function timeago(date) {
    var seconds = Math.floor((new Date() - date) / 1000);
    if(Math.round(seconds/(60*60*24*365.25)) >= 2) return Math.round(seconds/(60*60*24*365.25)) + " years ago";
    else if(Math.round(seconds/(60*60*24*365.25)) >= 1) return "1 year ago";
    else if(Math.round(seconds/(60*60*24*30.4)) >= 2) return Math.round(seconds/(60*60*24*30.4)) + " months ago";
    else if(Math.round(seconds/(60*60*24*30.4)) >= 1) return "1 month ago";
    else if(Math.round(seconds/(60*60*24*7)) >= 2) return Math.round(seconds/(60*60*24*7)) + " weeks ago";
    else if(Math.round(seconds/(60*60*24*7)) >= 1) return "1 week ago";
    else if(Math.round(seconds/(60*60*24)) >= 2) return Math.round(seconds/(60*60*24)) + " days ago";
    else if(Math.round(seconds/(60*60*24)) >= 1) return "1 day ago";
    else if(Math.round(seconds/(60*60)) >= 2) return Math.round(seconds/(60*60)) + " hours ago";
    else if(Math.round(seconds/(60*60)) >= 1) return "1 hour ago";
    else if(Math.round(seconds/60) >= 2) return Math.round(seconds/60) + " minutes ago";
    else if(Math.round(seconds/60) >= 1) return "1 minute ago";
    else if(seconds >= 2)return seconds + " seconds ago";
    else return seconds + "1 second ago";
}

在这种情况下可能有点过头了，但如果有机会，moment.js真的很棒!

js是一个javascript datetime库，在这种情况下使用它，你需要做:

moment(yourdate).fromNow()

http://momentjs.com/docs/#/displaying/fromnow/

2018附录:Luxon是一个新的现代图书馆，可能值得一看!

2022年附录:Day.js是一个较新的库，比Luxon轻80%左右，具有类似的功能。

 I achieve this by following method

   timeAgo = (date) => {
            var ms = (new Date()).getTime() - date.getTime();
            var seconds = Math.floor(ms / 1000);
            var minutes = Math.floor(seconds / 60);
        var hours = Math.floor(minutes / 60);
        var days = Math.floor(hours / 24);
        var months = Math.floor(days / 30);
        var years = Math.floor(months / 12);
    
        if (ms === 0) {
            return 'Just now';
        } if (seconds < 60) {
            return seconds + ' seconds Ago';
        } if (minutes < 60) {
            return minutes + ' minutes Ago';
        } if (hours < 24) {
            return hours + ' hours Ago';
        } if (days < 30) {
            return days + ' days Ago';
        } if (months < 12) {
            return months + ' months Ago';
        } else {
            return years + ' years Ago';
        }
    
    }
    
        console.log(timeAgo(new Date()));
        console.log(timeAgo(new Date('Jun 27 2020 10:12:19')));
        console.log(timeAgo(new Date('Jun 27 2020 00:12:19')));
        console.log(timeAgo(new Date('May 28 2020 13:12:19')));
        console.log(timeAgo(new Date('May 28 2017 13:12:19')));

我一直在寻找这个问题的答案，并且几乎实现了其中一个解决方案，但一位同事提醒我检查react-intl库，因为我们已经在使用它了。

所以在解决方案中…在使用react-intl库的情况下，它们有一个<FormattedRelative>组件。

https://github.com/yahoo/react-intl/wiki/Components#formattedrelative

我的尝试是基于其他的答案。

function timeSince(date) {
    let minute = 60;
    let hour   = minute * 60;
    let day    = hour   * 24;
    let month  = day    * 30;
    let year   = day    * 365;

    let suffix = ' ago';

    let elapsed = Math.floor((Date.now() - date) / 1000);

    if (elapsed < minute) {
        return 'just now';
    }

    // get an array in the form of [number, string]
    let a = elapsed < hour  && [Math.floor(elapsed / minute), 'minute'] ||
            elapsed < day   && [Math.floor(elapsed / hour), 'hour']     ||
            elapsed < month && [Math.floor(elapsed / day), 'day']       ||
            elapsed < year  && [Math.floor(elapsed / month), 'month']   ||
            [Math.floor(elapsed / year), 'year'];

    // pluralise and append suffix
    return a[0] + ' ' + a[1] + (a[0] === 1 ? '' : 's') + suffix;
}

以上答案适用于旧的java脚本。但它在新的EC6 JavaScript或TypeScript上运行得不太好。下面是一个非常简短和简单的函数，用于最新的JavaScript, TypeScript, AngularJs, ReactJs和NodeJs，根据给定的日期和时间返回时间。

  public timeAgo(date) {
    var seconds = Math.floor((new Date().getTime() - new Date(date).getTime()) / 1000);
    var interval = seconds / 31536000;
    if (interval > 1) return Math.floor(interval) + " years";
    interval = seconds / 2592000;
    if (interval > 1) return Math.floor(interval) + " months";
    interval = seconds / 86400;
    if (interval > 1) return Math.floor(interval) + " days";
    interval = seconds / 3600;
    if (interval > 1) return Math.floor(interval) + " hours";
    interval = seconds / 60;
    if (interval > 1) return Math.floor(interval) + " minutes";
    return Math.floor(seconds) + " seconds";
  }

console.log(timeAgo('2022-08-12 20:50:20'));
// 2 hours ago, as per the given date time string.