如何确定部分对象(partial <T>)等于typescript中的原始对象(T)。

function compareTwoObjects<T>(original: T, partial: Partial<T>): boolean {
  return !Object.keys(partial).some((key) => partial[key] !== original[key]);
}

附注:最初我打算提出一个有答案的新问题。但这样的问题已经存在，并被标记为重复题。

下面是一个使用JSON的简短实现。stringify但按@Jor建议的方式对键进行排序。

一些测试来自@EbrahimByagowi的回答。

当然，通过使用JSON。stringify，解决方案仅限于JSON序列化类型(字符串、数字、JSON对象、数组、布尔值、null)。不支持Date、Function等对象。

function objectEquals(obj1, obj2) { const JSONstringifyOrder = obj => { const keys = {}; JSON.stringify(obj, (key, value) => { keys[key] = null; return value; }); return JSON.stringify(obj, Object.keys(keys).sort()); }; return JSONstringifyOrder(obj1) === JSONstringifyOrder(obj2); } /////////////////////////////////////////////////////////////// /// The borrowed tests, run them by clicking "Run code snippet" /////////////////////////////////////////////////////////////// var printResult = function (x) { if (x) { document.write('<div style="color: green;">Passed</div>'); } else { document.write('<div style="color: red;">Failed</div>'); } }; var assert = { isTrue: function (x) { printResult(x); }, isFalse: function (x) { printResult(!x); } } assert.isTrue(objectEquals("hi","hi")); assert.isTrue(objectEquals(5,5)); assert.isFalse(objectEquals(5,10)); assert.isTrue(objectEquals([],[])); assert.isTrue(objectEquals([1,2],[1,2])); assert.isFalse(objectEquals([1,2],[2,1])); assert.isFalse(objectEquals([1,2],[1,2,3])); assert.isTrue(objectEquals({},{})); assert.isTrue(objectEquals({a:1,b:2},{a:1,b:2})); assert.isTrue(objectEquals({a:1,b:2},{b:2,a:1})); assert.isFalse(objectEquals({a:1,b:2},{a:1,b:3})); assert.isTrue(objectEquals({1:{name:"mhc",age:28}, 2:{name:"arb",age:26}},{1:{name:"mhc",age:28}, 2:{name:"arb",age:26}})); assert.isFalse(objectEquals({1:{name:"mhc",age:28}, 2:{name:"arb",age:26}},{1:{name:"mhc",age:28}, 2:{name:"arb",age:27}}));

ES6:我能做到的最小代码是这样的。它通过对代表对象的所有键值数组进行字符串化来进行递归的深度比较，唯一的限制是没有方法或符号进行比较。

const compareObjects = (a, b) => { let s = (o) => Object.entries(o).sort()。映射(i => { if(i[1]实例对象)i[1] = s(i[1]); 返回我 }) 返回JSON.stringify(s(a)) === JSON.stringify(s(b)) ｝ console.log (compareObjects ({b: 4,答:{b: 1}}, {} {b: 1, b: 4}));

重要提示:这个函数正在执行JSON。stringfy在数组中，并将键排序，而不是在对象本身中:

["a" ["b"， 1]] [" b ", 4]

你可以使用_。isEqual(obj1, obj2)来自underscore.js库。

这里有一个例子:

var stooge = {name: 'moe', luckyNumbers: [13, 27, 34]};
var clone  = {name: 'moe', luckyNumbers: [13, 27, 34]};
stooge == clone;
=> false
_.isEqual(stooge, clone);
=> true

在这里查看官方文档:http://underscorejs.org/#isEqual

下面是ES6/ES2015中使用函数式方法的解决方案:

const typeOf = x => 
  ({}).toString
      .call(x)
      .match(/\[object (\w+)\]/)[1]

function areSimilar(a, b) {
  const everyKey = f => Object.keys(a).every(f)

  switch(typeOf(a)) {
    case 'Array':
      return a.length === b.length &&
        everyKey(k => areSimilar(a.sort()[k], b.sort()[k]));
    case 'Object':
      return Object.keys(a).length === Object.keys(b).length &&
        everyKey(k => areSimilar(a[k], b[k]));
    default:
      return a === b;
  }
}

这里有演示

EDIT: This method is quite flawed, and is rife with its own issues. I don't recommend it, and would appreciate some down-votes! It is problematic because 1) Some things can not be compared (i.e. functions) because they can not be serialized, 2) It isn't a very fast method of comparing, 3) It has ordering issues, 4) It can have collision issues/false positives if not properly implemented, 5) It can't check for "exactness" (===), and instead is based of value equality, which is oftentimes not what is desired in a comparison method.

这个问题的一个简单解决方案是对JSON字符串进行排序(每个字符)，但很多人没有意识到这一点。这通常也比这里提到的其他解决方案更快:

function areEqual(obj1, obj2) {
    var a = JSON.stringify(obj1), b = JSON.stringify(obj2);
    if (!a) a = '';
    if (!b) b = '';
    return (a.split('').sort().join('') == b.split('').sort().join(''));
}

关于这个方法的另一个有用的事情是，您可以通过向JSON传递一个“replace”函数来筛选比较。stringify函数(https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/JSON/stringify#Example_of_using_replacer_parameter)。下面只比较所有命名为“derp”的对象键:

function areEqual(obj1, obj2, filter) {
    var a = JSON.stringify(obj1, filter), b = JSON.stringify(obj2, filter);
    if (!a) a = '';
    if (!b) b = '';
    return (a.split('').sort().join('') == b.split('').sort().join(''));
}
var equal = areEqual(obj1, obj2, function(key, value) {
    return (key === 'derp') ? value : undefined;
});