问题是如何将JavaScript Date格式化为一个字符串,声明时间经过,类似于您在Stack Overflow上看到的时间显示方式。
e.g.
1分钟前 1小时前 1天前 1个月前 一年前
问题是如何将JavaScript Date格式化为一个字符串,声明时间经过,类似于您在Stack Overflow上看到的时间显示方式。
e.g.
1分钟前 1小时前 1天前 1个月前 一年前
当前回答
要使用这个,只需复制所有这些代码,并将其导入到你的组件或任何地方,并将你的ISOstring()日期放在:showTimeAgo("2022-06-20T13:42:29-05:00"),你将获得每个场景的自动时间更新。
旁注:我为这个https://www.npmjs.com/package/showtimeago做了一个npm包
export const showTimeAgo = () => {
const MONTH_NAMES = [
'January',
'February',
'March',
'April',
'May',
'June',
'July',
'August',
'September',
'October',
'November',
'December',
];
function getOrdinalNum() {
return (
n +
(n > 0
? ['th', 'st', 'nd', 'rd'][
(n > 3 && n < 21) || n % 10 > 3 ? 0 : n % 10
]
: '')
);
}
function getFormattedDate(
date,
preformattedDate = false,
hideYear = false
) {
const day = date.getDate();
const month = MONTH_NAMES[date.getMonth()];
const year = date.getFullYear();
let hours = date.getHours();
let minutes = date.getMinutes();
let ampm = hours >= 12 ? 'pm' : 'am';
switch(true){
case (hours > 12):
hours = hours - 12;
break;
case (hours === 0):
hours = 12;
break;
case(minutes < 10):
minutes = `0${minutes}`;
break;
case(preformattedDate):
// Today at 10:20am
// Yesterday at 10:20am
return `${preformattedDate} at ${hours}:${minutes} ${ampm}`;
case(hideYear):
// January 10th at 10:20pm
return `${month} ${getOrdinalNum(
day
)}, at ${hours}:${minutes} ${ampm}`;
default:
// January 10th 2022 at 10:20pm
return `${month} ${getOrdinalNum(
day
)}, ${year} at ${hours}:${minutes} ${ampm}`;
}
}
// --- Main function
function timeAgo(dateParam) {
if (!dateParam) {
return null;
}
const date =
typeof dateParam === 'object' ? dateParam : new Date(dateParam);
const DAY_IN_MS = 86400000; // 24 * 60 * 60 * 1000
const today = new Date();
const yesterday = new Date(today - DAY_IN_MS);
const seconds = Math.round((today - date) / 1000);
const minutes = Math.round(seconds / 60);
const hour = Math.round(seconds / 3600);
const day = Math.round(seconds / 86400);
const month = Math.round(seconds / 2629800);
const year = Math.floor(seconds / 31536000);
const isToday = today.toDateString() === date.toDateString();
const isYesterday =
yesterday.toDateString() === date.toDateString();
const isThisYear = today.getFullYear() === date.getFullYear();
switch(true){
case (seconds < 5):
return 'now';
case (seconds < 60):
return `${seconds} seconds ago`;
case (seconds < 90):
return 'about a minute ago';
case (minutes < 60):
return `${minutes} minutes ago`;
case (hour === 1 && hour < 2):
return `${hour} hour ago`; // 1 hour ago
case (hour > 1 && hour <= 12):
return `${hour} hours ago`; // 2 hours ago
case (isToday):
return getFormattedDate(date, 'Today'); // Today at 10:20am
case (isYesterday):
return getFormattedDate(date, 'Yesterday'); // Yesterday at 10:20am
case(day > 1 && day <= 30):
return `${day} days ago`; // 2 days ago
case (isThisYear):
return getFormattedDate(date, false, true); // January 10th at 10:20pm
case (day > 30 && month <= 1):
return `${hour} month ago`; // 1 month ago
case (month > 1 && month <= 12):
return `${month} months ago`; // 2 months ago
case (year === 1):
return `${year} year ago`; // 1 year ago
case (year > 1):
return `${year} years ago`; // 2 years ago
default:
return getFormattedDate(date); // January 10th 2022 at 10:20pm
}
}
return timeAgo(date);
};
console.log(showTimeAgo("2022-06-20T13:42:29-05:00"));-05:00"))
其他回答
将上面的函数更改为
function timeSince(date) {
var seconds = Math.floor(((new Date().getTime()/1000) - date)),
interval = Math.floor(seconds / 31536000);
if (interval > 1) return interval + "y";
interval = Math.floor(seconds / 2592000);
if (interval > 1) return interval + "m";
