严格相等运算符将告诉您两个对象类型是否相等。然而,是否有一种方法来判断两个对象是否相等,就像Java中的哈希码值一样?
堆栈溢出问题JavaScript中有hashCode函数吗?类似于这个问题,但需要一个更学术的答案。上面的场景说明了为什么有必要有一个,我想知道是否有等效的解决方案。
严格相等运算符将告诉您两个对象类型是否相等。然而,是否有一种方法来判断两个对象是否相等,就像Java中的哈希码值一样?
堆栈溢出问题JavaScript中有hashCode函数吗?类似于这个问题,但需要一个更学术的答案。上面的场景说明了为什么有必要有一个,我想知道是否有等效的解决方案。
当前回答
var object1 = {name: "humza" , gender : "male", age: 23}
var object2 = {name: "humza" , gender : "male", age: 23}
var result = Object.keys(object1).every((key) => object1[key] === object2[key])
如果object1在object2上具有相同的值,Result将为true。
其他回答
我使用这个可比函数来生成JSON可比的对象副本:
Var可比= o => (typeof o != '对象' || !o)?o: 种(o) .sort()。减少((c键)= > (c[主要]=可比(o(例子)),c), {}); / /演示: var = {1, c: 4 b:[2、3],d: {e:“5”,f:零}}; var b = {b:[2、3],c: 4 d: {f: null, e:“5”},答:1}; console.log (JSON.stringify(可比(a))); console.log (JSON.stringify(可比(b))); console.log(JSON.stringify(comparable(a)) == JSON.stringify(comparable(b))); < div id = " div " > < / div >
在测试中很方便(大多数测试框架都有一个is函数)。如。
is(JSON.stringify(comparable(x)), JSON.stringify(comparable(y)), 'x must match y');
如果捕捉到差异,则记录字符串,使差异可见:
x must match y
got {"a":1,"b":{"0":2,"1":3},"c":7,"d":{"e":"5","f":null}},
expected {"a":1,"b":{"0":2,"1":3},"c":4,"d":{"e":"5","f":null}}.
这是一个非常干净的CoffeeScript版本,你可以这样做:
Object::equals = (other) ->
typeOf = Object::toString
return false if typeOf.call(this) isnt typeOf.call(other)
return `this == other` unless typeOf.call(other) is '[object Object]' or
typeOf.call(other) is '[object Array]'
(return false unless this[key].equals other[key]) for key, value of this
(return false if typeof this[key] is 'undefined') for key of other
true
下面是测试:
describe "equals", ->
it "should consider two numbers to be equal", ->
assert 5.equals(5)
it "should consider two empty objects to be equal", ->
assert {}.equals({})
it "should consider two objects with one key to be equal", ->
assert {a: "banana"}.equals {a: "banana"}
it "should consider two objects with keys in different orders to be equal", ->
assert {a: "banana", kendall: "garrus"}.equals {kendall: "garrus", a: "banana"}
it "should consider two objects with nested objects to be equal", ->
assert {a: {fruit: "banana"}}.equals {a: {fruit: "banana"}}
it "should consider two objects with nested objects that are jumbled to be equal", ->
assert {a: {a: "banana", kendall: "garrus"}}.equals {a: {kendall: "garrus", a: "banana"}}
it "should consider two objects with arrays as values to be equal", ->
assert {a: ["apple", "banana"]}.equals {a: ["apple", "banana"]}
it "should not consider an object to be equal to null", ->
assert !({a: "banana"}.equals null)
it "should not consider two objects with different keys to be equal", ->
assert !({a: "banana"}.equals {})
it "should not consider two objects with different values to be equal", ->
assert !({a: "banana"}.equals {a: "grapefruit"})
这里有一个非常基本的方法来检查对象的“值是否相等”。
var john = {
occupation: "Web Developer",
age: 25
};
var bobby = {
occupation: "Web Developer",
age: 25
};
function isEquivalent(a, b) {
// Create arrays of property names
var aProps = Object.getOwnPropertyNames(a);
var bProps = Object.getOwnPropertyNames(b);
// If number of properties is different, objects are not equivalent
if (aProps.length != bProps.length) {
return false;
}
for (var i = 0; i < aProps.length; i++) {
var propName = aProps[i];
// If values of same property are not equal, objects are not equivalent
if (a[propName] !== b[propName]) {
return false;
}
}
// If we made it this far, objects are considered equivalent
return true;
}
// Outputs: true
console.log(isEquivalent(john, bobby));
演示 - JSFiddle
如你所见,为了检查对象的“值是否相等”,我们本质上必须遍历对象中的每个属性,以查看它们是否相等。虽然这个简单的实现适用于我们的示例,但有很多情况它无法处理。例如:
如果其中一个属性值本身就是一个对象呢? 如果属性值之一是NaN(中唯一的值 JavaScript不等于它自己?) 如果a有一个值为undefined的属性,而b没有呢 这个属性(因此计算为undefined?)
对于一个健壮的检查对象“值是否相等”的方法,最好依赖于一个经过良好测试的库,它涵盖了各种边缘情况,如下划线。
var john = {
occupation: "Web Developer",
age: 25
};
var bobby = {
occupation: "Web Developer",
age: 25
};
// Outputs: true
console.log(_.isEqual(john, bobby));
演示 - JSFiddle
let std1 = {
name: "Abhijeet",
roll: 1
}
let std2 = {
name: "Siddharth",
roll: 2
}
console.log(JSON.stringify(std1) === JSON.stringify(std2))
判断两个对象是否相似的一个快速“破解”方法是使用它们的toString()方法。如果您正在检查对象A和B,请确保A和B具有有意义的toString()方法,并检查它们返回的字符串是否相同。
这不是灵丹妙药,但有时在正确的情况下是有用的。