android中合适的解决方案:

private static long SLEEP_TIME = 2 // for 2 second
.
.
MyLauncher launcher = new MyLauncher();
            launcher.start();
.
.
private class MyLauncher extends Thread {
        @Override
        /**
         * Sleep for 2 seconds as you can also change SLEEP_TIME 2 to any. 
         */
        public void run() {
            try {
                // Sleeping
                Thread.sleep(SLEEP_TIME * 1000);
            } catch (Exception e) {
                Log.e(TAG, e.getMessage());
            }
            //do something you want to do
           //And your code will be executed after 2 second
        }
    }

你可以使用新引入的lambda表达式让它更简洁:

new Handler().postDelayed(() -> {/*your code here*/}, time);

如果你必须使用处理器，但你在另一个线程中，你可以使用runonuithread在UI线程中运行处理器。这将避免抛出异常请求调用loop . prepare ()

runOnUiThread(new Runnable() {
    @Override
    public void run() {
        new Handler().postDelayed(new Runnable() {
            @Override
            public void run() {
                //Do something after 1 second
            }
        }, 1000);
    }
});

看起来很乱，但这是一种方法。

下面是Kotlin的答案，你们这些懒惰的人:

Handler().postDelayed({
//doSomethingHere()
}, 1000)

你可以在UIThread中使用Handler:

runOnUiThread(new Runnable() {
                
    @Override
    public void run() {
        new Handler().postDelayed(new Runnable() {
           @Override
           public void run() {
               //add your code here
          }
        }, 1000);           
    }
});

在Android中，我们可以编写下面的kotlin代码来延迟任何函数的执行

class MainActivity : AppCompatActivity() {

private lateinit var handler: Handler

override fun onCreate(savedInstanceState: Bundle?) {
    super.onCreate(savedInstanceState)
    setContentView(R.layout.activity_main)
    handler= Handler()
    handler.postDelayed({
        doSomething()
    },2000)
}

private fun doSomething() {
    Toast.makeText(this,"Hi! I am Toast Message",Toast.LENGTH_SHORT).show()
}
}