这是一个非常干净的CoffeeScript版本，你可以这样做:

Object::equals = (other) ->
  typeOf = Object::toString

  return false if typeOf.call(this) isnt typeOf.call(other)
  return `this == other` unless typeOf.call(other) is '[object Object]' or
                                typeOf.call(other) is '[object Array]'

  (return false unless this[key].equals other[key]) for key, value of this
  (return false if typeof this[key] is 'undefined') for key of other

  true

下面是测试:

  describe "equals", ->

    it "should consider two numbers to be equal", ->
      assert 5.equals(5)

    it "should consider two empty objects to be equal", ->
      assert {}.equals({})

    it "should consider two objects with one key to be equal", ->
      assert {a: "banana"}.equals {a: "banana"}

    it "should consider two objects with keys in different orders to be equal", ->
      assert {a: "banana", kendall: "garrus"}.equals {kendall: "garrus", a: "banana"}

    it "should consider two objects with nested objects to be equal", ->
      assert {a: {fruit: "banana"}}.equals {a: {fruit: "banana"}}

    it "should consider two objects with nested objects that are jumbled to be equal", ->
      assert {a: {a: "banana", kendall: "garrus"}}.equals {a: {kendall: "garrus", a: "banana"}}

    it "should consider two objects with arrays as values to be equal", ->
      assert {a: ["apple", "banana"]}.equals {a: ["apple", "banana"]}



    it "should not consider an object to be equal to null", ->
      assert !({a: "banana"}.equals null)

    it "should not consider two objects with different keys to be equal", ->
      assert !({a: "banana"}.equals {})

    it "should not consider two objects with different values to be equal", ->
      assert !({a: "banana"}.equals {a: "grapefruit"})

const one={name:'mohit' , age:30};
//const two ={name:'mohit',age:30};
const two ={age:30,name:'mohit'};

function isEquivalent(a, b) {
// Create arrays of property names
var aProps = Object.getOwnPropertyNames(a);
var bProps = Object.getOwnPropertyNames(b);



// If number of properties is different,
// objects are not equivalent
if (aProps.length != bProps.length) {
    return false;
}

for (var i = 0; i < aProps.length; i++) {
    var propName = aProps[i];

    // If values of same property are not equal,
    // objects are not equivalent
    if (a[propName] !== b[propName]) {
        return false;
    }
}

// If we made it this far, objects
// are considered equivalent
return true;
}

console.log(isEquivalent(one,two))

我需要模拟jQuery POST请求，因此对我来说重要的是两个对象具有相同的属性集(任何一个对象中都不缺少属性)，并且每个属性值都是“相等的”(根据这个定义)。我不关心对象是否有不匹配的方法。

这是我将使用的，它应该足以满足我的特定要求:

function PostRequest() {
    for (var i = 0; i < arguments.length; i += 2) {
        this[arguments[i]] = arguments[i+1];
    }

    var compare = function(u, v) {
        if (typeof(u) != typeof(v)) {
            return false;
        }

        var allkeys = {};
        for (var i in u) {
            allkeys[i] = 1;
        }
        for (var i in v) {
            allkeys[i] = 1;
        }
        for (var i in allkeys) {
            if (u.hasOwnProperty(i) != v.hasOwnProperty(i)) {
                if ((u.hasOwnProperty(i) && typeof(u[i]) == 'function') ||
                    (v.hasOwnProperty(i) && typeof(v[i]) == 'function')) {
                    continue;
                } else {
                    return false;
                }
            }
            if (typeof(u[i]) != typeof(v[i])) {
                return false;
            }
            if (typeof(u[i]) == 'object') {
                if (!compare(u[i], v[i])) {
                    return false;
                }
            } else {
                if (u[i] !== v[i]) {
                    return false;
                }
            }
        }

        return true;
    };

    this.equals = function(o) {
        return compare(this, o);
    };

    return this;
}

像这样使用:

foo = new PostRequest('text', 'hello', 'html', '<p>hello</p>');
foo.equals({ html: '<p>hello</p>', text: 'hello' });

Stringify两个对象并进行比较

返回(JSON.stringify(obj1) === = JSON.stringify(obj2))

这将返回true或false

function isEqual(obj1, obj2){
    type1 = typeof(obj1);
    type2 = typeof(obj2);
    if(type1===type2){
        switch (type1){
            case "object": return JSON.stringify(obj1)===JSON.stringify(obj2);
            case "function": return eval(obj1).toString()===eval(obj2).toString();
            default: return obj1==obj2;
        }
    }
    return false;
}//have not tried but should work.

这里有很多好的想法!这是我对深度相等的理解。我把它发布在github上，并围绕它写了一些测试。很难涵盖所有可能的情况，有时也没有必要这样做。

我介绍了NaN !== NaN以及循环依赖关系。

https://github.com/ryancat/simple-deep-equal/blob/master/index.js