我肯定会给Perl提供多个可怕的例子:

if(!$#var)

or

if($mystring =~ m/(\d+)/) {

从技术上讲，WTF不是一种语言，而是一种架构。

http://www.6502.org/tutorials/6502opcodes.html#JMP

6502总成，间接JMP:

注意，间接跳转没有进位，因此: 间接跳转绝对不能使用 从最后一个字节开始的向量 一页的 例如，如果地址$3000包含$40，$30FF包含$80，$3100包含$50,JMP ($30FF)的结果将是控制权转移到$4080，而不是你想要的$5080，即6502从$30FF获取地址的低字节，从$3000获取高字节。

因此，在代码中添加一个字节可能会使间接跳转偏离目标。

在PHP中，函数名不区分大小写。这可能会导致您认为php中的所有标识符都不区分大小写。再猜一遍。变量区分大小写。WTF。

function add($a, $b)
{
    return $a + $b;
}

$foo = add(1, 2);
$Foo = Add(3, 4);

echo "foo is $foo"; // outputs foo is 3
echo "Foo is $Foo"; // outputs Foo is 7

JCL条件返回执行。

//STEP02 EXEC PGM=PROG02,COND=(4,GT,STEP01) .

该特性允许您根据前面步骤的返回代码运行或不运行某个步骤。真是个不错的功能。

除了一些小功能，把逻辑颠倒过来。

首先，如果条件为真，则不运行步骤。

其次，4 GT,STEP01实际上意味着“如果STEP01的返回码大于4”

因此，整个过程意味着“如果来自STEP01的返回代码大于4，则不要运行此步骤”。这与“如果4大于来自STEP01的返回代码，则运行步骤”的简单解释几乎相同，但并不完全相同。

考虑到你唯一认真看待这些事情的时间是凌晨2点30分左右，电话另一端是一个疯狂的夜班接线员，这种双重模糊会导致严重的头痛。

MySQL枚举，特别是他们的能力，使生活的地狱毫无准备的同事。

CREATE TABLE foo (
    ....
    dispatched ENUM('0','1') NOT NULL DEFAULT '0',
)

然后:

UPDATE TABLE foo SET ..., dispatched = 1;

哎呀，dispatch被设置为0，因为1没有被引用。这真的惹恼了为我编写代码的人;我现在使用普通的int。

在一个相关的注意事项，即使你添加一个空字符串选项到你的枚举，例如。

blah ENUM('','A','B') NOT NULL,

如果给blah赋了一个无效值，MySQL将使用一个秘密隐藏的空字符串值来表示无效值，这将很难与您自己添加的值区分开来。耶!

Haskell's use of Maybe and Just. Maybe a is a type constructor that returns a type of Just a, but Maybe Int won't accept just an Int, it requires it to be a Just Int or Nothing. So in essence in haskell parlance Just Int is about as much of an Int as an apple is an orange. The only connection is that Just 5 returns a type of Maybe Interger, which can be constructed with the function Just and an Integer argument. This makes sense but is about as hard to explain as it can theoretically be, which is the purpose of haskell right? So is Just really JustKindaLikeButNotAtAll yea sorta, and is Maybe really a KindaLooksLikeOrIsNothing, yea sorta again.

-- Create a function that returns a Maybe Int, and return a 5, which know is definitly Int'able
>  let x :: Maybe Int; x = 5;
<interactive>:1:24:
    No instance for (Num (Maybe Int))
      arising from the literal `5' at <interactive>:1:24
    Possible fix: add an instance declaration for (Num (Maybe Int))
    In the expression: 5
    In the definition of `x': x = 5

>  Just 5  
Just 5
it :: Maybe Integer

    -- Create a function x which takes an Int
>  let x :: Int -> Int; x _ = 0;
x :: Int -> Int
-- Try to give it a Just Int
>  x $ Just 5                   

<interactive>:1:4:
    Couldn't match expected type `Int' against inferred type `Maybe t'
    In the second argument of `($)', namely `Just 5'
    In the expression: x $ Just 5
    In the definition of `it': it = x $ Just 5

祝你好运读到这篇文章，我希望它是正确的。