问题是如何将JavaScript Date格式化为一个字符串,声明时间经过,类似于您在Stack Overflow上看到的时间显示方式。
e.g.
1分钟前 1小时前 1天前 1个月前 一年前
问题是如何将JavaScript Date格式化为一个字符串,声明时间经过,类似于您在Stack Overflow上看到的时间显示方式。
e.g.
1分钟前 1小时前 1天前 1个月前 一年前
当前回答
要使用这个,只需复制所有这些代码,并将其导入到你的组件或任何地方,并将你的ISOstring()日期放在:showTimeAgo("2022-06-20T13:42:29-05:00"),你将获得每个场景的自动时间更新。
旁注:我为这个https://www.npmjs.com/package/showtimeago做了一个npm包
export const showTimeAgo = () => {
const MONTH_NAMES = [
'January',
'February',
'March',
'April',
'May',
'June',
'July',
'August',
'September',
'October',
'November',
'December',
];
function getOrdinalNum() {
return (
n +
(n > 0
? ['th', 'st', 'nd', 'rd'][
(n > 3 && n < 21) || n % 10 > 3 ? 0 : n % 10
]
: '')
);
}
function getFormattedDate(
date,
preformattedDate = false,
hideYear = false
) {
const day = date.getDate();
const month = MONTH_NAMES[date.getMonth()];
const year = date.getFullYear();
let hours = date.getHours();
let minutes = date.getMinutes();
let ampm = hours >= 12 ? 'pm' : 'am';
switch(true){
case (hours > 12):
hours = hours - 12;
break;
case (hours === 0):
hours = 12;
break;
case(minutes < 10):
minutes = `0${minutes}`;
break;
case(preformattedDate):
// Today at 10:20am
// Yesterday at 10:20am
return `${preformattedDate} at ${hours}:${minutes} ${ampm}`;
case(hideYear):
// January 10th at 10:20pm
return `${month} ${getOrdinalNum(
day
)}, at ${hours}:${minutes} ${ampm}`;
default:
// January 10th 2022 at 10:20pm
return `${month} ${getOrdinalNum(
day
)}, ${year} at ${hours}:${minutes} ${ampm}`;
}
}
// --- Main function
function timeAgo(dateParam) {
if (!dateParam) {
return null;
}
const date =
typeof dateParam === 'object' ? dateParam : new Date(dateParam);
const DAY_IN_MS = 86400000; // 24 * 60 * 60 * 1000
const today = new Date();
const yesterday = new Date(today - DAY_IN_MS);
const seconds = Math.round((today - date) / 1000);
const minutes = Math.round(seconds / 60);
const hour = Math.round(seconds / 3600);
const day = Math.round(seconds / 86400);
const month = Math.round(seconds / 2629800);
const year = Math.floor(seconds / 31536000);
const isToday = today.toDateString() === date.toDateString();
const isYesterday =
yesterday.toDateString() === date.toDateString();
const isThisYear = today.getFullYear() === date.getFullYear();
switch(true){
case (seconds < 5):
return 'now';
case (seconds < 60):
return `${seconds} seconds ago`;
case (seconds < 90):
return 'about a minute ago';
case (minutes < 60):
return `${minutes} minutes ago`;
case (hour === 1 && hour < 2):
return `${hour} hour ago`; // 1 hour ago
case (hour > 1 && hour <= 12):
return `${hour} hours ago`; // 2 hours ago
case (isToday):
return getFormattedDate(date, 'Today'); // Today at 10:20am
case (isYesterday):
return getFormattedDate(date, 'Yesterday'); // Yesterday at 10:20am
case(day > 1 && day <= 30):
return `${day} days ago`; // 2 days ago
case (isThisYear):
return getFormattedDate(date, false, true); // January 10th at 10:20pm
case (day > 30 && month <= 1):
return `${hour} month ago`; // 1 month ago
case (month > 1 && month <= 12):
return `${month} months ago`; // 2 months ago
case (year === 1):
return `${year} year ago`; // 1 year ago
case (year > 1):
return `${year} years ago`; // 2 years ago
default:
return getFormattedDate(date); // January 10th 2022 at 10:20pm
}
}
return timeAgo(date);
};
console.log(showTimeAgo("2022-06-20T13:42:29-05:00"));-05:00"))
其他回答
以上答案适用于旧的java脚本。但它在新的EC6 JavaScript或TypeScript上运行得不太好。下面是一个非常简短和简单的函数,用于最新的JavaScript, TypeScript, AngularJs, ReactJs和NodeJs,根据给定的日期和时间返回时间。
public timeAgo(date) {
var seconds = Math.floor((new Date().getTime() - new Date(date).getTime()) / 1000);
var interval = seconds / 31536000;
if (interval > 1) return Math.floor(interval) + " years";
interval = seconds / 2592000;
if (interval > 1) return Math.floor(interval) + " months";
interval = seconds / 86400;
if (interval > 1) return Math.floor(interval) + " days";
interval = seconds / 3600;
if (interval > 1) return Math.floor(interval) + " hours";
interval = seconds / 60;
if (interval > 1) return Math.floor(interval) + " minutes";
return Math.floor(seconds) + " seconds";
}
console.log(timeAgo('2022-08-12 20:50:20'));
// 2 hours ago, as per the given date time string.
