问题是如何将JavaScript Date格式化为一个字符串，声明时间经过，类似于您在Stack Overflow上看到的时间显示方式。
e.g.
1分钟前 1小时前 1天前 1个月前 一年前
当前回答
可读性强且跨浏览器兼容的代码:
@Travis给出的
var DURATION_IN_SECONDS = { epochs: ['year', 'month', 'day', 'hour', 'minute'], year: 31536000, month: 2592000, day: 86400, hour: 3600, minute: 60 }; function getDuration(seconds) { var epoch, interval; for (var i = 0; i < DURATION_IN_SECONDS.epochs.length; i++) { epoch = DURATION_IN_SECONDS.epochs[i]; interval = Math.floor(seconds / DURATION_IN_SECONDS[epoch]); if (interval >= 1) { return { interval: interval, epoch: epoch }; } } }; function timeSince(date) { var seconds = Math.floor((new Date() - new Date(date)) / 1000); var duration = getDuration(seconds); var suffix = (duration.interval > 1 || duration.interval === 0) ? 's' : ''; return duration.interval + ' ' + duration.epoch + suffix; }; alert(timeSince('2015-09-17T18:53:23'));
其他回答
我使用这个包:javascript-time-ago
设置TimeAgo 导入TimeAgo 从javascript-time-ago/locale/en.json导入en TimeAgo.addDefaultLocale (en) 写一个函数 // twitter-now是twitter风格。查看文档以获得更多选项 const clockToDateString = (timestamp) => timeAgo。format(new Date(timestamp.toNumber() * 1000)， 'twitter-now') 在dom中使用它 < div > {clockToDateString (post.postTime)} < / div >
这些答案大多不能解释复数(例如:复数)。当我们想要“1分钟前”时，用“1分钟前”)
const MINUTE = 60;
const HOUR = MINUTE * 60;
const DAY = HOUR * 24;
const WEEK = DAY * 7;
const MONTH = DAY * 30;
const YEAR = DAY * 365;
function getTimeAgo(date) {
const secondsAgo = Math.round((Date.now() - Number(date)) / 1000);
if (secondsAgo < MINUTE) {
return secondsAgo + ` second${secondsAgo !== 1 ? "s" : ""} ago`;
}
let divisor;
let unit = "";
if (secondsAgo < HOUR) {
[divisor, unit] = [MINUTE, "minute"];
} else if (secondsAgo < DAY) {
[divisor, unit] = [HOUR, "hour"];
} else if (secondsAgo < WEEK) {
[divisor, unit] = [DAY, "day"];
} else if (secondsAgo < MONTH) {
[divisor, unit] = [WEEK, "week"];
} else if (secondsAgo < YEAR) {
[divisor, unit] = [MONTH, "month"];
} else {
[divisor, unit] = [YEAR, "year"];
}
const count = Math.floor(secondsAgo / divisor);
return `${count} ${unit}${count > 1 ? "s" : ""} ago`;
}
然后你可以这样使用它:
const date = new Date();
console.log(getTimeAgo(date));
// 1 second ago
// 2 seconds ago
// 1 minute ago
// 2 minutes ago
// ...
可读性强且跨浏览器兼容的代码:
@Travis给出的
var DURATION_IN_SECONDS = { epochs: ['year', 'month', 'day', 'hour', 'minute'], year: 31536000, month: 2592000, day: 86400, hour: 3600, minute: 60 }; function getDuration(seconds) { var epoch, interval; for (var i = 0; i < DURATION_IN_SECONDS.epochs.length; i++) { epoch = DURATION_IN_SECONDS.epochs[i]; interval = Math.floor(seconds / DURATION_IN_SECONDS[epoch]); if (interval >= 1) { return { interval: interval, epoch: epoch }; } } }; function timeSince(date) { var seconds = Math.floor((new Date() - new Date(date)) / 1000); var duration = getDuration(seconds); var suffix = (duration.interval > 1 || duration.interval === 0) ? 's' : ''; return duration.interval + ' ' + duration.epoch + suffix; }; alert(timeSince('2015-09-17T18:53:23'));
我的尝试是基于其他的答案。
function timeSince(date) {
let minute = 60;
let hour = minute * 60;
let day = hour * 24;
let month = day * 30;
let year = day * 365;
let suffix = ' ago';
let elapsed = Math.floor((Date.now() - date) / 1000);
if (elapsed < minute) {
return 'just now';
}
// get an array in the form of [number, string]
let a = elapsed < hour && [Math.floor(elapsed / minute), 'minute'] ||
elapsed < day && [Math.floor(elapsed / hour), 'hour'] ||
elapsed < month && [Math.floor(elapsed / day), 'day'] ||
elapsed < year && [Math.floor(elapsed / month), 'month'] ||
[Math.floor(elapsed / year), 'year'];
// pluralise and append suffix
return a[0] + ' ' + a[1] + (a[0] === 1 ? '' : 's') + suffix;
}
我一直在寻找这个问题的答案，并且几乎实现了其中一个解决方案，但一位同事提醒我检查react-intl库，因为我们已经在使用它了。
所以在解决方案中…在使用react-intl库的情况下，它们有一个<FormattedRelative>组件。
https://github.com/yahoo/react-intl/wiki/Components#formattedrelative
