问题是如何将JavaScript Date格式化为一个字符串,声明时间经过,类似于您在Stack Overflow上看到的时间显示方式。
e.g.
1分钟前 1小时前 1天前 1个月前 一年前
问题是如何将JavaScript Date格式化为一个字符串,声明时间经过,类似于您在Stack Overflow上看到的时间显示方式。
e.g.
1分钟前 1小时前 1天前 1个月前 一年前
当前回答
Lokely使用的一个简短版本:
const intervals = [
{ label: 'year', seconds: 31536000 },
{ label: 'month', seconds: 2592000 },
{ label: 'day', seconds: 86400 },
{ label: 'hour', seconds: 3600 },
{ label: 'minute', seconds: 60 },
{ label: 'second', seconds: 1 }
];
function timeSince(date) {
const seconds = Math.floor((Date.now() - date.getTime()) / 1000);
const interval = intervals.find(i => i.seconds < seconds);
const count = Math.floor(seconds / interval.seconds);
return `${count} ${interval.label}${count !== 1 ? 's' : ''} ago`;
}
其他回答
function timeSince(date) { var seconds = Math.floor((new Date() - date) / 1000); var interval = seconds / 31536000; if (interval > 1) { return Math.floor(interval) + " years"; } interval = seconds / 2592000; if (interval > 1) { return Math.floor(interval) + " months"; } interval = seconds / 86400; if (interval > 1) { return Math.floor(interval) + " days"; } interval = seconds / 3600; if (interval > 1) { return Math.floor(interval) + " hours"; } interval = seconds / 60; if (interval > 1) { return Math.floor(interval) + " minutes"; } return Math.floor(seconds) + " seconds"; } var aDay = 24*60*60*1000; console.log(timeSince(new Date(Date.now()-aDay))); console.log(timeSince(new Date(Date.now()-aDay*2)));
这是对国际的另一种看法。RelativeTimeFormat
支持过去日期和将来日期 同时接受字符串和日期 易于添加自定义范围(编辑范围) 可以很容易地翻译为Intl.RelativeTimeFormat('ua')
console.log(timeAgo('2021-08-09T15:29:01+0000')); function timeAgo(input) { const date = (input instanceof Date) ? input : new Date(input); const formatter = new Intl.RelativeTimeFormat('en'); const ranges = { years: 3600 * 24 * 365, months: 3600 * 24 * 30, weeks: 3600 * 24 * 7, days: 3600 * 24, hours: 3600, minutes: 60, seconds: 1 }; const secondsElapsed = (date.getTime() - Date.now()) / 1000; for (let key in ranges) { if (ranges[key] < Math.abs(secondsElapsed)) { const delta = secondsElapsed / ranges[key]; return formatter.format(Math.round(delta), key); } } }
https://jsfiddle.net/tv9701uf
function calDateAgo(dString=null){
//var dString = "2021-04-1 12:00:00";
var d1 = new Date(dString);
var d2 = new Date();
var t2 = d2.getTime();
var t1 = d1.getTime();
var d1Y = d1.getFullYear();
var d2Y = d2.getFullYear();
var d1M = d1.getMonth();
var d2M = d2.getMonth();
var time_obj = {};
time_obj.year = d2.getFullYear()-d1.getFullYear();
time_obj.month = (d2M+12*d2Y)-(d1M+12*d1Y);
time_obj.week = parseInt((t2-t1)/(24*3600*1000*7));
time_obj.day = parseInt((t2-t1)/(24*3600*1000));
time_obj.hour = parseInt((t2-t1)/(3600*1000));
time_obj.minute = parseInt((t2-t1)/(60*1000));
time_obj.second = parseInt((t2-t1)/(1000));
for (const obj_key in time_obj) {
if(time_obj[obj_key] == 0){
delete time_obj[obj_key];
}
}
var ago_text = 'just now';
if(typeof Object.keys(time_obj)[0] != 'undefined'){
var time_key = Object.keys(time_obj)[0];
var time_val = time_obj[Object.keys(time_obj)[0]];
time_key += (time_val > 1) ? 's':'';
ago_text = time_val+' '+time_key+' ago';
}
return ago_text;
}
以上答案适用于旧的java脚本。但它在新的EC6 JavaScript或TypeScript上运行得不太好。下面是一个非常简短和简单的函数,用于最新的JavaScript, TypeScript, AngularJs, ReactJs和NodeJs,根据给定的日期和时间返回时间。
public timeAgo(date) {
var seconds = Math.floor((new Date().getTime() - new Date(date).getTime()) / 1000);
var interval = seconds / 31536000;
if (interval > 1) return Math.floor(interval) + " years";
interval = seconds / 2592000;
if (interval > 1) return Math.floor(interval) + " months";
interval = seconds / 86400;
if (interval > 1) return Math.floor(interval) + " days";
interval = seconds / 3600;
if (interval > 1) return Math.floor(interval) + " hours";
interval = seconds / 60;
if (interval > 1) return Math.floor(interval) + " minutes";
return Math.floor(seconds) + " seconds";
}
console.log(timeAgo('2022-08-12 20:50:20'));
// 2 hours ago, as per the given date time string.
这是一个简化版的@sky-sanders的回答。
function timeSince(date) {
var seconds = Math.floor((new Date() - date) / 1000);
var divisors = [31536000, 2592000, 86400, 3600, 60, 1]
var description = ["years", "months", "days", "hours", "minutes", "seconds"]
var result = [];
var interval = seconds;
for (i = 0; i < divisors.length; i++) {
interval = Math.floor(seconds / divisors[i])
if (interval > 1) {
result.push(interval + " " + description[i])
}
seconds -= interval * divisors[i]
}
return result.join(" ")
}