从现在开始,Unix时间戳参数
function timeSince(ts){
now = new Date();
ts = new Date(ts*1000);
var delta = now.getTime() - ts.getTime();
delta = delta/1000; //us to s
var ps, pm, ph, pd, min, hou, sec, days;
if(delta<=59){
ps = (delta>1) ? "s": "";
return delta+" second"+ps
}
if(delta>=60 && delta<=3599){
min = Math.floor(delta/60);
sec = delta-(min*60);
pm = (min>1) ? "s": "";
ps = (sec>1) ? "s": "";
return min+" minute"+pm+" "+sec+" second"+ps;
}
if(delta>=3600 && delta<=86399){
hou = Math.floor(delta/3600);
min = Math.floor((delta-(hou*3600))/60);
ph = (hou>1) ? "s": "";
pm = (min>1) ? "s": "";
return hou+" hour"+ph+" "+min+" minute"+pm;
}
if(delta>=86400){
days = Math.floor(delta/86400);
hou = Math.floor((delta-(days*86400))/60/60);
pd = (days>1) ? "s": "";
ph = (hou>1) ? "s": "";
return days+" day"+pd+" "+hou+" hour"+ph;
}
}
我一直在寻找这个问题的答案,并且几乎实现了其中一个解决方案,但一位同事提醒我检查react-intl库,因为我们已经在使用它了。
所以在解决方案中…在使用react-intl库的情况下,它们有一个<FormattedRelative>组件。
https://github.com/yahoo/react-intl/wiki/Components#formattedrelative
这是我的版本,它既适用于过去的日期,也适用于未来的日期。 它使用Intl。RelativeTimeFormat提供本地化字符串,而不是硬编码字符串。 您可以将日期作为时间戳、日期对象或可解析的日期字符串传递。
/** * Human readable elapsed or remaining time (example: 3 minutes ago) * @param {Date|Number|String} date A Date object, timestamp or string parsable with Date.parse() * @param {Date|Number|String} [nowDate] A Date object, timestamp or string parsable with Date.parse() * @param {Intl.RelativeTimeFormat} [trf] A Intl formater * @return {string} Human readable elapsed or remaining time * @author github.com/victornpb * @see https://stackoverflow.com/a/67338038/938822 */ function fromNow(date, nowDate = Date.now(), rft = new Intl.RelativeTimeFormat(undefined, { numeric: "auto" })) { const SECOND = 1000; const MINUTE = 60 * SECOND; const HOUR = 60 * MINUTE; const DAY = 24 * HOUR; const WEEK = 7 * DAY; const MONTH = 30 * DAY; const YEAR = 365 * DAY; const intervals = [ { ge: YEAR, divisor: YEAR, unit: 'year' }, { ge: MONTH, divisor: MONTH, unit: 'month' }, { ge: WEEK, divisor: WEEK, unit: 'week' }, { ge: DAY, divisor: DAY, unit: 'day' }, { ge: HOUR, divisor: HOUR, unit: 'hour' }, { ge: MINUTE, divisor: MINUTE, unit: 'minute' }, { ge: 30 * SECOND, divisor: SECOND, unit: 'seconds' }, { ge: 0, divisor: 1, text: 'just now' }, ]; const now = typeof nowDate === 'object' ? nowDate.getTime() : new Date(nowDate).getTime(); const diff = now - (typeof date === 'object' ? date : new Date(date)).getTime(); const diffAbs = Math.abs(diff); for (const interval of intervals) { if (diffAbs >= interval.ge) { const x = Math.round(Math.abs(diff) / interval.divisor); const isFuture = diff < 0; return interval.unit ? rft.format(isFuture ? x : -x, interval.unit) : interval.text; } } }
// examples
fromNow('2020-01-01') // 9 months ago
fromNow(161651684156) // 4 days ago
fromNow(new Date()-1) // just now
