问题是如何将JavaScript Date格式化为一个字符串,声明时间经过,类似于您在Stack Overflow上看到的时间显示方式。
e.g.
1分钟前 1小时前 1天前 1个月前 一年前
问题是如何将JavaScript Date格式化为一个字符串,声明时间经过,类似于您在Stack Overflow上看到的时间显示方式。
e.g.
1分钟前 1小时前 1天前 1个月前 一年前
当前回答
这是我的版本,它既适用于过去的日期,也适用于未来的日期。 它使用Intl。RelativeTimeFormat提供本地化字符串,而不是硬编码字符串。 您可以将日期作为时间戳、日期对象或可解析的日期字符串传递。
/** * Human readable elapsed or remaining time (example: 3 minutes ago) * @param {Date|Number|String} date A Date object, timestamp or string parsable with Date.parse() * @param {Date|Number|String} [nowDate] A Date object, timestamp or string parsable with Date.parse() * @param {Intl.RelativeTimeFormat} [trf] A Intl formater * @return {string} Human readable elapsed or remaining time * @author github.com/victornpb * @see https://stackoverflow.com/a/67338038/938822 */ function fromNow(date, nowDate = Date.now(), rft = new Intl.RelativeTimeFormat(undefined, { numeric: "auto" })) { const SECOND = 1000; const MINUTE = 60 * SECOND; const HOUR = 60 * MINUTE; const DAY = 24 * HOUR; const WEEK = 7 * DAY; const MONTH = 30 * DAY; const YEAR = 365 * DAY; const intervals = [ { ge: YEAR, divisor: YEAR, unit: 'year' }, { ge: MONTH, divisor: MONTH, unit: 'month' }, { ge: WEEK, divisor: WEEK, unit: 'week' }, { ge: DAY, divisor: DAY, unit: 'day' }, { ge: HOUR, divisor: HOUR, unit: 'hour' }, { ge: MINUTE, divisor: MINUTE, unit: 'minute' }, { ge: 30 * SECOND, divisor: SECOND, unit: 'seconds' }, { ge: 0, divisor: 1, text: 'just now' }, ]; const now = typeof nowDate === 'object' ? nowDate.getTime() : new Date(nowDate).getTime(); const diff = now - (typeof date === 'object' ? date : new Date(date)).getTime(); const diffAbs = Math.abs(diff); for (const interval of intervals) { if (diffAbs >= interval.ge) { const x = Math.round(Math.abs(diff) / interval.divisor); const isFuture = diff < 0; return interval.unit ? rft.format(isFuture ? x : -x, interval.unit) : interval.text; } } }
// examples
fromNow('2020-01-01') // 9 months ago
fromNow(161651684156) // 4 days ago
fromNow(new Date()-1) // just now
fromNow(30000 + Date.now()) // in 30 seconds
fromNow(Date.now() + (1000*60*60*24)) // in 1 day
fromNow(new Date('2029-12-01Z00:00:00.000')) // in 9 years
不使用Intl的替代方法。RelativeTimeFormat
/** * Human readable elapsed or remaining time (example: 3 minutes ago) * @param {Date|Number|String} date A Date object, timestamp or string parsable with Date.parse() * @return {string} Human readable elapsed or remaining time * @author github.com/victornpb * @see https://stackoverflow.com/a/67338038/938822 */ function fromNow(date) { const SECOND = 1000; const MINUTE = 60 * SECOND; const HOUR = 60 * MINUTE; const DAY = 24 * HOUR; const WEEK = 7 * DAY; const MONTH = 30 * DAY; const YEAR = 365 * DAY; const units = [ { max: 30 * SECOND, divisor: 1, past1: 'just now', pastN: 'just now', future1: 'just now', futureN: 'just now' }, { max: MINUTE, divisor: SECOND, past1: 'a second ago', pastN: '# seconds ago', future1: 'in a second', futureN: 'in # seconds' }, { max: HOUR, divisor: MINUTE, past1: 'a minute ago', pastN: '# minutes ago', future1: 'in a minute', futureN: 'in # minutes' }, { max: DAY, divisor: HOUR, past1: 'an hour ago', pastN: '# hours ago', future1: 'in an hour', futureN: 'in # hours' }, { max: WEEK, divisor: DAY, past1: 'yesterday', pastN: '# days ago', future1: 'tomorrow', futureN: 'in # days' }, { max: 4 * WEEK, divisor: WEEK, past1: 'last week', pastN: '# weeks ago', future1: 'in a week', futureN: 'in # weeks' }, { max: YEAR, divisor: MONTH, past1: 'last month', pastN: '# months ago', future1: 'in a month', futureN: 'in # months' }, { max: 100 * YEAR, divisor: YEAR, past1: 'last year', pastN: '# years ago', future1: 'in a year', futureN: 'in # years' }, { max: 1000 * YEAR, divisor: 100 * YEAR, past1: 'last century', pastN: '# centuries ago', future1: 'in a century', futureN: 'in # centuries' }, { max: Infinity, divisor: 1000 * YEAR, past1: 'last millennium', pastN: '# millennia ago', future1: 'in a millennium', futureN: 'in # millennia' }, ]; const diff = Date.now() - (typeof date === 'object' ? date : new Date(date)).getTime(); const diffAbs = Math.abs(diff); for (const unit of units) { if (diffAbs < unit.max) { const isFuture = diff < 0; const x = Math.round(Math.abs(diff) / unit.divisor); if (x <= 1) return isFuture ? unit.future1 : unit.past1; return (isFuture ? unit.futureN : unit.pastN).replace('#', x); } } };
