在这种情况下可能有点过头了，但如果有机会，moment.js真的很棒!

js是一个javascript datetime库，在这种情况下使用它，你需要做:

moment(yourdate).fromNow()

http://momentjs.com/docs/#/displaying/fromnow/

2018附录:Luxon是一个新的现代图书馆，可能值得一看!

2022年附录:Day.js是一个较新的库，比Luxon轻80%左右，具有类似的功能。

我修改了Sky Sanders的版本。Math.floor(…)操作在if块中计算

       var timeSince = function(date) {
            var seconds = Math.floor((new Date() - date) / 1000);
            var months = ["January", "February", "March", "April", "May", "June", "July", "August", "September", "October", "November", "December"];
            if (seconds < 5){
                return "just now";
            }else if (seconds < 60){
                return seconds + " seconds ago";
            }
            else if (seconds < 3600) {
                minutes = Math.floor(seconds/60)
                if(minutes > 1)
                    return minutes + " minutes ago";
                else
                    return "1 minute ago";
            }
            else if (seconds < 86400) {
                hours = Math.floor(seconds/3600)
                if(hours > 1)
                    return hours + " hours ago";
                else
                    return "1 hour ago";
            }
            //2 days and no more
            else if (seconds < 172800) {
                days = Math.floor(seconds/86400)
                if(days > 1)
                    return days + " days ago";
                else
                    return "1 day ago";
            }
            else{

                //return new Date(time).toLocaleDateString();
                return date.getDate().toString() + " " + months[date.getMonth()] + ", " + date.getFullYear();
            }
        }

从现在开始，Unix时间戳参数

function timeSince(ts){
    now = new Date();
    ts = new Date(ts*1000);
    var delta = now.getTime() - ts.getTime();

    delta = delta/1000; //us to s

    var ps, pm, ph, pd, min, hou, sec, days;

    if(delta<=59){
        ps = (delta>1) ? "s": "";
        return delta+" second"+ps
    }

    if(delta>=60 && delta<=3599){
        min = Math.floor(delta/60);
        sec = delta-(min*60);
        pm = (min>1) ? "s": "";
        ps = (sec>1) ? "s": "";
        return min+" minute"+pm+" "+sec+" second"+ps;
    }

    if(delta>=3600 && delta<=86399){
        hou = Math.floor(delta/3600);
        min = Math.floor((delta-(hou*3600))/60);
        ph = (hou>1) ? "s": "";
        pm = (min>1) ? "s": "";
        return hou+" hour"+ph+" "+min+" minute"+pm;
    } 

    if(delta>=86400){
        days = Math.floor(delta/86400);
        hou =  Math.floor((delta-(days*86400))/60/60);
        pd = (days>1) ? "s": "";
        ph = (hou>1) ? "s": "";
        return days+" day"+pd+" "+hou+" hour"+ph;
    }

}

Lokely使用的一个简短版本:

const intervals = [
  { label: 'year', seconds: 31536000 },
  { label: 'month', seconds: 2592000 },
  { label: 'day', seconds: 86400 },
  { label: 'hour', seconds: 3600 },
  { label: 'minute', seconds: 60 },
  { label: 'second', seconds: 1 }
];

function timeSince(date) {
  const seconds = Math.floor((Date.now() - date.getTime()) / 1000);
  const interval = intervals.find(i => i.seconds < seconds);
  const count = Math.floor(seconds / interval.seconds);
  return `${count} ${interval.label}${count !== 1 ? 's' : ''} ago`;
}

这应该正确地处理任何有效的时间戳，包括Date.now()、单数单位和未来日期。我漏掉了月份，但是这些月份应该很容易加进去。我尽量保持它的可读性。

function getTimeInterval(date) { let seconds = Math.floor((Date.now() - date) / 1000); let unit = "second"; let direction = "ago"; if (seconds < 0) { seconds = -seconds; direction = "from now"; } let value = seconds; if (seconds >= 31536000) { value = Math.floor(seconds / 31536000); unit = "year"; } else if (seconds >= 86400) { value = Math.floor(seconds / 86400); unit = "day"; } else if (seconds >= 3600) { value = Math.floor(seconds / 3600); unit = "hour"; } else if (seconds >= 60) { value = Math.floor(seconds / 60); unit = "minute"; } if (value != 1) unit = unit + "s"; return value + " " + unit + " " + direction; } console.log(getTimeInterval(Date.now())); // 0 seconds ago console.log(getTimeInterval(Date.now() + 1000)); // 1 second from now console.log(getTimeInterval(Date.now() - 1000)); // 1 second ago console.log(getTimeInterval(Date.now() + 60000)); // 1 minute from now console.log(getTimeInterval(Date.now() - 120000)); // 2 minutes ago console.log(getTimeInterval(Date.now() + 120000)); // 2 minutes from now console.log(getTimeInterval(Date.now() + 3600000)); // 1 hour from now console.log(getTimeInterval(Date.now() + 360000000000)); // 11 years from now console.log(getTimeInterval(0)); // 49 years ago

以上答案适用于旧的java脚本。但它在新的EC6 JavaScript或TypeScript上运行得不太好。下面是一个非常简短和简单的函数，用于最新的JavaScript, TypeScript, AngularJs, ReactJs和NodeJs，根据给定的日期和时间返回时间。

  public timeAgo(date) {
    var seconds = Math.floor((new Date().getTime() - new Date(date).getTime()) / 1000);
    var interval = seconds / 31536000;
    if (interval > 1) return Math.floor(interval) + " years";
    interval = seconds / 2592000;
    if (interval > 1) return Math.floor(interval) + " months";
    interval = seconds / 86400;
    if (interval > 1) return Math.floor(interval) + " days";
    interval = seconds / 3600;
    if (interval > 1) return Math.floor(interval) + " hours";
    interval = seconds / 60;
    if (interval > 1) return Math.floor(interval) + " minutes";
    return Math.floor(seconds) + " seconds";
  }

console.log(timeAgo('2022-08-12 20:50:20'));
// 2 hours ago, as per the given date time string.