我如何以编程方式设置一个故事板的InitialViewController ?我想打开我的故事板到一个不同的视图这取决于不同的启动条件。
当前回答
Swift 5或以上版本#创建路由视图控制器 如果你使用xcode 11或以上版本,首先初始化var window: UIWindow?在AppDelegate
let rootVC = mainStoryboard.instantiateViewController(withIdentifier: "YOURCONTROLLER") as! YOURCONTROLLER
navigationController.setNavigationBarHidden(true, animated: true)
UIApplication.shared.windows.first?.rootViewController = UINavigationController.init(rootViewController: rootVC)
UIApplication.shared.windows.first?.makeKeyAndVisible()
其他回答
在AppDelegate.swift中,你可以添加以下代码:
let sb = UIStoryboard(name: "Main", bundle: nil)
let vc = sb.instantiateViewController(withIdentifier: "YourViewController_StorboardID")
self.window?.rootViewController = vc
self.window?.makeKeyAndVisible()
当然,你需要实现你的逻辑,基于什么标准你将选择一个合适的视图控制器。
另外,不要忘记添加一个标识(select storyboard -> Controller Scene -> Show the identity inspector -> assign StorboardID)。
谢谢在AppDelegate中修改如下:
func application(application: UIApplication, didFinishLaunchingWithOptions launchOptions: [NSObject: AnyObject]?) -> Bool {
//Some code to check value of pins
if pins! == "Verified"{
print(pins)
self.window = UIWindow(frame: UIScreen.mainScreen().bounds)
let mainStoryboard: UIStoryboard = UIStoryboard(name: "HomePage", bundle: nil)
let exampleViewController: UINavigationController = mainStoryboard.instantiateViewControllerWithIdentifier("SBHP") as! UINavigationController
self.window?.rootViewController = exampleViewController
self.window?.makeKeyAndVisible()
}else{
print(pins)
self.window = UIWindow(frame: UIScreen.mainScreen().bounds)
let mainStoryboard: UIStoryboard = UIStoryboard(name: "Main", bundle: nil)
let exampleViewController: UINavigationController = mainStoryboard.instantiateViewControllerWithIdentifier("SBUser") as! UINavigationController
self.window?.rootViewController = exampleViewController
self.window?.makeKeyAndVisible()
}
如果你在iOS 13+中使用场景委托:
在你的信息中确认。Plist文件你发现行在:
Application Scene Manifest > Scene Configuration > Application Session Role > Item 0
并在那里删除对Main Storyboard的引用。否则,您将得到关于从storyboard实例化失败的相同警告。
同样,将代码从应用程序委托移动到场景委托方法scene(_:willConnectTo:options:),因为这是现在处理生命周期事件的地方。
使用Swift 3和Swift 4避免强制铸造的另一个解决方案是这样的
func application(_ application: UIApplication, didFinishLaunchingWithOptions launchOptions: [UIApplicationLaunchOptionsKey: Any]?) -> Bool {
self.window = UIWindow(frame: UIScreen.main.bounds)
let storyboard = UIStoryboard(name: "Main", bundle: nil)
guard let viewController = storyboard.instantiateViewController(withIdentifier: "YourViewController") as? YourViewController else {
return false
}
self.window?.rootViewController = viewController
self.window?.makeKeyAndVisible()
return true
}
下面是使用UINavigationController
func application(_ application: UIApplication, didFinishLaunchingWithOptions launchOptions: [UIApplicationLaunchOptionsKey: Any]?) -> Bool {
self.window = UIWindow(frame: UIScreen.main.bounds)
let storyboard = UIStoryboard(name: "Main", bundle: nil)
guard let viewController = storyboard.instantiateViewController(withIdentifier: "YourViewController") as? YourViewController else {
return false
}
let navigationController = UINavigationController(rootViewController: viewController)
self.window?.rootViewController = navigationController
self.window?.makeKeyAndVisible()
return true
}
Swift 4, Xcode 9
在AppDelegate.swift文件中
func application(_ application: UIApplication, didFinishLaunchingWithOptions launchOptions: [UIApplicationLaunchOptionsKey: Any]?) -> Bool {
let storyboard = UIStoryboard(name: "Main", bundle: nil)
let firstVC = storyboard.instantiateViewController(withIdentifier: "firstViewController") as! firstViewController
self.window?.rootViewController = firstVC
}
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