问题是如何将JavaScript Date格式化为一个字符串,声明时间经过,类似于您在Stack Overflow上看到的时间显示方式。
e.g.
1分钟前 1小时前 1天前 1个月前 一年前
问题是如何将JavaScript Date格式化为一个字符串,声明时间经过,类似于您在Stack Overflow上看到的时间显示方式。
e.g.
1分钟前 1小时前 1天前 1个月前 一年前
当前回答
function dateToHowManyAgo(stringDate){
var currDate = new Date();
var diffMs=currDate.getTime() - new Date(stringDate).getTime();
var sec=diffMs/1000;
if(sec<60)
return parseInt(sec)+' second'+(parseInt(sec)>1?'s':'')+' ago';
var min=sec/60;
if(min<60)
return parseInt(min)+' minute'+(parseInt(min)>1?'s':'')+' ago';
var h=min/60;
if(h<24)
return parseInt(h)+' hour'+(parseInt(h)>1?'s':'')+' ago';
var d=h/24;
if(d<30)
return parseInt(d)+' day'+(parseInt(d)>1?'s':'')+' ago';
var m=d/30;
if(m<12)
return parseInt(m)+' month'+(parseInt(m)>1?'s':'')+' ago';
var y=m/12;
return parseInt(y)+' year'+(parseInt(y)>1?'s':'')+' ago';
}
console.log(dateToHowManyAgo('2019-11-07 19:17:06'));
其他回答
以上答案适用于旧的java脚本。但它在新的EC6 JavaScript或TypeScript上运行得不太好。下面是一个非常简短和简单的函数,用于最新的JavaScript, TypeScript, AngularJs, ReactJs和NodeJs,根据给定的日期和时间返回时间。
public timeAgo(date) {
var seconds = Math.floor((new Date().getTime() - new Date(date).getTime()) / 1000);
var interval = seconds / 31536000;
if (interval > 1) return Math.floor(interval) + " years";
interval = seconds / 2592000;
if (interval > 1) return Math.floor(interval) + " months";
interval = seconds / 86400;
if (interval > 1) return Math.floor(interval) + " days";
interval = seconds / 3600;
if (interval > 1) return Math.floor(interval) + " hours";
interval = seconds / 60;
if (interval > 1) return Math.floor(interval) + " minutes";
return Math.floor(seconds) + " seconds";
}
console.log(timeAgo('2022-08-12 20:50:20'));
// 2 hours ago, as per the given date time string.
下面是我所做的(对象返回时间单位及其值):
function timeSince(post_date, reference) { var reference = reference ? new Date(reference) : new Date(), diff = reference - new Date(post_date + ' GMT-0000'), date = new Date(diff), object = { unit: null, value: null }; if (diff < 86400000) { var secs = date.getSeconds(), mins = date.getMinutes(), hours = date.getHours(), array = [ ['second', secs], ['minute', mins], ['hour', hours] ]; } else { var days = date.getDate(), weeks = Math.floor(days / 7), months = date.getMonth(), years = date.getFullYear() - 1970, array = [ ['day', days], ['week', weeks], ['month', months], ['year', years] ]; } for (var i = 0; i < array.length; i++) { array[i][0] += array[i][1] != 1 ? 's' : ''; object.unit = array[i][1] >= 1 ? array[i][0] : object.unit; object.value = array[i][1] >= 1 ? array[i][1] : object.value; } return object; }
const timeHandler = (time: any) => {
var a = moment(); //now
var b = moment.utc(time);
const sec = a.diff(b, 'seconds');
const minuts = a.diff(b, 'minutes');
const hours = a.diff(b, 'hours');
const days = a.diff(b, 'days');
const weeks = a.diff(b, 'weeks');
return weeks == 0
? days == 0
? hours == 0
? minuts == 0
? sec >= 0 && `${sec}s ago`
: `${minuts}m ago`
: `${hours}h ago`
: `${days}d ago`
: `${weeks}w ago`;
};
console.log(timeHandler('2022-11-11T12:11:06.6103808'))
由@user1012181提供的ES6版本代码:
const epochs = [
['year', 31536000],
['month', 2592000],
['day', 86400],
['hour', 3600],
['minute', 60],
['second', 1]
];
const getDuration = (timeAgoInSeconds) => {
for (let [name, seconds] of epochs) {
const interval = Math.floor(timeAgoInSeconds / seconds);
if (interval >= 1) {
return {
interval: interval,
epoch: name
};
}
}
};
const timeAgo = (date) => {
const timeAgoInSeconds = Math.floor((new Date() - new Date(date)) / 1000);
const {interval, epoch} = getDuration(timeAgoInSeconds);
const suffix = interval === 1 ? '' : 's';
return `${interval} ${epoch}${suffix} ago`;
};
由@ibe-vanmeenen编辑建议。(谢谢!)
这将显示你过去和以前的时间格式,如“2天前”“从现在开始10分钟”,你可以传递给它一个日期对象,数字时间戳或日期字符串
function time_ago(time) { switch (typeof time) { case 'number': break; case 'string': time = +new Date(time); break; case 'object': if (time.constructor === Date) time = time.getTime(); break; default: time = +new Date(); } var time_formats = [ [60, 'seconds', 1], // 60 [120, '1 minute ago', '1 minute from now'], // 60*2 [3600, 'minutes', 60], // 60*60, 60 [7200, '1 hour ago', '1 hour from now'], // 60*60*2 [86400, 'hours', 3600], // 60*60*24, 60*60 [172800, 'Yesterday', 'Tomorrow'], // 60*60*24*2 [604800, 'days', 86400], // 60*60*24*7, 60*60*24 [1209600, 'Last week', 'Next week'], // 60*60*24*7*4*2 [2419200, 'weeks', 604800], // 60*60*24*7*4, 60*60*24*7 [4838400, 'Last month', 'Next month'], // 60*60*24*7*4*2 [29030400, 'months', 2419200], // 60*60*24*7*4*12, 60*60*24*7*4 [58060800, 'Last year', 'Next year'], // 60*60*24*7*4*12*2 [2903040000, 'years', 29030400], // 60*60*24*7*4*12*100, 60*60*24*7*4*12 [5806080000, 'Last century', 'Next century'], // 60*60*24*7*4*12*100*2 [58060800000, 'centuries', 2903040000] // 60*60*24*7*4*12*100*20, 60*60*24*7*4*12*100 ]; var seconds = (+new Date() - time) / 1000, token = 'ago', list_choice = 1; if (seconds == 0) { return 'Just now' } if (seconds < 0) { seconds = Math.abs(seconds); token = 'from now'; list_choice = 2; } var i = 0, format; while (format = time_formats[i++]) if (seconds < format[0]) { if (typeof format[2] == 'string') return format[list_choice]; else return Math.floor(seconds / format[2]) + ' ' + format[1] + ' ' + token; } return time; } var aDay = 24 * 60 * 60 * 1000; console.log(time_ago(new Date(Date.now() - aDay))); console.log(time_ago(new Date(Date.now() - aDay * 2)));