以上答案适用于旧的java脚本。但它在新的EC6 JavaScript或TypeScript上运行得不太好。下面是一个非常简短和简单的函数，用于最新的JavaScript, TypeScript, AngularJs, ReactJs和NodeJs，根据给定的日期和时间返回时间。

  public timeAgo(date) {
    var seconds = Math.floor((new Date().getTime() - new Date(date).getTime()) / 1000);
    var interval = seconds / 31536000;
    if (interval > 1) return Math.floor(interval) + " years";
    interval = seconds / 2592000;
    if (interval > 1) return Math.floor(interval) + " months";
    interval = seconds / 86400;
    if (interval > 1) return Math.floor(interval) + " days";
    interval = seconds / 3600;
    if (interval > 1) return Math.floor(interval) + " hours";
    interval = seconds / 60;
    if (interval > 1) return Math.floor(interval) + " minutes";
    return Math.floor(seconds) + " seconds";
  }

console.log(timeAgo('2022-08-12 20:50:20'));
// 2 hours ago, as per the given date time string.

下面是我所做的(对象返回时间单位及其值):

function timeSince(post_date, reference) { var reference = reference ? new Date(reference) : new Date(), diff = reference - new Date(post_date + ' GMT-0000'), date = new Date(diff), object = { unit: null, value: null }; if (diff < 86400000) { var secs = date.getSeconds(), mins = date.getMinutes(), hours = date.getHours(), array = [ ['second', secs], ['minute', mins], ['hour', hours] ]; } else { var days = date.getDate(), weeks = Math.floor(days / 7), months = date.getMonth(), years = date.getFullYear() - 1970, array = [ ['day', days], ['week', weeks], ['month', months], ['year', years] ]; } for (var i = 0; i < array.length; i++) { array[i][0] += array[i][1] != 1 ? 's' : ''; object.unit = array[i][1] >= 1 ? array[i][0] : object.unit; object.value = array[i][1] >= 1 ? array[i][1] : object.value; } return object; }

回答10年的老问题，帮助新人。

我们可以将这个包用于javascript时间之前

 
// Load locale-specific relative date/time formatting rules.
import en from 'javascript-time-ago/locale/en'
 
// Add locale-specific relative date/time formatting rules.
TimeAgo.addLocale(en)
 
// Create relative date/time formatter.
const timeAgo = new TimeAgo('en-US')
 
timeAgo.format(new Date())
// "just now"
 
timeAgo.format(Date.now() - 60 * 1000)
// "a minute ago"
 
timeAgo.format(Date.now() - 2 * 60 * 60 * 1000)
// "2 hours ago"
 
timeAgo.format(Date.now() - 24 * 60 * 60 * 1000)
// "a day ago"

我的尝试是基于其他的答案。

function timeSince(date) {
    let minute = 60;
    let hour   = minute * 60;
    let day    = hour   * 24;
    let month  = day    * 30;
    let year   = day    * 365;

    let suffix = ' ago';

    let elapsed = Math.floor((Date.now() - date) / 1000);

    if (elapsed < minute) {
        return 'just now';
    }

    // get an array in the form of [number, string]
    let a = elapsed < hour  && [Math.floor(elapsed / minute), 'minute'] ||
            elapsed < day   && [Math.floor(elapsed / hour), 'hour']     ||
            elapsed < month && [Math.floor(elapsed / day), 'day']       ||
            elapsed < year  && [Math.floor(elapsed / month), 'month']   ||
            [Math.floor(elapsed / year), 'year'];

    // pluralise and append suffix
    return a[0] + ' ' + a[1] + (a[0] === 1 ? '' : 's') + suffix;
}

我用js和python写了一个，在两个项目中使用，非常漂亮和简单:一个简单的库(少于2kb)，用于*** time ago语句格式化日期。

简单，小巧，易于使用，并且经过良好测试。

NPM安装timeago.js 从timeago.js导入timeago;//或使用脚本标签 使用API格式。

示例:

var timeagoIns  = timeago();
timeagoIns .format('2016-06-12');

你也可以实时渲染。

var timeagoIns = timeago();
timeagoIns.render(document.querySelectorAll('time'));

将上面的函数更改为

function timeSince(date) {

    var seconds = Math.floor(((new Date().getTime()/1000) - date)),
    interval = Math.floor(seconds / 31536000);

    if (interval > 1) return interval + "y";

    interval = Math.floor(seconds / 2592000);
    if (interval > 1) return interval + "m";

    interval = Math.floor(seconds / 86400);
    if (interval >= 1) return interval + "d";

    interval = Math.floor(seconds / 3600);
    if (interval >= 1) return interval + "h";

    interval = Math.floor(seconds / 60);
    if (interval > 1) return interval + "m ";

    return Math.floor(seconds) + "s";
}

否则它会显示“75分钟”(介于1到2小时之间)。它现在还假定输入日期是Unix时间戳。