fromNow(30000 + Date.now()) // in 30 seconds
fromNow(Date.now() + (1000*60*60*24)) // in 1 day
fromNow(new Date('2029-12-01Z00:00:00.000')) // in 9 years
不使用Intl的替代方法。RelativeTimeFormat
/** * Human readable elapsed or remaining time (example: 3 minutes ago) * @param {Date|Number|String} date A Date object, timestamp or string parsable with Date.parse() * @return {string} Human readable elapsed or remaining time * @author github.com/victornpb * @see https://stackoverflow.com/a/67338038/938822 */ function fromNow(date) { const SECOND = 1000; const MINUTE = 60 * SECOND; const HOUR = 60 * MINUTE; const DAY = 24 * HOUR; const WEEK = 7 * DAY; const MONTH = 30 * DAY; const YEAR = 365 * DAY; const units = [ { max: 30 * SECOND, divisor: 1, past1: 'just now', pastN: 'just now', future1: 'just now', futureN: 'just now' }, { max: MINUTE, divisor: SECOND, past1: 'a second ago', pastN: '# seconds ago', future1: 'in a second', futureN: 'in # seconds' }, { max: HOUR, divisor: MINUTE, past1: 'a minute ago', pastN: '# minutes ago', future1: 'in a minute', futureN: 'in # minutes' }, { max: DAY, divisor: HOUR, past1: 'an hour ago', pastN: '# hours ago', future1: 'in an hour', futureN: 'in # hours' }, { max: WEEK, divisor: DAY, past1: 'yesterday', pastN: '# days ago', future1: 'tomorrow', futureN: 'in # days' }, { max: 4 * WEEK, divisor: WEEK, past1: 'last week', pastN: '# weeks ago', future1: 'in a week', futureN: 'in # weeks' }, { max: YEAR, divisor: MONTH, past1: 'last month', pastN: '# months ago', future1: 'in a month', futureN: 'in # months' }, { max: 100 * YEAR, divisor: YEAR, past1: 'last year', pastN: '# years ago', future1: 'in a year', futureN: 'in # years' }, { max: 1000 * YEAR, divisor: 100 * YEAR, past1: 'last century', pastN: '# centuries ago', future1: 'in a century', futureN: 'in # centuries' }, { max: Infinity, divisor: 1000 * YEAR, past1: 'last millennium', pastN: '# millennia ago', future1: 'in a millennium', futureN: 'in # millennia' }, ]; const diff = Date.now() - (typeof date === 'object' ? date : new Date(date)).getTime(); const diffAbs = Math.abs(diff); for (const unit of units) { if (diffAbs < unit.max) { const isFuture = diff < 0; const x = Math.round(Math.abs(diff) / unit.divisor); if (x <= 1) return isFuture ? unit.future1 : unit.past1; return (isFuture ? unit.futureN : unit.pastN).replace('#', x); } } };
这是一个简化版的@sky-sanders的回答。
function timeSince(date) {
var seconds = Math.floor((new Date() - date) / 1000);
var divisors = [31536000, 2592000, 86400, 3600, 60, 1]
var description = ["years", "months", "days", "hours", "minutes", "seconds"]
var result = [];
var interval = seconds;
for (i = 0; i < divisors.length; i++) {
interval = Math.floor(seconds / divisors[i])
if (interval > 1) {
result.push(interval + " " + description[i])
}
seconds -= interval * divisors[i]
}
return result.join(" ")
}