问题是如何将JavaScript Date格式化为一个字符串,声明时间经过,类似于您在Stack Overflow上看到的时间显示方式。
e.g.
1分钟前 1小时前 1天前 1个月前 一年前
问题是如何将JavaScript Date格式化为一个字符串,声明时间经过,类似于您在Stack Overflow上看到的时间显示方式。
e.g.
1分钟前 1小时前 1天前 1个月前 一年前
当前回答
function dateToHowManyAgo(stringDate){
var currDate = new Date();
var diffMs=currDate.getTime() - new Date(stringDate).getTime();
var sec=diffMs/1000;
if(sec<60)
return parseInt(sec)+' second'+(parseInt(sec)>1?'s':'')+' ago';
var min=sec/60;
if(min<60)
return parseInt(min)+' minute'+(parseInt(min)>1?'s':'')+' ago';
var h=min/60;
if(h<24)
return parseInt(h)+' hour'+(parseInt(h)>1?'s':'')+' ago';
var d=h/24;
if(d<30)
return parseInt(d)+' day'+(parseInt(d)>1?'s':'')+' ago';
var m=d/30;
if(m<12)
return parseInt(m)+' month'+(parseInt(m)>1?'s':'')+' ago';
var y=m/12;
return parseInt(y)+' year'+(parseInt(y)>1?'s':'')+' ago';
}
console.log(dateToHowManyAgo('2019-11-07 19:17:06'));
其他回答
function timeSince(date) { var seconds = Math.floor((new Date() - date) / 1000); var interval = seconds / 31536000; if (interval > 1) { return Math.floor(interval) + " years"; } interval = seconds / 2592000; if (interval > 1) { return Math.floor(interval) + " months"; } interval = seconds / 86400; if (interval > 1) { return Math.floor(interval) + " days"; } interval = seconds / 3600; if (interval > 1) { return Math.floor(interval) + " hours"; } interval = seconds / 60; if (interval > 1) { return Math.floor(interval) + " minutes"; } return Math.floor(seconds) + " seconds"; } var aDay = 24*60*60*1000; console.log(timeSince(new Date(Date.now()-aDay))); console.log(timeSince(new Date(Date.now()-aDay*2)));
我还没有检查(虽然这并不难),但我认为Stack Exchange站点使用jquery。Timeago插件来创建这些时间字符串。
这个插件使用起来很简单,而且很干净,还能自动更新。
下面是一个简单的例子(来自插件的主页):
First, load jQuery and the plugin: <script src="jquery.min.js" type="text/javascript"></script> <script src="jquery.timeago.js" type="text/javascript"></script> Now, let's attach it to your timestamps on DOM ready: jQuery(document).ready(function() { jQuery("abbr.timeago").timeago(); }); This will turn all abbr elements with a class of timeago and an ISO 8601 timestamp in the title: <abbr class="timeago" title="2008-07-17T09:24:17Z">July 17, 2008</abbr> into something like this: <abbr class="timeago" title="July 17, 2008">about a year ago</abbr> which yields: about a year ago. As time passes, the timestamps will automatically update.
const createdAt = moment(created_at).fromNow()
量身定制的解决方案
const duration = moment.duration(moment().diff(moment(created_at)))
const createdAt = duration.as('week') >= 1
? `${Math.floor(duration.as('week'))} week(s)`
: duration.as('day') >= 1
? `${Math.floor(duration.as('day'))} day(s)`
: duration.as('hour') >= 1
? `${Math.floor(duration.as('hour'))} hour(s)`
: `${Math.floor(duration.as('minute'))} minute(s)`
我修改了Sky Sanders的版本。Math.floor(…)操作在if块中计算
var timeSince = function(date) {
var seconds = Math.floor((new Date() - date) / 1000);
var months = ["January", "February", "March", "April", "May", "June", "July", "August", "September", "October", "November", "December"];
if (seconds < 5){
return "just now";
}else if (seconds < 60){
return seconds + " seconds ago";
}
else if (seconds < 3600) {
minutes = Math.floor(seconds/60)
if(minutes > 1)
return minutes + " minutes ago";
else
return "1 minute ago";
}
else if (seconds < 86400) {
hours = Math.floor(seconds/3600)
if(hours > 1)
return hours + " hours ago";
else
return "1 hour ago";
}
//2 days and no more
else if (seconds < 172800) {
days = Math.floor(seconds/86400)
if(days > 1)
return days + " days ago";
else
return "1 day ago";
}
else{
//return new Date(time).toLocaleDateString();
return date.getDate().toString() + " " + months[date.getMonth()] + ", " + date.getFullYear();
}
}
简单易读版本:
const relativeTimePeriods = [
[31536000, 'year'],
[2419200, 'month'],
[604800, 'week'],
[86400, 'day'],
[3600, 'hour'],
[60, 'minute'],
[1, 'second']
];
function relativeTime(date, isUtc=true) {
if (!(date instanceof Date)) date = new Date(date * 1000);
const seconds = (new Date() - date) / 1000;
for (let [secondsPer, name] of relativeTimePeriods) {
if (seconds >= secondsPer) {
const amount = Math.floor(seconds / secondsPer);
return `${amount} ${name}${amount ? 's' : ''}s ago`;
}
}
return 'Just now';
}