问题是如何将JavaScript Date格式化为一个字符串,声明时间经过,类似于您在Stack Overflow上看到的时间显示方式。
e.g.
1分钟前 1小时前 1天前 1个月前 一年前
问题是如何将JavaScript Date格式化为一个字符串,声明时间经过,类似于您在Stack Overflow上看到的时间显示方式。
e.g.
1分钟前 1小时前 1天前 1个月前 一年前
当前回答
function calDateAgo(dString=null){
//var dString = "2021-04-1 12:00:00";
var d1 = new Date(dString);
var d2 = new Date();
var t2 = d2.getTime();
var t1 = d1.getTime();
var d1Y = d1.getFullYear();
var d2Y = d2.getFullYear();
var d1M = d1.getMonth();
var d2M = d2.getMonth();
var time_obj = {};
time_obj.year = d2.getFullYear()-d1.getFullYear();
time_obj.month = (d2M+12*d2Y)-(d1M+12*d1Y);
time_obj.week = parseInt((t2-t1)/(24*3600*1000*7));
time_obj.day = parseInt((t2-t1)/(24*3600*1000));
time_obj.hour = parseInt((t2-t1)/(3600*1000));
time_obj.minute = parseInt((t2-t1)/(60*1000));
time_obj.second = parseInt((t2-t1)/(1000));
for (const obj_key in time_obj) {
if(time_obj[obj_key] == 0){
delete time_obj[obj_key];
}
}
var ago_text = 'just now';
if(typeof Object.keys(time_obj)[0] != 'undefined'){
var time_key = Object.keys(time_obj)[0];
var time_val = time_obj[Object.keys(time_obj)[0]];
time_key += (time_val > 1) ? 's':'';
ago_text = time_val+' '+time_key+' ago';
}
return ago_text;
}
其他回答
在这种情况下可能有点过头了,但如果有机会,moment.js真的很棒!
js是一个javascript datetime库,在这种情况下使用它,你需要做:
moment(yourdate).fromNow()
http://momentjs.com/docs/#/displaying/fromnow/
2018附录:Luxon是一个新的现代图书馆,可能值得一看!
2022年附录:Day.js是一个较新的库,比Luxon轻80%左右,具有类似的功能。
以下是对Sky Sander的解决方案的轻微修改,允许日期作为字符串输入,并能够显示像“1分钟”而不是“73秒”这样的跨度
var timeSince = function(date) { if (typeof date !== 'object') { date = new Date(date); } var seconds = Math.floor((new Date() - date) / 1000); var intervalType; var interval = Math.floor(seconds / 31536000); if (interval >= 1) { intervalType = 'year'; } else { interval = Math.floor(seconds / 2592000); if (interval >= 1) { intervalType = 'month'; } else { interval = Math.floor(seconds / 86400); if (interval >= 1) { intervalType = 'day'; } else { interval = Math.floor(seconds / 3600); if (interval >= 1) { intervalType = "hour"; } else { interval = Math.floor(seconds / 60); if (interval >= 1) { intervalType = "minute"; } else { interval = seconds; intervalType = "second"; } } } } } if (interval > 1 || interval === 0) { intervalType += 's'; } return interval + ' ' + intervalType; }; var aDay = 24 * 60 * 60 * 1000; console.log(timeSince(new Date(Date.now() - aDay))); console.log(timeSince(new Date(Date.now() - aDay * 2)));
function timeago(date) {
var seconds = Math.floor((new Date() - date) / 1000);
if(Math.round(seconds/(60*60*24*365.25)) >= 2) return Math.round(seconds/(60*60*24*365.25)) + " years ago";
else if(Math.round(seconds/(60*60*24*365.25)) >= 1) return "1 year ago";
else if(Math.round(seconds/(60*60*24*30.4)) >= 2) return Math.round(seconds/(60*60*24*30.4)) + " months ago";
else if(Math.round(seconds/(60*60*24*30.4)) >= 1) return "1 month ago";
else if(Math.round(seconds/(60*60*24*7)) >= 2) return Math.round(seconds/(60*60*24*7)) + " weeks ago";
else if(Math.round(seconds/(60*60*24*7)) >= 1) return "1 week ago";
else if(Math.round(seconds/(60*60*24)) >= 2) return Math.round(seconds/(60*60*24)) + " days ago";
else if(Math.round(seconds/(60*60*24)) >= 1) return "1 day ago";
else if(Math.round(seconds/(60*60)) >= 2) return Math.round(seconds/(60*60)) + " hours ago";
else if(Math.round(seconds/(60*60)) >= 1) return "1 hour ago";
else if(Math.round(seconds/60) >= 2) return Math.round(seconds/60) + " minutes ago";
else if(Math.round(seconds/60) >= 1) return "1 minute ago";
else if(seconds >= 2)return seconds + " seconds ago";
else return seconds + "1 second ago";
}
由@user1012181提供的ES6版本代码:
const epochs = [
['year', 31536000],
['month', 2592000],
['day', 86400],
['hour', 3600],
['minute', 60],
['second', 1]
];
const getDuration = (timeAgoInSeconds) => {
for (let [name, seconds] of epochs) {
const interval = Math.floor(timeAgoInSeconds / seconds);
if (interval >= 1) {
return {
interval: interval,
epoch: name
};
}
}
};
const timeAgo = (date) => {
const timeAgoInSeconds = Math.floor((new Date() - new Date(date)) / 1000);
const {interval, epoch} = getDuration(timeAgoInSeconds);
const suffix = interval === 1 ? '' : 's';
return `${interval} ${epoch}${suffix} ago`;
};
由@ibe-vanmeenen编辑建议。(谢谢!)
简单易读版本:
const relativeTimePeriods = [
[31536000, 'year'],
[2419200, 'month'],
[604800, 'week'],
[86400, 'day'],
[3600, 'hour'],
[60, 'minute'],
[1, 'second']
];
function relativeTime(date, isUtc=true) {
if (!(date instanceof Date)) date = new Date(date * 1000);
const seconds = (new Date() - date) / 1000;
for (let [secondsPer, name] of relativeTimePeriods) {
if (seconds >= secondsPer) {
const amount = Math.floor(seconds / secondsPer);
return `${amount} ${name}${amount ? 's' : ''}s ago`;
}
}
return 'Just now';
}