在Python中:

abs((10+5j)-(25+-5j))

返回~18.03，根据毕达哥拉斯定理，这是点(10,5)和(25,5)之间的距离。之所以会出现这种情况，是因为Python的原生语言支持2+2j形式的复数。由于复数的绝对值形式为a+bj =根号下(a^2+b^2)，我们得到距离，同时从一个复数减去另一个复数，然后应用abs(绝对)函数在它上面。

在Bash中，变量可以显示为标量和数组:

$ a=3
$ echo $a
3
$ echo ${a[@]}    # treat it like an array
3
$ declare -p a    # but it's not
declare -- a="3"
$ a[1]=4          # treat it like an array
$ echo $a         # acts like it's scalar
3
$ echo ${a[@]}    # but it's not
3 4
$ declare -p a
declare -a a='([0]="3" [1]="4")'
$ a=5             # treat it like a scalar
$ echo $a         # acts like it's scalar
5
$ echo ${a[@]}    # but it's not
5 4
$ declare -p a
declare -a a='([0]="5" [1]="4")'

KSH做同样的事情，但是使用排版而不是声明。

当你在zsh中这样做时，你得到的是子字符串赋值而不是数组:

$ a=3
$ a[2]=4          # zsh is one-indexed by default
$ echo $a
34
$ a[3]=567
$ echo $a
34567
$ a[3]=9
$ echo $a
34967
$ a[3]=123         # here it overwrites the first character, but inserts the others
$ echo $a
3412367
$ a=(1 2 3)
$ echo $a
1 2 3              # it's an array without needing to use ${a[@]} (but it will work)
$ a[2]=99          # what about assignments?
$ echo $a
1 99 3

Go的伪常数Iota:

type ByteSize float64
const (
_ = iota;   // ignore first value by assigning to blank identifier
KB ByteSize = 1<<(10*iota); MB; GB; TB; PB; YB;
)   

SQLite允许你用你想要的任何数据类型来声明列。它查找一些特定的子字符串(“INT”、“REAL”、“TEXT”等)来确定相关性。

这使得它可以在你的类型声明:

CREATE TABLE Quirks (
   X    FLOATING POINT,  -- = INTEGER affinity because of the "INT"
   Y    STRING,          -- = NUMERIC affinity
);

在Java中:

int[] numbers() {
  return null;
}

可以写成:

int numbers() [] {
  return null;
}

在Python中:

>>> a[0] = "hello"
NameError: name 'a' is not defined
>>> a[0:] = "hello"
NameError: name 'a' is not defined
>>> a = []
>>> a[0] = "hello"
IndexError: list assignment index out of range
>>> a[0:] = "hello"
>>> a
['h', 'e', 'l', 'l', 'o']

这些切片分配也会给出相同的结果:

a[:] = "hello"
a[42:] = "hello"
a[:33] = "hello"