interval = Math.floor(seconds / 86400);
if (interval >= 1) return interval + "d";
interval = Math.floor(seconds / 3600);
if (interval >= 1) return interval + "h";
interval = Math.floor(seconds / 60);
if (interval > 1) return interval + "m ";
return Math.floor(seconds) + "s";
}
否则它会显示“75分钟”(介于1到2小时之间)。它现在还假定输入日期是Unix时间戳。
从现在开始,Unix时间戳参数
function timeSince(ts){
now = new Date();
ts = new Date(ts*1000);
var delta = now.getTime() - ts.getTime();
delta = delta/1000; //us to s
var ps, pm, ph, pd, min, hou, sec, days;
if(delta<=59){
ps = (delta>1) ? "s": "";
return delta+" second"+ps
}
if(delta>=60 && delta<=3599){
min = Math.floor(delta/60);
sec = delta-(min*60);
pm = (min>1) ? "s": "";
ps = (sec>1) ? "s": "";
return min+" minute"+pm+" "+sec+" second"+ps;
}
if(delta>=3600 && delta<=86399){
hou = Math.floor(delta/3600);
min = Math.floor((delta-(hou*3600))/60);
ph = (hou>1) ? "s": "";
pm = (min>1) ? "s": "";
return hou+" hour"+ph+" "+min+" minute"+pm;
}
if(delta>=86400){
days = Math.floor(delta/86400);
hou = Math.floor((delta-(days*86400))/60/60);
pd = (days>1) ? "s": "";
ph = (hou>1) ? "s": "";
return days+" day"+pd+" "+hou+" hour"+ph;
}
}
回复@Stas Parshin的答案,这是最好的答案,代码更少,但它在与typescript一起使用时有bug, Intl的.format函数需要2个输入
number, Units - i.e of type 'RelativeTimeFormatUnit' so if you pass a object key typescript will through error saying unit must be of type RelativeTimeFormatUnit and not of type string, so the work-around for this is to use the type to make another list of same type and rest you can have look at code... Happy coding. console.log(timeAgo('2021-08-09T15:29:01+0000')); function timeAgo(input) { const date = (input instanceof Date) ? input : new Date(input); const formatter = new Intl.RelativeTimeFormat('en'); const ranges = { years: 3600 * 24 * 365, months: 3600 * 24 * 30, weeks: 3600 * 24 * 7, days: 3600 * 24, hours: 3600, minutes: 60, seconds: 1 }; type RelativeTimeFormatUnit = | "year" | "years" | "quarter" | "quarters" | "month" | "months" | "week" | "weeks" | "day" | "days" | "hour" | "hours" | "minute" | "minutes" | "second" | "seconds" ; const units: RelativeTimeFormatUnit[] = ["years", "months", "weeks", "days", "hours", "minutes", "seconds"]; // order matters here. const secondsElapsed = (date.getTime() - Date.now()) / 1000; for (let key in ranges) { let i = 0; if (ranges[key] < Math.abs(secondsElapsed)) { const delta = secondsElapsed / ranges[key]; return formatter.format(Math.round(delta), units[i++]); } } }
以上答案适用于旧的java脚本。但它在新的EC6 JavaScript或TypeScript上运行得不太好。下面是一个非常简短和简单的函数,用于最新的JavaScript, TypeScript, AngularJs, ReactJs和NodeJs,根据给定的日期和时间返回时间。
public timeAgo(date) {
var seconds = Math.floor((new Date().getTime() - new Date(date).getTime()) / 1000);
var interval = seconds / 31536000;
if (interval > 1) return Math.floor(interval) + " years";
interval = seconds / 2592000;
if (interval > 1) return Math.floor(interval) + " months";
interval = seconds / 86400;
if (interval > 1) return Math.floor(interval) + " days";
interval = seconds / 3600;
if (interval > 1) return Math.floor(interval) + " hours";
interval = seconds / 60;
if (interval > 1) return Math.floor(interval) + " minutes";
return Math.floor(seconds) + " seconds";
}
console.log(timeAgo('2022-08-12 20:50:20'));
// 2 hours ago, as per the given date time string.
我用js和python写了一个,在两个项目中使用,非常漂亮和简单:一个简单的库(少于2kb),用于*** time ago语句格式化日期。
简单,小巧,易于使用,并且经过良好测试。
NPM安装timeago.js 从timeago.js导入timeago;//或使用脚本标签 使用API格式。
示例:
var timeagoIns = timeago();
timeagoIns .format('2016-06-12');
你也可以实时渲染。
var timeagoIns = timeago();
timeagoIns.render(document.querySelectorAll('time'));