问题是如何将JavaScript Date格式化为一个字符串,声明时间经过,类似于您在Stack Overflow上看到的时间显示方式。
e.g.
1分钟前 1小时前 1天前 1个月前 一年前
问题是如何将JavaScript Date格式化为一个字符串,声明时间经过,类似于您在Stack Overflow上看到的时间显示方式。
e.g.
1分钟前 1小时前 1天前 1个月前 一年前
当前回答
以下是对Sky Sander的解决方案的轻微修改,允许日期作为字符串输入,并能够显示像“1分钟”而不是“73秒”这样的跨度
var timeSince = function(date) { if (typeof date !== 'object') { date = new Date(date); } var seconds = Math.floor((new Date() - date) / 1000); var intervalType; var interval = Math.floor(seconds / 31536000); if (interval >= 1) { intervalType = 'year'; } else { interval = Math.floor(seconds / 2592000); if (interval >= 1) { intervalType = 'month'; } else { interval = Math.floor(seconds / 86400); if (interval >= 1) { intervalType = 'day'; } else { interval = Math.floor(seconds / 3600); if (interval >= 1) { intervalType = "hour"; } else { interval = Math.floor(seconds / 60); if (interval >= 1) { intervalType = "minute"; } else { interval = seconds; intervalType = "second"; } } } } } if (interval > 1 || interval === 0) { intervalType += 's'; } return interval + ' ' + intervalType; }; var aDay = 24 * 60 * 60 * 1000; console.log(timeSince(new Date(Date.now() - aDay))); console.log(timeSince(new Date(Date.now() - aDay * 2)));
其他回答
function timeago(date) {
var seconds = Math.floor((new Date() - date) / 1000);
if(Math.round(seconds/(60*60*24*365.25)) >= 2) return Math.round(seconds/(60*60*24*365.25)) + " years ago";
else if(Math.round(seconds/(60*60*24*365.25)) >= 1) return "1 year ago";
else if(Math.round(seconds/(60*60*24*30.4)) >= 2) return Math.round(seconds/(60*60*24*30.4)) + " months ago";
else if(Math.round(seconds/(60*60*24*30.4)) >= 1) return "1 month ago";
else if(Math.round(seconds/(60*60*24*7)) >= 2) return Math.round(seconds/(60*60*24*7)) + " weeks ago";
else if(Math.round(seconds/(60*60*24*7)) >= 1) return "1 week ago";
else if(Math.round(seconds/(60*60*24)) >= 2) return Math.round(seconds/(60*60*24)) + " days ago";
else if(Math.round(seconds/(60*60*24)) >= 1) return "1 day ago";
else if(Math.round(seconds/(60*60)) >= 2) return Math.round(seconds/(60*60)) + " hours ago";
else if(Math.round(seconds/(60*60)) >= 1) return "1 hour ago";
else if(Math.round(seconds/60) >= 2) return Math.round(seconds/60) + " minutes ago";
else if(Math.round(seconds/60) >= 1) return "1 minute ago";
else if(seconds >= 2)return seconds + " seconds ago";
else return seconds + "1 second ago";
}
要使用这个,只需复制所有这些代码,并将其导入到你的组件或任何地方,并将你的ISOstring()日期放在:showTimeAgo("2022-06-20T13:42:29-05:00"),你将获得每个场景的自动时间更新。
旁注:我为这个https://www.npmjs.com/package/showtimeago做了一个npm包
export const showTimeAgo = () => {
const MONTH_NAMES = [
'January',
'February',
'March',
'April',
'May',
'June',
'July',
'August',
'September',
'October',
'November',
'December',
];
function getOrdinalNum() {
return (
n +
(n > 0
? ['th', 'st', 'nd', 'rd'][
(n > 3 && n < 21) || n % 10 > 3 ? 0 : n % 10
]
: '')
);
}
function getFormattedDate(
date,
preformattedDate = false,
hideYear = false
) {
const day = date.getDate();
const month = MONTH_NAMES[date.getMonth()];
const year = date.getFullYear();
let hours = date.getHours();
let minutes = date.getMinutes();
let ampm = hours >= 12 ? 'pm' : 'am';
switch(true){
case (hours > 12):
hours = hours - 12;
break;
case (hours === 0):
hours = 12;
break;
case(minutes < 10):
minutes = `0${minutes}`;
break;
case(preformattedDate):
// Today at 10:20am
// Yesterday at 10:20am
return `${preformattedDate} at ${hours}:${minutes} ${ampm}`;
case(hideYear):
// January 10th at 10:20pm
return `${month} ${getOrdinalNum(
day
)}, at ${hours}:${minutes} ${ampm}`;
default:
// January 10th 2022 at 10:20pm
return `${month} ${getOrdinalNum(
day
)}, ${year} at ${hours}:${minutes} ${ampm}`;
}
}
// --- Main function
function timeAgo(dateParam) {
if (!dateParam) {
return null;
}
const date =
typeof dateParam === 'object' ? dateParam : new Date(dateParam);
const DAY_IN_MS = 86400000; // 24 * 60 * 60 * 1000
const today = new Date();
const yesterday = new Date(today - DAY_IN_MS);
const seconds = Math.round((today - date) / 1000);
const minutes = Math.round(seconds / 60);
const hour = Math.round(seconds / 3600);
