案在性能、功能和风格方面存在问题……它们没有经过充分的考虑，其中一些在不同的情况下失败了。我试图在自己的解决方案中解决这个问题，我非常感谢您的反馈:

http://stamat.wordpress.com/javascript-object-comparison/

//Returns the object's class, Array, Date, RegExp, Object are of interest to us
var getClass = function(val) {
    return Object.prototype.toString.call(val)
        .match(/^\[object\s(.*)\]$/)[1];
};

//Defines the type of the value, extended typeof
var whatis = function(val) {

    if (val === undefined)
        return 'undefined';
    if (val === null)
        return 'null';

    var type = typeof val;

    if (type === 'object')
        type = getClass(val).toLowerCase();

    if (type === 'number') {
        if (val.toString().indexOf('.') > 0)
            return 'float';
        else
        return 'integer';
    }

    return type;
   };

var compareObjects = function(a, b) {
    if (a === b)
        return true;
    for (var i in a) {
        if (b.hasOwnProperty(i)) {
            if (!equal(a[i],b[i])) return false;
        } else {
            return false;
        }
    }

    for (var i in b) {
        if (!a.hasOwnProperty(i)) {
            return false;
        }
    }
    return true;
};

var compareArrays = function(a, b) {
    if (a === b)
        return true;
    if (a.length !== b.length)
        return false;
    for (var i = 0; i < a.length; i++){
        if(!equal(a[i], b[i])) return false;
    };
    return true;
};

var _equal = {};
_equal.array = compareArrays;
_equal.object = compareObjects;
_equal.date = function(a, b) {
    return a.getTime() === b.getTime();
};
_equal.regexp = function(a, b) {
    return a.toString() === b.toString();
};
//  uncoment to support function as string compare
//  _equal.fucntion =  _equal.regexp;



/*
 * Are two values equal, deep compare for objects and arrays.
 * @param a {any}
 * @param b {any}
 * @return {boolean} Are equal?
 */
var equal = function(a, b) {
    if (a !== b) {
        var atype = whatis(a), btype = whatis(b);

        if (atype === btype)
            return _equal.hasOwnProperty(atype) ? _equal[atype](a, b) : a==b;

        return false;
    }

    return true;
};

最简单和逻辑的解决方案，比较一切像对象，数组，字符串，Int…

JSON。stringify({a: val1}) == JSON。stringify ({a: val2})

注意:

你需要用你的Object替换val1和val2 对于对象，必须对两侧对象进行递归排序(按键)

假设对象中属性的顺序没有改变。

JSON.stringify()适用于深度和非深度这两种类型的对象，不太确定性能方面:

Var object1 = { 关键:“价值” }; Var object2 = { 关键:“价值” }; Var object3 = { 键:“无值” }; console.log('object1和object2相等:'，JSON.stringify(object1) === JSON.stringify(object2)); console.log('object2和object3相等:'，JSON.stringify(object2) === JSON.stringify(object3));

短功能deepEqual实现:

function deepEqual(x, y) {
  return (x && y && typeof x === 'object' && typeof y === 'object') ?
    (Object.keys(x).length === Object.keys(y).length) &&
      Object.keys(x).reduce(function(isEqual, key) {
        return isEqual && deepEqual(x[key], y[key]);
      }, true) : (x === y);
}

编辑:版本2，使用jib的建议和ES6的箭头函数:

function deepEqual(x, y) {
  const ok = Object.keys, tx = typeof x, ty = typeof y;
  return x && y && tx === 'object' && tx === ty ? (
    ok(x).length === ok(y).length &&
      ok(x).every(key => deepEqual(x[key], y[key]))
  ) : (x === y);
}

这是一个非常干净的CoffeeScript版本，你可以这样做:

Object::equals = (other) ->
  typeOf = Object::toString

  return false if typeOf.call(this) isnt typeOf.call(other)
  return `this == other` unless typeOf.call(other) is '[object Object]' or
                                typeOf.call(other) is '[object Array]'

  (return false unless this[key].equals other[key]) for key, value of this
  (return false if typeof this[key] is 'undefined') for key of other

  true

下面是测试:

  describe "equals", ->

    it "should consider two numbers to be equal", ->
      assert 5.equals(5)

    it "should consider two empty objects to be equal", ->
      assert {}.equals({})

    it "should consider two objects with one key to be equal", ->
      assert {a: "banana"}.equals {a: "banana"}

    it "should consider two objects with keys in different orders to be equal", ->
      assert {a: "banana", kendall: "garrus"}.equals {kendall: "garrus", a: "banana"}

    it "should consider two objects with nested objects to be equal", ->
      assert {a: {fruit: "banana"}}.equals {a: {fruit: "banana"}}

    it "should consider two objects with nested objects that are jumbled to be equal", ->
      assert {a: {a: "banana", kendall: "garrus"}}.equals {a: {kendall: "garrus", a: "banana"}}

    it "should consider two objects with arrays as values to be equal", ->
      assert {a: ["apple", "banana"]}.equals {a: ["apple", "banana"]}



    it "should not consider an object to be equal to null", ->
      assert !({a: "banana"}.equals null)

    it "should not consider two objects with different keys to be equal", ->
      assert !({a: "banana"}.equals {})

    it "should not consider two objects with different values to be equal", ->
      assert !({a: "banana"}.equals {a: "grapefruit"})