问题是如何将JavaScript Date格式化为一个字符串,声明时间经过,类似于您在Stack Overflow上看到的时间显示方式。
e.g.
1分钟前 1小时前 1天前 1个月前 一年前
问题是如何将JavaScript Date格式化为一个字符串,声明时间经过,类似于您在Stack Overflow上看到的时间显示方式。
e.g.
1分钟前 1小时前 1天前 1个月前 一年前
当前回答
我用js和python写了一个,在两个项目中使用,非常漂亮和简单:一个简单的库(少于2kb),用于*** time ago语句格式化日期。
简单,小巧,易于使用,并且经过良好测试。
NPM安装timeago.js 从timeago.js导入timeago;//或使用脚本标签 使用API格式。
示例:
var timeagoIns = timeago();
timeagoIns .format('2016-06-12');
你也可以实时渲染。
var timeagoIns = timeago();
timeagoIns.render(document.querySelectorAll('time'));
其他回答
这应该正确地处理任何有效的时间戳,包括Date.now()、单数单位和未来日期。我漏掉了月份,但是这些月份应该很容易加进去。我尽量保持它的可读性。
function getTimeInterval(date) { let seconds = Math.floor((Date.now() - date) / 1000); let unit = "second"; let direction = "ago"; if (seconds < 0) { seconds = -seconds; direction = "from now"; } let value = seconds; if (seconds >= 31536000) { value = Math.floor(seconds / 31536000); unit = "year"; } else if (seconds >= 86400) { value = Math.floor(seconds / 86400); unit = "day"; } else if (seconds >= 3600) { value = Math.floor(seconds / 3600); unit = "hour"; } else if (seconds >= 60) { value = Math.floor(seconds / 60); unit = "minute"; } if (value != 1) unit = unit + "s"; return value + " " + unit + " " + direction; } console.log(getTimeInterval(Date.now())); // 0 seconds ago console.log(getTimeInterval(Date.now() + 1000)); // 1 second from now console.log(getTimeInterval(Date.now() - 1000)); // 1 second ago console.log(getTimeInterval(Date.now() + 60000)); // 1 minute from now console.log(getTimeInterval(Date.now() - 120000)); // 2 minutes ago console.log(getTimeInterval(Date.now() + 120000)); // 2 minutes from now console.log(getTimeInterval(Date.now() + 3600000)); // 1 hour from now console.log(getTimeInterval(Date.now() + 360000000000)); // 11 years from now console.log(getTimeInterval(0)); // 49 years ago
function timeSince(date) { var seconds = Math.floor((new Date() - date) / 1000); var interval = seconds / 31536000; if (interval > 1) { return Math.floor(interval) + " years"; } interval = seconds / 2592000; if (interval > 1) { return Math.floor(interval) + " months"; } interval = seconds / 86400; if (interval > 1) { return Math.floor(interval) + " days"; } interval = seconds / 3600; if (interval > 1) { return Math.floor(interval) + " hours"; } interval = seconds / 60; if (interval > 1) { return Math.floor(interval) + " minutes"; } return Math.floor(seconds) + " seconds"; } var aDay = 24*60*60*1000; console.log(timeSince(new Date(Date.now()-aDay))); console.log(timeSince(new Date(Date.now()-aDay*2)));
回复@Stas Parshin的答案,这是最好的答案,代码更少,但它在与typescript一起使用时有bug, Intl的.format函数需要2个输入
number, Units - i.e of type 'RelativeTimeFormatUnit' so if you pass a object key typescript will through error saying unit must be of type RelativeTimeFormatUnit and not of type string, so the work-around for this is to use the type to make another list of same type and rest you can have look at code... Happy coding. console.log(timeAgo('2021-08-09T15:29:01+0000')); function timeAgo(input) { const date = (input instanceof Date) ? input : new Date(input); const formatter = new Intl.RelativeTimeFormat('en'); const ranges = { years: 3600 * 24 * 365, months: 3600 * 24 * 30, weeks: 3600 * 24 * 7, days: 3600 * 24, hours: 3600, minutes: 60, seconds: 1 }; type RelativeTimeFormatUnit = | "year" | "years" | "quarter" | "quarters" | "month" | "months" | "week" | "weeks" | "day" | "days" | "hour" | "hours" | "minute" | "minutes" | "second" | "seconds" ; const units: RelativeTimeFormatUnit[] = ["years", "months", "weeks", "days", "hours", "minutes", "seconds"]; // order matters here. const secondsElapsed = (date.getTime() - Date.now()) / 1000; for (let key in ranges) { let i = 0; if (ranges[key] < Math.abs(secondsElapsed)) { const delta = secondsElapsed / ranges[key]; return formatter.format(Math.round(delta), units[i++]); } } }
function timeago(date) {
var seconds = Math.floor((new Date() - date) / 1000);
if(Math.round(seconds/(60*60*24*365.25)) >= 2) return Math.round(seconds/(60*60*24*365.25)) + " years ago";
else if(Math.round(seconds/(60*60*24*365.25)) >= 1) return "1 year ago";
else if(Math.round(seconds/(60*60*24*30.4)) >= 2) return Math.round(seconds/(60*60*24*30.4)) + " months ago";
else if(Math.round(seconds/(60*60*24*30.4)) >= 1) return "1 month ago";
else if(Math.round(seconds/(60*60*24*7)) >= 2) return Math.round(seconds/(60*60*24*7)) + " weeks ago";
else if(Math.round(seconds/(60*60*24*7)) >= 1) return "1 week ago";
else if(Math.round(seconds/(60*60*24)) >= 2) return Math.round(seconds/(60*60*24)) + " days ago";
else if(Math.round(seconds/(60*60*24)) >= 1) return "1 day ago";
else if(Math.round(seconds/(60*60)) >= 2) return Math.round(seconds/(60*60)) + " hours ago";
else if(Math.round(seconds/(60*60)) >= 1) return "1 hour ago";
else if(Math.round(seconds/60) >= 2) return Math.round(seconds/60) + " minutes ago";
else if(Math.round(seconds/60) >= 1) return "1 minute ago";
else if(seconds >= 2)return seconds + " seconds ago";
else return seconds + "1 second ago";
}
我的尝试是基于其他的答案。
function timeSince(date) {
let minute = 60;
let hour = minute * 60;
let day = hour * 24;
let month = day * 30;
let year = day * 365;
let suffix = ' ago';
let elapsed = Math.floor((Date.now() - date) / 1000);
if (elapsed < minute) {
return 'just now';
}
// get an array in the form of [number, string]
let a = elapsed < hour && [Math.floor(elapsed / minute), 'minute'] ||
elapsed < day && [Math.floor(elapsed / hour), 'hour'] ||
elapsed < month && [Math.floor(elapsed / day), 'day'] ||
elapsed < year && [Math.floor(elapsed / month), 'month'] ||
[Math.floor(elapsed / year), 'year'];
// pluralise and append suffix
return a[0] + ' ' + a[1] + (a[0] === 1 ? '' : 's') + suffix;
}