const day = Math.round(seconds / 86400);
const month = Math.round(seconds / 2629800);
const year = Math.floor(seconds / 31536000);
const isToday = today.toDateString() === date.toDateString();
const isYesterday =
yesterday.toDateString() === date.toDateString();
const isThisYear = today.getFullYear() === date.getFullYear();
switch(true){
case (seconds < 5):
return 'now';
case (seconds < 60):
return `${seconds} seconds ago`;
case (seconds < 90):
return 'about a minute ago';
case (minutes < 60):
return `${minutes} minutes ago`;
case (hour === 1 && hour < 2):
return `${hour} hour ago`; // 1 hour ago
case (hour > 1 && hour <= 12):
return `${hour} hours ago`; // 2 hours ago
case (isToday):
return getFormattedDate(date, 'Today'); // Today at 10:20am
case (isYesterday):
return getFormattedDate(date, 'Yesterday'); // Yesterday at 10:20am
case(day > 1 && day <= 30):
return `${day} days ago`; // 2 days ago
case (isThisYear):
return getFormattedDate(date, false, true); // January 10th at 10:20pm
case (day > 30 && month <= 1):
return `${hour} month ago`; // 1 month ago
case (month > 1 && month <= 12):
return `${month} months ago`; // 2 months ago
case (year === 1):
return `${year} year ago`; // 1 year ago
case (year > 1):
return `${year} years ago`; // 2 years ago
default:
return getFormattedDate(date); // January 10th 2022 at 10:20pm
}
}
return timeAgo(date);
};
console.log(showTimeAgo("2022-06-20T13:42:29-05:00"));-05:00"))
你可以使用Luxon:
DateTime.toRelative()
https://moment.github.io/luxon/api-docs/index.html#datetimetorelative
这里还有一些例子:
const DateTime = luxon.DateTime; // toRelative console.log(DateTime.now().minus({ seconds: 1 }).toRelative()) // 1 second ago console.log(DateTime.now().minus({ seconds: 10 }).toRelative()) // 10 seconds ago console.log(DateTime.now().minus({ days: 2 }).toRelative()) console.log(DateTime.now().minus({ years: 3 }).toRelative()) console.log(DateTime.now().plus({ years: 3 }).toRelative()) console.log(DateTime.now().plus({ days: 2 }).toRelative()) console.log(DateTime.now().plus({ seconds: 1 }).toRelative()) console.log(DateTime.now().plus({ seconds: 10 }).toRelative()) // toRelativeCalendar console.log(DateTime.now().minus({ seconds: 1 }).toRelativeCalendar()) // today console.log(DateTime.now().minus({ seconds: 10 }).toRelativeCalendar()) // today console.log(DateTime.now().minus({ days: 2 }).toRelativeCalendar()) console.log(DateTime.now().minus({ years: 3 }).toRelativeCalendar()) console.log(DateTime.now().plus({ years: 3 }).toRelativeCalendar()) console.log(DateTime.now().plus({ days: 2 }).toRelativeCalendar()) console.log(DateTime.now().plus({ seconds: 1 }).toRelativeCalendar()) console.log(DateTime.now().plus({ seconds: 10 }).toRelativeCalendar()) <script src="https://moment.github.io/luxon/global/luxon.min.js"></script>
const timeHandler = (time: any) => {
var a = moment(); //now
var b = moment.utc(time);
const sec = a.diff(b, 'seconds');
const minuts = a.diff(b, 'minutes');
const hours = a.diff(b, 'hours');
const days = a.diff(b, 'days');
const weeks = a.diff(b, 'weeks');
return weeks == 0
? days == 0
? hours == 0
? minuts == 0
? sec >= 0 && `${sec}s ago`
: `${minuts}m ago`
: `${hours}h ago`
: `${days}d ago`
: `${weeks}w ago`;
};
console.log(timeHandler('2022-11-11T12:11:06.6103808'))
以上答案适用于旧的java脚本。但它在新的EC6 JavaScript或TypeScript上运行得不太好。下面是一个非常简短和简单的函数,用于最新的JavaScript, TypeScript, AngularJs, ReactJs和NodeJs,根据给定的日期和时间返回时间。
public timeAgo(date) {
var seconds = Math.floor((new Date().getTime() - new Date(date).getTime()) / 1000);
var interval = seconds / 31536000;
if (interval > 1) return Math.floor(interval) + " years";
interval = seconds / 2592000;
if (interval > 1) return Math.floor(interval) + " months";
interval = seconds / 86400;
if (interval > 1) return Math.floor(interval) + " days";
interval = seconds / 3600;
if (interval > 1) return Math.floor(interval) + " hours";
interval = seconds / 60;
if (interval > 1) return Math.floor(interval) + " minutes";
return Math.floor(seconds) + " seconds";
}
console.log(timeAgo('2022-08-12 20:50:20'));
// 2 hours ago, as per the given date time string.