这应该正确地处理任何有效的时间戳，包括Date.now()、单数单位和未来日期。我漏掉了月份，但是这些月份应该很容易加进去。我尽量保持它的可读性。

function getTimeInterval(date) { let seconds = Math.floor((Date.now() - date) / 1000); let unit = "second"; let direction = "ago"; if (seconds < 0) { seconds = -seconds; direction = "from now"; } let value = seconds; if (seconds >= 31536000) { value = Math.floor(seconds / 31536000); unit = "year"; } else if (seconds >= 86400) { value = Math.floor(seconds / 86400); unit = "day"; } else if (seconds >= 3600) { value = Math.floor(seconds / 3600); unit = "hour"; } else if (seconds >= 60) { value = Math.floor(seconds / 60); unit = "minute"; } if (value != 1) unit = unit + "s"; return value + " " + unit + " " + direction; } console.log(getTimeInterval(Date.now())); // 0 seconds ago console.log(getTimeInterval(Date.now() + 1000)); // 1 second from now console.log(getTimeInterval(Date.now() - 1000)); // 1 second ago console.log(getTimeInterval(Date.now() + 60000)); // 1 minute from now console.log(getTimeInterval(Date.now() - 120000)); // 2 minutes ago console.log(getTimeInterval(Date.now() + 120000)); // 2 minutes from now console.log(getTimeInterval(Date.now() + 3600000)); // 1 hour from now console.log(getTimeInterval(Date.now() + 360000000000)); // 11 years from now console.log(getTimeInterval(0)); // 49 years ago

function mdiv(dividend, divisor) {
    return [ Math.floor(dividend/divisor), dividend % divisor ];
}
// pass in milliseconds, gained by Date1.getTime() - Date2.getTime()
// if max_units is two, the result will be, for example
// 2years 12months ago, or 2hours 38minutes ago
// return formated period

function readable_period(ms, max_units=2){
    let [yy, yr] = mdiv(ms, 3.154e10);
    let [mm, mr] = mdiv(yr, 2.628e9);
    let [dd, dr] = mdiv(mr, 8.64e7);
    let [hh, hr] = mdiv(dr, 3.6e6);
    let [tt, ss] = mdiv(hr, 6e4);

    var ymdht = ['year', 'month', 'day', 'hour', 'minute'];
    let res = [];
    [yy, mm, dd, hh, tt].forEach((tis, ii)=>{
        if(res.length === max_units){return};
        if(tis !== 0){
            res.push(tis === 1 ? `${tis}${ymdht[ii]}` : `${tis}${ymdht[ii]}s`);
        }
    });
    return res.length === 0 ? '' : res.join(' ') + ' ago';
}

以上答案适用于旧的java脚本。但它在新的EC6 JavaScript或TypeScript上运行得不太好。下面是一个非常简短和简单的函数，用于最新的JavaScript, TypeScript, AngularJs, ReactJs和NodeJs，根据给定的日期和时间返回时间。

  public timeAgo(date) {
    var seconds = Math.floor((new Date().getTime() - new Date(date).getTime()) / 1000);
    var interval = seconds / 31536000;
    if (interval > 1) return Math.floor(interval) + " years";
    interval = seconds / 2592000;
    if (interval > 1) return Math.floor(interval) + " months";
    interval = seconds / 86400;
    if (interval > 1) return Math.floor(interval) + " days";
    interval = seconds / 3600;
    if (interval > 1) return Math.floor(interval) + " hours";
    interval = seconds / 60;
    if (interval > 1) return Math.floor(interval) + " minutes";
    return Math.floor(seconds) + " seconds";
  }

console.log(timeAgo('2022-08-12 20:50:20'));
// 2 hours ago, as per the given date time string.

由@user1012181提供的ES6版本代码:

const epochs = [
    ['year', 31536000],
    ['month', 2592000],
    ['day', 86400],
    ['hour', 3600],
    ['minute', 60],
    ['second', 1]
];

const getDuration = (timeAgoInSeconds) => {
    for (let [name, seconds] of epochs) {
        const interval = Math.floor(timeAgoInSeconds / seconds);
        if (interval >= 1) {
            return {
                interval: interval,
                epoch: name
            };
        }
    }
};

const timeAgo = (date) => {
    const timeAgoInSeconds = Math.floor((new Date() - new Date(date)) / 1000);
    const {interval, epoch} = getDuration(timeAgoInSeconds);
    const suffix = interval === 1 ? '' : 's';
    return `${interval} ${epoch}${suffix} ago`;
};

由@ibe-vanmeenen编辑建议。(谢谢!)

回答10年的老问题，帮助新人。

我们可以将这个包用于javascript时间之前

 
// Load locale-specific relative date/time formatting rules.
import en from 'javascript-time-ago/locale/en'
 
// Add locale-specific relative date/time formatting rules.
TimeAgo.addLocale(en)
 
// Create relative date/time formatter.
const timeAgo = new TimeAgo('en-US')
 
timeAgo.format(new Date())
// "just now"
 
timeAgo.format(Date.now() - 60 * 1000)
// "a minute ago"
 
timeAgo.format(Date.now() - 2 * 60 * 60 * 1000)
// "2 hours ago"
 
timeAgo.format(Date.now() - 24 * 60 * 60 * 1000)
// "a day ago"

这是一个简化版的@sky-sanders的回答。

function timeSince(date) {

  var seconds = Math.floor((new Date() - date) / 1000);
  var divisors = [31536000, 2592000, 86400, 3600, 60, 1]
  var description = ["years", "months", "days", "hours", "minutes", "seconds"]
  var result = [];

  var interval = seconds;

  for (i = 0; i < divisors.length; i++) {
    interval = Math.floor(seconds / divisors[i])
    if (interval > 1) {
      result.push(interval + " " + description[i])
    }
    seconds -= interval * divisors[i]
  }

  return result.join(" ")
}