问题是如何将JavaScript Date格式化为一个字符串，声明时间经过，类似于您在Stack Overflow上看到的时间显示方式。
e.g.
1分钟前 1小时前 1天前 1个月前 一年前
当前回答
以上答案适用于旧的java脚本。但它在新的EC6 JavaScript或TypeScript上运行得不太好。下面是一个非常简短和简单的函数，用于最新的JavaScript, TypeScript, AngularJs, ReactJs和NodeJs，根据给定的日期和时间返回时间。
public timeAgo(date) {
var seconds = Math.floor((new Date().getTime() - new Date(date).getTime()) / 1000);
var interval = seconds / 31536000;
if (interval > 1) return Math.floor(interval) + " years";
interval = seconds / 2592000;
if (interval > 1) return Math.floor(interval) + " months";
interval = seconds / 86400;
if (interval > 1) return Math.floor(interval) + " days";
interval = seconds / 3600;
if (interval > 1) return Math.floor(interval) + " hours";
interval = seconds / 60;
if (interval > 1) return Math.floor(interval) + " minutes";
return Math.floor(seconds) + " seconds";
}
console.log(timeAgo('2022-08-12 20:50:20'));
// 2 hours ago, as per the given date time string.
其他回答
我一直在寻找这个问题的答案，并且几乎实现了其中一个解决方案，但一位同事提醒我检查react-intl库，因为我们已经在使用它了。
所以在解决方案中…在使用react-intl库的情况下，它们有一个<FormattedRelative>组件。
https://github.com/yahoo/react-intl/wiki/Components#formattedrelative
const timeHandler = (time: any) => {
var a = moment(); //now
var b = moment.utc(time);
const sec = a.diff(b, 'seconds');
const minuts = a.diff(b, 'minutes');
const hours = a.diff(b, 'hours');
const days = a.diff(b, 'days');
const weeks = a.diff(b, 'weeks');
return weeks == 0
? days == 0
? hours == 0
? minuts == 0
? sec >= 0 && `${sec}s ago`
: `${minuts}m ago`
: `${hours}h ago`
: `${days}d ago`
: `${weeks}w ago`;
};
console.log(timeHandler('2022-11-11T12:11:06.6103808'))
从现在开始，Unix时间戳参数
function timeSince(ts){
now = new Date();
ts = new Date(ts*1000);
var delta = now.getTime() - ts.getTime();
delta = delta/1000; //us to s
var ps, pm, ph, pd, min, hou, sec, days;
if(delta<=59){
ps = (delta>1) ? "s": "";
return delta+" second"+ps
}
if(delta>=60 && delta<=3599){
min = Math.floor(delta/60);
sec = delta-(min*60);
pm = (min>1) ? "s": "";
ps = (sec>1) ? "s": "";
return min+" minute"+pm+" "+sec+" second"+ps;
}
if(delta>=3600 && delta<=86399){
hou = Math.floor(delta/3600);
min = Math.floor((delta-(hou*3600))/60);
ph = (hou>1) ? "s": "";
pm = (min>1) ? "s": "";
return hou+" hour"+ph+" "+min+" minute"+pm;
}
if(delta>=86400){
days = Math.floor(delta/86400);
hou = Math.floor((delta-(days*86400))/60/60);
pd = (days>1) ? "s": "";
ph = (hou>1) ? "s": "";
return days+" day"+pd+" "+hou+" hour"+ph;
}
}
你可以使用Luxon:
DateTime.toRelative()
https://moment.github.io/luxon/api-docs/index.html#datetimetorelative
这里还有一些例子:
const DateTime = luxon.DateTime; // toRelative console.log(DateTime.now().minus({ seconds: 1 }).toRelative()) // 1 second ago console.log(DateTime.now().minus({ seconds: 10 }).toRelative()) // 10 seconds ago console.log(DateTime.now().minus({ days: 2 }).toRelative()) console.log(DateTime.now().minus({ years: 3 }).toRelative()) console.log(DateTime.now().plus({ years: 3 }).toRelative()) console.log(DateTime.now().plus({ days: 2 }).toRelative()) console.log(DateTime.now().plus({ seconds: 1 }).toRelative()) console.log(DateTime.now().plus({ seconds: 10 }).toRelative()) // toRelativeCalendar console.log(DateTime.now().minus({ seconds: 1 }).toRelativeCalendar()) // today console.log(DateTime.now().minus({ seconds: 10 }).toRelativeCalendar()) // today console.log(DateTime.now().minus({ days: 2 }).toRelativeCalendar()) console.log(DateTime.now().minus({ years: 3 }).toRelativeCalendar()) console.log(DateTime.now().plus({ years: 3 }).toRelativeCalendar()) console.log(DateTime.now().plus({ days: 2 }).toRelativeCalendar()) console.log(DateTime.now().plus({ seconds: 1 }).toRelativeCalendar()) console.log(DateTime.now().plus({ seconds: 10 }).toRelativeCalendar()) <script src="https://moment.github.io/luxon/global/luxon.min.js"></script>
我的解决方案。
(function(global){
const SECOND = 1;
const MINUTE = 60;
const HOUR = 3600;
const DAY = 86400;
const MONTH = 2629746;
const YEAR = 31556952;
const DECADE = 315569520;
global.timeAgo = function(date){
var now = new Date();
var diff = Math.round(( now - date ) / 1000);
var unit = '';
var num = 0;
var plural = false;
switch(true){
case diff <= 0:
return 'just now';
break;
case diff < MINUTE:
num = Math.round(diff / SECOND);
unit = 'sec';
plural = num > 1;
break;
case diff < HOUR:
num = Math.round(diff / MINUTE);
unit = 'min';
plural = num > 1;
break;
case diff < DAY:
num = Math.round(diff / HOUR);
unit = 'hour';
plural = num > 1;
break;
case diff < MONTH:
num = Math.round(diff / DAY);
unit = 'day';
plural = num > 1;
break;
case diff < YEAR:
num = Math.round(diff / MONTH);
unit = 'month';
plural = num > 1;
break;
case diff < DECADE:
num = Math.round(diff / YEAR);
unit = 'year';
plural = num > 1;
break;
default:
num = Math.round(diff / YEAR);
unit = 'year';
plural = num > 1;
}
var str = '';
if(num){
str += `${num} `;
}
str += `${unit}`;
if(plural){
str += 's';
}
str += ' ago';
return str;
}
})(window);
console.log(timeAgo(new Date()));
console.log(timeAgo(new Date('Jun 03 2018 15:12:19 GMT+0300 (FLE Daylight Time)')));
console.log(timeAgo(new Date('Jun 03 2018 13:12:19 GMT+0300 (FLE Daylight Time)')));
console.log(timeAgo(new Date('May 28 2018 13:12:19 GMT+0300 (FLE Daylight Time)')));
console.log(timeAgo(new Date('May 28 2017 13:12:19 GMT+0300 (FLE Daylight Time)')));
console.log(timeAgo(new Date('May 28 2000 13:12:19 GMT+0300 (FLE Daylight Time)')));
console.log(timeAgo(new Date('Sep 10 1994 13:12:19 GMT+0300 (FLE Daylight Time)')));
