问题是如何将JavaScript Date格式化为一个字符串,声明时间经过,类似于您在Stack Overflow上看到的时间显示方式。
e.g.
1分钟前 1小时前 1天前 1个月前 一年前
问题是如何将JavaScript Date格式化为一个字符串,声明时间经过,类似于您在Stack Overflow上看到的时间显示方式。
e.g.
1分钟前 1小时前 1天前 1个月前 一年前
当前回答
function calDateAgo(dString=null){
//var dString = "2021-04-1 12:00:00";
var d1 = new Date(dString);
var d2 = new Date();
var t2 = d2.getTime();
var t1 = d1.getTime();
var d1Y = d1.getFullYear();
var d2Y = d2.getFullYear();
var d1M = d1.getMonth();
var d2M = d2.getMonth();
var time_obj = {};
time_obj.year = d2.getFullYear()-d1.getFullYear();
time_obj.month = (d2M+12*d2Y)-(d1M+12*d1Y);
time_obj.week = parseInt((t2-t1)/(24*3600*1000*7));
time_obj.day = parseInt((t2-t1)/(24*3600*1000));
time_obj.hour = parseInt((t2-t1)/(3600*1000));
time_obj.minute = parseInt((t2-t1)/(60*1000));
time_obj.second = parseInt((t2-t1)/(1000));
for (const obj_key in time_obj) {
if(time_obj[obj_key] == 0){
delete time_obj[obj_key];
}
}
var ago_text = 'just now';
if(typeof Object.keys(time_obj)[0] != 'undefined'){
var time_key = Object.keys(time_obj)[0];
var time_val = time_obj[Object.keys(time_obj)[0]];
time_key += (time_val > 1) ? 's':'';
ago_text = time_val+' '+time_key+' ago';
}
return ago_text;
}
其他回答
在这种情况下可能有点过头了,但如果有机会,moment.js真的很棒!
js是一个javascript datetime库,在这种情况下使用它,你需要做:
moment(yourdate).fromNow()
http://momentjs.com/docs/#/displaying/fromnow/
2018附录:Luxon是一个新的现代图书馆,可能值得一看!
2022年附录:Day.js是一个较新的库,比Luxon轻80%左右,具有类似的功能。
从现在开始,Unix时间戳参数
function timeSince(ts){
now = new Date();
ts = new Date(ts*1000);
var delta = now.getTime() - ts.getTime();
delta = delta/1000; //us to s
var ps, pm, ph, pd, min, hou, sec, days;
if(delta<=59){
ps = (delta>1) ? "s": "";
return delta+" second"+ps
}
if(delta>=60 && delta<=3599){
min = Math.floor(delta/60);
sec = delta-(min*60);
pm = (min>1) ? "s": "";
ps = (sec>1) ? "s": "";
return min+" minute"+pm+" "+sec+" second"+ps;
}
if(delta>=3600 && delta<=86399){
hou = Math.floor(delta/3600);
min = Math.floor((delta-(hou*3600))/60);
ph = (hou>1) ? "s": "";
pm = (min>1) ? "s": "";
return hou+" hour"+ph+" "+min+" minute"+pm;
}
if(delta>=86400){
days = Math.floor(delta/86400);
hou = Math.floor((delta-(days*86400))/60/60);
pd = (days>1) ? "s": "";
ph = (hou>1) ? "s": "";
return days+" day"+pd+" "+hou+" hour"+ph;
}
}
这些答案大多不能解释复数(例如:复数)。当我们想要“1分钟前”时,用“1分钟前”)
const MINUTE = 60;
const HOUR = MINUTE * 60;
const DAY = HOUR * 24;
const WEEK = DAY * 7;
const MONTH = DAY * 30;
const YEAR = DAY * 365;
function getTimeAgo(date) {
const secondsAgo = Math.round((Date.now() - Number(date)) / 1000);
if (secondsAgo < MINUTE) {
return secondsAgo + ` second${secondsAgo !== 1 ? "s" : ""} ago`;
}
let divisor;
let unit = "";
if (secondsAgo < HOUR) {
[divisor, unit] = [MINUTE, "minute"];
} else if (secondsAgo < DAY) {
[divisor, unit] = [HOUR, "hour"];
} else if (secondsAgo < WEEK) {
[divisor, unit] = [DAY, "day"];
} else if (secondsAgo < MONTH) {
[divisor, unit] = [WEEK, "week"];
} else if (secondsAgo < YEAR) {
[divisor, unit] = [MONTH, "month"];
} else {
[divisor, unit] = [YEAR, "year"];
}
const count = Math.floor(secondsAgo / divisor);
return `${count} ${unit}${count > 1 ? "s" : ""} ago`;
}
然后你可以这样使用它:
const date = new Date();
console.log(getTimeAgo(date));
// 1 second ago
// 2 seconds ago
// 1 minute ago
// 2 minutes ago
// ...
以上答案适用于旧的java脚本。但它在新的EC6 JavaScript或TypeScript上运行得不太好。下面是一个非常简短和简单的函数,用于最新的JavaScript, TypeScript, AngularJs, ReactJs和NodeJs,根据给定的日期和时间返回时间。
public timeAgo(date) {
var seconds = Math.floor((new Date().getTime() - new Date(date).getTime()) / 1000);
var interval = seconds / 31536000;
if (interval > 1) return Math.floor(interval) + " years";
interval = seconds / 2592000;
if (interval > 1) return Math.floor(interval) + " months";
interval = seconds / 86400;
if (interval > 1) return Math.floor(interval) + " days";
interval = seconds / 3600;
if (interval > 1) return Math.floor(interval) + " hours";
interval = seconds / 60;
if (interval > 1) return Math.floor(interval) + " minutes";
return Math.floor(seconds) + " seconds";
}
console.log(timeAgo('2022-08-12 20:50:20'));
// 2 hours ago, as per the given date time string.
I achieve this by following method
timeAgo = (date) => {
var ms = (new Date()).getTime() - date.getTime();
var seconds = Math.floor(ms / 1000);
var minutes = Math.floor(seconds / 60);
var hours = Math.floor(minutes / 60);
var days = Math.floor(hours / 24);
var months = Math.floor(days / 30);
var years = Math.floor(months / 12);
if (ms === 0) {
return 'Just now';
} if (seconds < 60) {
return seconds + ' seconds Ago';
} if (minutes < 60) {
return minutes + ' minutes Ago';
} if (hours < 24) {
return hours + ' hours Ago';
} if (days < 30) {
return days + ' days Ago';
} if (months < 12) {
return months + ' months Ago';
} else {
return years + ' years Ago';
}
}
console.log(timeAgo(new Date()));
console.log(timeAgo(new Date('Jun 27 2020 10:12:19')));
console.log(timeAgo(new Date('Jun 27 2020 00:12:19')));
console.log(timeAgo(new Date('May 28 2020 13:12:19')));
console.log(timeAgo(new Date('May 28 2017 13:12:19')));