问题是如何将JavaScript Date格式化为一个字符串,声明时间经过,类似于您在Stack Overflow上看到的时间显示方式。

e.g.

1分钟前 1小时前 1天前 1个月前 一年前


当前回答

 I achieve this by following method

   timeAgo = (date) => {
            var ms = (new Date()).getTime() - date.getTime();
            var seconds = Math.floor(ms / 1000);
            var minutes = Math.floor(seconds / 60);
        var hours = Math.floor(minutes / 60);
        var days = Math.floor(hours / 24);
        var months = Math.floor(days / 30);
        var years = Math.floor(months / 12);
    
        if (ms === 0) {
            return 'Just now';
        } if (seconds < 60) {
            return seconds + ' seconds Ago';
        } if (minutes < 60) {
            return minutes + ' minutes Ago';
        } if (hours < 24) {
            return hours + ' hours Ago';
        } if (days < 30) {
            return days + ' days Ago';
        } if (months < 12) {
            return months + ' months Ago';
        } else {
            return years + ' years Ago';
        }
    
    }
    
        console.log(timeAgo(new Date()));
        console.log(timeAgo(new Date('Jun 27 2020 10:12:19')));
        console.log(timeAgo(new Date('Jun 27 2020 00:12:19')));
        console.log(timeAgo(new Date('May 28 2020 13:12:19')));
        console.log(timeAgo(new Date('May 28 2017 13:12:19')));

其他回答

将上面的函数更改为

function timeSince(date) {

    var seconds = Math.floor(((new Date().getTime()/1000) - date)),
    interval = Math.floor(seconds / 31536000);

    if (interval > 1) return interval + "y";

    interval = Math.floor(seconds / 2592000);
    if (interval > 1) return interval + "m";

    interval = Math.floor(seconds / 86400);
    if (interval >= 1) return interval + "d";

    interval = Math.floor(seconds / 3600);
    if (interval >= 1) return interval + "h";

    interval = Math.floor(seconds / 60);
    if (interval > 1) return interval + "m ";

    return Math.floor(seconds) + "s";
}

否则它会显示“75分钟”(介于1到2小时之间)。它现在还假定输入日期是Unix时间戳。

您可能需要查看humanized_time_span: https://github.com/layam/js_humanized_time_span

它与框架无关,并且完全可定制。

只需下载/包含脚本,然后你可以这样做:

humanized_time_span("2011-05-11 12:00:00")  
   => '3 hours ago'

humanized_time_span("2011-05-11 12:00:00", "2011-05-11 16:00:00)  
   => '4 hours ago'

甚至是这样:

var custom_date_formats = {
  past: [
    { ceiling: 60, text: "less than a minute ago" },
    { ceiling: 86400, text: "$hours hours, $minutes minutes and $seconds seconds ago" },
    { ceiling: null, text: "$years years ago" }
  ],
  future: [
    { ceiling: 60, text: "in less than a minute" },
    { ceiling: 86400, text: "in $hours hours, $minutes minutes and $seconds seconds time" },
    { ceiling: null, text: "in $years years" }
  ]
}

humanized_time_span("2010/09/10 10:00:00", "2010/09/10 10:00:05", custom_date_formats) 
  => "less than a minute ago"

更多信息请阅读文档。

我使用这个包:javascript-time-ago

设置TimeAgo 导入TimeAgo 从javascript-time-ago/locale/en.json导入en TimeAgo.addDefaultLocale (en) 写一个函数 // twitter-now是twitter风格。查看文档以获得更多选项 const clockToDateString = (timestamp) => timeAgo。format(new Date(timestamp.toNumber() * 1000), 'twitter-now') 在dom中使用它 < div > {clockToDateString (post.postTime)} < / div >

如果你已经在使用date-fns,你可以使用内置的formatDistance(以前是distanceInWords):

const date1 = new Date(2014, 6, 2);
const date2 = new Date(2015, 0, 1);
const options = { addSuffix: true }
const result = formatDistance(date1, date2, options);
//=> '6 months ago'

我的尝试是基于其他的答案。

function timeSince(date) {
    let minute = 60;
    let hour   = minute * 60;
    let day    = hour   * 24;
    let month  = day    * 30;
    let year   = day    * 365;

    let suffix = ' ago';

    let elapsed = Math.floor((Date.now() - date) / 1000);

    if (elapsed < minute) {
        return 'just now';
    }

    // get an array in the form of [number, string]
    let a = elapsed < hour  && [Math.floor(elapsed / minute), 'minute'] ||
            elapsed < day   && [Math.floor(elapsed / hour), 'hour']     ||
            elapsed < month && [Math.floor(elapsed / day), 'day']       ||
            elapsed < year  && [Math.floor(elapsed / month), 'month']   ||
            [Math.floor(elapsed / year), 'year'];

    // pluralise and append suffix
    return a[0] + ' ' + a[1] + (a[0] === 1 ? '' : 's') + suffix;
}