其他回答
这应该正确地处理任何有效的时间戳,包括Date.now()、单数单位和未来日期。我漏掉了月份,但是这些月份应该很容易加进去。我尽量保持它的可读性。
function getTimeInterval(date) { let seconds = Math.floor((Date.now() - date) / 1000); let unit = "second"; let direction = "ago"; if (seconds < 0) { seconds = -seconds; direction = "from now"; } let value = seconds; if (seconds >= 31536000) { value = Math.floor(seconds / 31536000); unit = "year"; } else if (seconds >= 86400) { value = Math.floor(seconds / 86400); unit = "day"; } else if (seconds >= 3600) { value = Math.floor(seconds / 3600); unit = "hour"; } else if (seconds >= 60) { value = Math.floor(seconds / 60); unit = "minute"; } if (value != 1) unit = unit + "s"; return value + " " + unit + " " + direction; } console.log(getTimeInterval(Date.now())); // 0 seconds ago console.log(getTimeInterval(Date.now() + 1000)); // 1 second from now console.log(getTimeInterval(Date.now() - 1000)); // 1 second ago console.log(getTimeInterval(Date.now() + 60000)); // 1 minute from now console.log(getTimeInterval(Date.now() - 120000)); // 2 minutes ago console.log(getTimeInterval(Date.now() + 120000)); // 2 minutes from now console.log(getTimeInterval(Date.now() + 3600000)); // 1 hour from now console.log(getTimeInterval(Date.now() + 360000000000)); // 11 years from now console.log(getTimeInterval(0)); // 49 years ago
Lokely使用的一个简短版本:
const intervals = [
{ label: 'year', seconds: 31536000 },
{ label: 'month', seconds: 2592000 },
{ label: 'day', seconds: 86400 },
{ label: 'hour', seconds: 3600 },
{ label: 'minute', seconds: 60 },
{ label: 'second', seconds: 1 }
];
function timeSince(date) {
const seconds = Math.floor((Date.now() - date.getTime()) / 1000);
const interval = intervals.find(i => i.seconds < seconds);
const count = Math.floor(seconds / interval.seconds);
return `${count} ${interval.label}${count !== 1 ? 's' : ''} ago`;
}
I achieve this by following method
timeAgo = (date) => {
var ms = (new Date()).getTime() - date.getTime();
var seconds = Math.floor(ms / 1000);
var minutes = Math.floor(seconds / 60);
var hours = Math.floor(minutes / 60);
var days = Math.floor(hours / 24);
var months = Math.floor(days / 30);
var years = Math.floor(months / 12);
if (ms === 0) {
return 'Just now';
} if (seconds < 60) {
return seconds + ' seconds Ago';
} if (minutes < 60) {
return minutes + ' minutes Ago';
} if (hours < 24) {
return hours + ' hours Ago';
} if (days < 30) {
return days + ' days Ago';
} if (months < 12) {
return months + ' months Ago';
} else {
return years + ' years Ago';
}
}
console.log(timeAgo(new Date()));
console.log(timeAgo(new Date('Jun 27 2020 10:12:19')));
console.log(timeAgo(new Date('Jun 27 2020 00:12:19')));
console.log(timeAgo(new Date('May 28 2020 13:12:19')));
console.log(timeAgo(new Date('May 28 2017 13:12:19')));
function mdiv(dividend, divisor) {
return [ Math.floor(dividend/divisor), dividend % divisor ];
}
// pass in milliseconds, gained by Date1.getTime() - Date2.getTime()
// if max_units is two, the result will be, for example
// 2years 12months ago, or 2hours 38minutes ago
// return formated period
function readable_period(ms, max_units=2){
let [yy, yr] = mdiv(ms, 3.154e10);
let [mm, mr] = mdiv(yr, 2.628e9);
let [dd, dr] = mdiv(mr, 8.64e7);
let [hh, hr] = mdiv(dr, 3.6e6);
let [tt, ss] = mdiv(hr, 6e4);
var ymdht = ['year', 'month', 'day', 'hour', 'minute'];
let res = [];
[yy, mm, dd, hh, tt].forEach((tis, ii)=>{
if(res.length === max_units){return};
if(tis !== 0){
res.push(tis === 1 ? `${tis}${ymdht[ii]}` : `${tis}${ymdht[ii]}s`);
}
});
return res.length === 0 ? '' : res.join(' ') + ' ago';
}
这是一个简化版的@sky-sanders的回答。
function timeSince(date) {
var seconds = Math.floor((new Date() - date) / 1000);
var divisors = [31536000, 2592000, 86400, 3600, 60, 1]
var description = ["years", "months", "days", "hours", "minutes", "seconds"]
var result = [];
var interval = seconds;
for (i = 0; i < divisors.length; i++) {
interval = Math.floor(seconds / divisors[i])
if (interval > 1) {
result.push(interval + " " + description[i])
}
seconds -= interval * divisors[i]
}
return result.join(" ")
}