问题是如何将JavaScript Date格式化为一个字符串,声明时间经过,类似于您在Stack Overflow上看到的时间显示方式。
e.g.
1分钟前 1小时前 1天前 1个月前 一年前
问题是如何将JavaScript Date格式化为一个字符串,声明时间经过,类似于您在Stack Overflow上看到的时间显示方式。
e.g.
1分钟前 1小时前 1天前 1个月前 一年前
当前回答
回复@Stas Parshin的答案,这是最好的答案,代码更少,但它在与typescript一起使用时有bug, Intl的.format函数需要2个输入
number, Units - i.e of type 'RelativeTimeFormatUnit' so if you pass a object key typescript will through error saying unit must be of type RelativeTimeFormatUnit and not of type string, so the work-around for this is to use the type to make another list of same type and rest you can have look at code... Happy coding. console.log(timeAgo('2021-08-09T15:29:01+0000')); function timeAgo(input) { const date = (input instanceof Date) ? input : new Date(input); const formatter = new Intl.RelativeTimeFormat('en'); const ranges = { years: 3600 * 24 * 365, months: 3600 * 24 * 30, weeks: 3600 * 24 * 7, days: 3600 * 24, hours: 3600, minutes: 60, seconds: 1 }; type RelativeTimeFormatUnit = | "year" | "years" | "quarter" | "quarters" | "month" | "months" | "week" | "weeks" | "day" | "days" | "hour" | "hours" | "minute" | "minutes" | "second" | "seconds" ; const units: RelativeTimeFormatUnit[] = ["years", "months", "weeks", "days", "hours", "minutes", "seconds"]; // order matters here. const secondsElapsed = (date.getTime() - Date.now()) / 1000; for (let key in ranges) { let i = 0; if (ranges[key] < Math.abs(secondsElapsed)) { const delta = secondsElapsed / ranges[key]; return formatter.format(Math.round(delta), units[i++]); } } }
其他回答
我的尝试是基于其他的答案。
function timeSince(date) {
let minute = 60;
let hour = minute * 60;
let day = hour * 24;
let month = day * 30;
let year = day * 365;
let suffix = ' ago';
let elapsed = Math.floor((Date.now() - date) / 1000);
if (elapsed < minute) {
return 'just now';
}
// get an array in the form of [number, string]
let a = elapsed < hour && [Math.floor(elapsed / minute), 'minute'] ||
elapsed < day && [Math.floor(elapsed / hour), 'hour'] ||
elapsed < month && [Math.floor(elapsed / day), 'day'] ||
elapsed < year && [Math.floor(elapsed / month), 'month'] ||
[Math.floor(elapsed / year), 'year'];
// pluralise and append suffix
return a[0] + ' ' + a[1] + (a[0] === 1 ? '' : 's') + suffix;
}
简单易读版本:
const relativeTimePeriods = [
[31536000, 'year'],
[2419200, 'month'],
[604800, 'week'],
[86400, 'day'],
[3600, 'hour'],
[60, 'minute'],
[1, 'second']
];
function relativeTime(date, isUtc=true) {
if (!(date instanceof Date)) date = new Date(date * 1000);
const seconds = (new Date() - date) / 1000;
for (let [secondsPer, name] of relativeTimePeriods) {
if (seconds >= secondsPer) {
const amount = Math.floor(seconds / secondsPer);
return `${amount} ${name}${amount ? 's' : ''}s ago`;
}
}
return 'Just now';
}
虽然这个问题是很久以前问过的,但写下这个答案希望它能帮助到一些人。
传递您想要开始计数的日期。使用momentjs的moment().fromNow():(在这里查看更多信息)
getRelativeTime(date) {
const d = new Date(date * 1000);
return moment(d).fromNow();
}
如果您想更改日期fromNow提供的信息,请编写自定义相对时间为时刻。
例如,在我自己的例子中,我想打印'one month ago'而不是'a month ago'(由moment(d). fromnow()提供)。在这种情况下,你可以写出下面给出的内容。
moment.updateLocale('en', {
relativeTime: {
future: 'in %s',
past: '%s ago',
s: 'a few seconds',
ss: '%d seconds',
m: '1 m',
mm: '%d minutes',
h: '1 h',
hh: '%d hours',
d: '1 d',
dd: '%d days',
M: '1 month',
MM: '%d months',
y: '1 y',
yy: '%d years'
}
});
注意:我是在Angular 6中为项目编写代码的
要使用这个,只需复制所有这些代码,并将其导入到你的组件或任何地方,并将你的ISOstring()日期放在:showTimeAgo("2022-06-20T13:42:29-05:00"),你将获得每个场景的自动时间更新。
旁注:我为这个https://www.npmjs.com/package/showtimeago做了一个npm包
export const showTimeAgo = () => {
const MONTH_NAMES = [
'January',
'February',
'March',
'April',
'May',
'June',
'July',
'August',
'September',
'October',
'November',
'December',
];
function getOrdinalNum() {
return (
n +
(n > 0
? ['th', 'st', 'nd', 'rd'][
