我希望能够在指定的延迟后调用以下方法。 在objective c中,有这样的东西:

[self performSelector:@selector(DoSomething) withObject:nil afterDelay:5];

在android和java中是否有类似的方法? 例如,我需要能够在5秒后调用一个方法。

public void DoSomething()
{
     //do something here
}

当前回答

android中合适的解决方案:

private static long SLEEP_TIME = 2 // for 2 second
.
.
MyLauncher launcher = new MyLauncher();
            launcher.start();
.
.
private class MyLauncher extends Thread {
        @Override
        /**
         * Sleep for 2 seconds as you can also change SLEEP_TIME 2 to any. 
         */
        public void run() {
            try {
                // Sleeping
                Thread.sleep(SLEEP_TIME * 1000);
            } catch (Exception e) {
                Log.e(TAG, e.getMessage());
            }
            //do something you want to do
           //And your code will be executed after 2 second
        }
    }

其他回答

5秒后在UI线程中执行一些东西:

new Handler(Looper.getMainLooper()).postDelayed(new Runnable() {
    @Override
    public void run() {
        //Do something here
    }
}, 5000);
final Handler handler = new Handler(); 
Timer t = new Timer(); 
t.schedule(new TimerTask() { 
    public void run() { 
        handler.post(new Runnable() { 
            public void run() { 
                //DO SOME ACTIONS HERE , THIS ACTIONS WILL WILL EXECUTE AFTER 5 SECONDS...
            }
        }); 
    } 
}, 5000); 

你可以使用这个最简单的解决方案:

new Handler().postDelayed(new Runnable() {
    @Override
    public void run() {
        //Write your code here
    }
}, 5000); //Timer is in ms here.

否则,下面可能是另一个干净有用的解决方案:

new Handler().postDelayed(() -> 
{/*Do something here*/}, 
5000); //time in ms

android中合适的解决方案:

private static long SLEEP_TIME = 2 // for 2 second
.
.
MyLauncher launcher = new MyLauncher();
            launcher.start();
.
.
private class MyLauncher extends Thread {
        @Override
        /**
         * Sleep for 2 seconds as you can also change SLEEP_TIME 2 to any. 
         */
        public void run() {
            try {
                // Sleeping
                Thread.sleep(SLEEP_TIME * 1000);
            } catch (Exception e) {
                Log.e(TAG, e.getMessage());
            }
            //do something you want to do
           //And your code will be executed after 2 second
        }
    }

在我的例子中,我不能用其他答案。 我使用本机java定时器代替。

new Timer().schedule(new TimerTask() {          
    @Override
    public void run() {
        // this code will be executed after 2 seconds       
    }
}, 2000);