var object1 = {name: "humza" , gender : "male", age: 23}
var object2 = {name: "humza" , gender : "male", age: 23}
var result = Object.keys(object1).every((key) =>  object1[key] === object2[key])

如果object1在object2上具有相同的值，Result将为true。

最简单和逻辑的解决方案，比较一切像对象，数组，字符串，Int…

JSON。stringify({a: val1}) == JSON。stringify ({a: val2})

注意:

你需要用你的Object替换val1和val2 对于对象，必须对两侧对象进行递归排序(按键)

下面是stringify技巧的一个版本，它的输入较少，在很多情况下适用于简单的JSON数据比较。

var obj1Fingerprint = JSON.stringify(obj1).replace(/\{|\}/g,'').split(',').sort().join(',');
var obj2Fingerprint = JSON.stringify(obj2).replace(/\{|\}/g,'').split(',').sort().join(',');
if ( obj1Fingerprint === obj2Fingerprint) { ... } else { ... }

虽然这个问题已经有很多答案了。我只是想提供另一种实现方法:

const primitveDataTypes = ['number', 'boolean', 'string', 'undefined']; const isDateOrRegExp = (value) => value instanceof Date || value instanceof RegExp; const compare = (first, second) => { let agg = true; if(typeof first === typeof second && primitveDataTypes.indexOf(typeof first) !== -1 && first !== second){ agg = false; } // adding support for Date and RegExp. else if(isDateOrRegExp(first) || isDateOrRegExp(second)){ if(first.toString() !== second.toString()){ agg = false; } } else { if(Array.isArray(first) && Array.isArray(second)){ if(first.length === second.length){ for(let i = 0; i < first.length; i++){ if(typeof first[i] === 'object' && typeof second[i] === 'object'){ agg = compare(first[i], second[i]); } else if(first[i] !== second[i]){ agg = false; } } } else { agg = false; } } else { const firstKeys = Object.keys(first); const secondKeys = Object.keys(second); if(firstKeys.length !== secondKeys.length){ agg = false; } for(let j = 0 ; j < firstKeys.length; j++){ if(firstKeys[j] !== secondKeys[j]){ agg = false; } if(first[firstKeys[j]] && second[secondKeys[j]] && typeof first[firstKeys[j]] === 'object' && typeof second[secondKeys[j]] === 'object'){ agg = compare(first[firstKeys[j]], second[secondKeys[j]]); } else if(first[firstKeys[j]] !== second[secondKeys[j]]){ agg = false; } } } } return agg; } console.log('result', compare({a: 1, b: { c: [4, {d:5}, {e:6}]}, r: null}, {a: 1, b: { c: [4, {d:5}, {e:6}]}, r: 'ffd'})); //returns false.

let std1 = {
  name: "Abhijeet",
  roll: 1
}

let std2 = {
  name: "Siddharth",
  roll: 2
}

console.log(JSON.stringify(std1) === JSON.stringify(std2))

在Node.js中，你可以使用它的原生require("assert"). deepstrictequal。更多信息: http://nodejs.org/api/assert.html

例如:

var assert = require("assert");
assert.deepStrictEqual({a:1, b:2}, {a:1, b:3}); // will throw AssertionError

另一个返回true / false而不是返回错误的例子:

var assert = require("assert");

function deepEqual(a, b) {
    try {
      assert.deepEqual(a, b);
    } catch (error) {
      if (error.name === "AssertionError") {
        return false;
      }
      throw error;
    }
    return true;
};