Java有一整本关于它们的书。

书http://www.javapuzzlers.com/lg-puzzlers-cropped.jpg

爪哇益智游戏

2000年Perl Journal's obfusated Perl Contest的最佳参赛作品:

#:: ::-| ::-| .-. :||-:: 0-| .-| ::||-| .:|-. :||
open(Q,$0);while(<Q>){if(/^#(.*)$/){for(split('-',$1)){$q=0;for(split){s/\|
/:.:/xg;s/:/../g;$Q=$_?length:$_;$q+=$q?$Q:$Q*20;}print chr($q);}}}print"\n";
#.: ::||-| .||-| :|||-| ::||-| ||-:: :|||-| .:|

代码由作者在http://mysite.verizon.net/les.peters/id2.html详细解释

Haskell's use of Maybe and Just. Maybe a is a type constructor that returns a type of Just a, but Maybe Int won't accept just an Int, it requires it to be a Just Int or Nothing. So in essence in haskell parlance Just Int is about as much of an Int as an apple is an orange. The only connection is that Just 5 returns a type of Maybe Interger, which can be constructed with the function Just and an Integer argument. This makes sense but is about as hard to explain as it can theoretically be, which is the purpose of haskell right? So is Just really JustKindaLikeButNotAtAll yea sorta, and is Maybe really a KindaLooksLikeOrIsNothing, yea sorta again.

-- Create a function that returns a Maybe Int, and return a 5, which know is definitly Int'able
>  let x :: Maybe Int; x = 5;
<interactive>:1:24:
    No instance for (Num (Maybe Int))
      arising from the literal `5' at <interactive>:1:24
    Possible fix: add an instance declaration for (Num (Maybe Int))
    In the expression: 5
    In the definition of `x': x = 5

>  Just 5  
Just 5
it :: Maybe Integer

    -- Create a function x which takes an Int
>  let x :: Int -> Int; x _ = 0;
x :: Int -> Int
-- Try to give it a Just Int
>  x $ Just 5                   

<interactive>:1:4:
    Couldn't match expected type `Int' against inferred type `Maybe t'
    In the second argument of `($)', namely `Just 5'
    In the expression: x $ Just 5
    In the definition of `it': it = x $ Just 5

祝你好运读到这篇文章，我希望它是正确的。

在JavaScript中，下面的构造

return
{
    id : 1234,
    title : 'Tony the Pony'
};

返回undefined是一个语法错误，因为在返回后的换行上偷偷地插入了分号。以下工作正如你所期望的那样:

return {
    id : 1234,
    title : 'Tony the Pony'
};

更糟糕的是，这个也可以(至少在Chrome中):

return /*
*/{
    id : 1234,
    title : 'Tony the Pony'
};

下面是同一个问题的一个变种，它不会产生语法错误，只是无声地失败了:

return
    2 + 2;

FORTRAN并不是一个真正的WTF时刻，而更像是一个“为什么我需要输入所有这些垃圾时刻”

IF(12 .gt. 11) THEN
 // Do some magic
ENDIF

“.gt.”在我玩这门语言的时候把我弄糊涂了，直到我意识到它是“>”符号。哦，我多喜欢不学生物，不用天天接触这些垃圾

其他奇怪的事情:

在c++中，覆盖一个虚方法会隐藏该方法的所有其他重载。在Java中，这种情况不会发生。这很烦人。例如:http://codepad.org/uhvl1nJp

在c++中，如果基类有一个公共虚方法foo()，子类有一个私有方法foo()，这个私有方法会覆盖另一个方法! 这样，只需将子类对象指针强制转换为父类对象指针，就可以在类外部调用私有方法。这不应该是可能的:这违反了封装。新方法不应被视为对旧方法的重写。例如:http://codepad.org/LUGSNPdh

在PHP中，你可以定义函数来接受类型化参数(例如，对象是某个接口/类的子类)，讨厌的是，在这种情况下，你不能使用NULL作为实际的参数值。 例如:http://codepad.org/FphVRZ3S