(n > 3 && n < 21) || n % 10 > 3 ? 0 : n % 10
]
: '')
);
}
function getFormattedDate(
date,
preformattedDate = false,
hideYear = false
) {
const day = date.getDate();
const month = MONTH_NAMES[date.getMonth()];
const year = date.getFullYear();
let hours = date.getHours();
let minutes = date.getMinutes();
let ampm = hours >= 12 ? 'pm' : 'am';
switch(true){
case (hours > 12):
hours = hours - 12;
break;
case (hours === 0):
hours = 12;
break;
case(minutes < 10):
minutes = `0${minutes}`;
break;
case(preformattedDate):
// Today at 10:20am
// Yesterday at 10:20am
return `${preformattedDate} at ${hours}:${minutes} ${ampm}`;
case(hideYear):
// January 10th at 10:20pm
return `${month} ${getOrdinalNum(
day
)}, at ${hours}:${minutes} ${ampm}`;
default:
// January 10th 2022 at 10:20pm
return `${month} ${getOrdinalNum(
day
)}, ${year} at ${hours}:${minutes} ${ampm}`;
}
}
// --- Main function
function timeAgo(dateParam) {
if (!dateParam) {
return null;
}
const date =
typeof dateParam === 'object' ? dateParam : new Date(dateParam);
const DAY_IN_MS = 86400000; // 24 * 60 * 60 * 1000
const today = new Date();
const yesterday = new Date(today - DAY_IN_MS);
const seconds = Math.round((today - date) / 1000);
const minutes = Math.round(seconds / 60);
const hour = Math.round(seconds / 3600);
const day = Math.round(seconds / 86400);
const month = Math.round(seconds / 2629800);
const year = Math.floor(seconds / 31536000);
const isToday = today.toDateString() === date.toDateString();
const isYesterday =
yesterday.toDateString() === date.toDateString();
const isThisYear = today.getFullYear() === date.getFullYear();
switch(true){
case (seconds < 5):
return 'now';
case (seconds < 60):
return `${seconds} seconds ago`;
case (seconds < 90):
return 'about a minute ago';
case (minutes < 60):
return `${minutes} minutes ago`;
case (hour === 1 && hour < 2):
return `${hour} hour ago`; // 1 hour ago
case (hour > 1 && hour <= 12):
return `${hour} hours ago`; // 2 hours ago
case (isToday):
return getFormattedDate(date, 'Today'); // Today at 10:20am
case (isYesterday):
return getFormattedDate(date, 'Yesterday'); // Yesterday at 10:20am
case(day > 1 && day <= 30):
return `${day} days ago`; // 2 days ago
case (isThisYear):
return getFormattedDate(date, false, true); // January 10th at 10:20pm
case (day > 30 && month <= 1):
return `${hour} month ago`; // 1 month ago
case (month > 1 && month <= 12):
return `${month} months ago`; // 2 months ago
case (year === 1):
return `${year} year ago`; // 1 year ago
case (year > 1):
return `${year} years ago`; // 2 years ago
default:
return getFormattedDate(date); // January 10th 2022 at 10:20pm
}
}
return timeAgo(date);
};
console.log(showTimeAgo("2022-06-20T13:42:29-05:00"));-05:00"))
这些答案大多不能解释复数(例如:复数)。当我们想要“1分钟前”时,用“1分钟前”)
const MINUTE = 60;
const HOUR = MINUTE * 60;
const DAY = HOUR * 24;
const WEEK = DAY * 7;
const MONTH = DAY * 30;
const YEAR = DAY * 365;
function getTimeAgo(date) {
const secondsAgo = Math.round((Date.now() - Number(date)) / 1000);
if (secondsAgo < MINUTE) {
return secondsAgo + ` second${secondsAgo !== 1 ? "s" : ""} ago`;
}
let divisor;
let unit = "";
if (secondsAgo < HOUR) {
[divisor, unit] = [MINUTE, "minute"];
} else if (secondsAgo < DAY) {
[divisor, unit] = [HOUR, "hour"];
} else if (secondsAgo < WEEK) {
[divisor, unit] = [DAY, "day"];
} else if (secondsAgo < MONTH) {
[divisor, unit] = [WEEK, "week"];
} else if (secondsAgo < YEAR) {
[divisor, unit] = [MONTH, "month"];
} else {
[divisor, unit] = [YEAR, "year"];
}
const count = Math.floor(secondsAgo / divisor);
return `${count} ${unit}${count > 1 ? "s" : ""} ago`;
}
然后你可以这样使用它:
const date = new Date();
console.log(getTimeAgo(date));
// 1 second ago
// 2 seconds ago
// 1 minute ago
// 2 minutes ago
// ...